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Chapter 33: Q10P (page 1001)

A plane electromagnetic wave has a maximum electric field magnitude of $3.20 脳 10^{- 4} V/m$ . Find the magnetic field amplitude.

Short Answer

Expert verified

The magnetic field amplitude is $1.067 脳 10^{- 12} T$ .

Step by step solution

01

Listing the given quantities

Maximum electric field magnitude $E_{m} = 3.20 脳 10^{- 4} V/m$ .

02

Understanding the concepts of magnetic field

The electric $E_{m}$ and magnetic fields $B_{m}$ are related to the wave speed c as,

$c = \frac{E_{m}}{B_{m}}$

03

Calculations of the magnetic field amplitude

The electric and the magnetic field are related as,

$c = \frac{E_{m}}{B_{m}}$

Where c is the wave speed $c = 3.0 脳 10^{8} m/s$ .

Rearranging the above expression as,

$B_{m} = \frac{E_{m}}{c}$

Substitute the values in the above expression, and we get,

$\begin{array}{rcl} B_{m} & = & \frac{3.20 脳 10^{- 4} V/m}{3.0 脳 10^{8} m/s} \\ = & 1.067 脳 10^{- 12} T \end{array}$

Thus, the magnetic field amplitude is $1.067 脳 10^{- 12} T$ .

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Most popular questions from this chapter

A thin, totally absorbing sheet of mass m, face area A, and specificheat $c_{s}$ isfully illuminated by a perpendicular beam of a plane electromagnetic wave. The magnitude of the maximum electric field of the wave is $E_{m}$ .What is the rate $\frac{d T}{d t}$ at which the sheet鈥檚 temperature increases due to the absorption of the wave?

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Light in a vacuum is incident on the surface of a glass slab. In the vacuum, the beam makes an angle of $32.0掳$ with the normal to the surface, while in the glass it makes an angle of $21.0掳$ with the normal. What is the index of refraction of the glass?

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