Q68P Here are the charges and coordin... [FREE SOLUTION]

Chapter 24: Q68P (page 715)

Here are the charges and coordinates of two charged particles located in an xyplane: $q_{2}^{'} = - 3.0 脳 10^{- 6} C$ , $x = + 3.50 cm$ , $y = + 0.500 cm$ androle="math" localid="1662728679285" $q_{2}^{} = - 4.0 脳 10^{- 6} C$ , $x = - 2.00 cm$ , $y = + 1.50 cm$ . How much work must be done to locate these charges at their given positions, starting from infinite separation?

Short Answer

Expert verified

The work done is $W = 鈭� 1.39 鈥塉$

Step by step solution

Given

After reading the question, For the first charge $q_{1}^{} = + 3.0 脳 10^{鈭� 6} 鈥塁$ at $p (3.5, 0.5) 鈥塩尘$ for the second charge $^{'} q_{2}^{'} = 鈭� 4.0 脳 10^{鈭� 6} C$ at $q (鈭� 2, 1.5) 鈥塩尘$
From the figure:

Determine the concept

Work done is given by s follows:

$W = \frac{1}{4 {蟺蔚}_{o}} 鈰� \frac{q_{1} q_{2}}{d}$

Calculate how much work must be done to locate these charges at their given positions

The separation between p and q,

$d = \sqrt{{(3.5 + 2)}^{2} + {(0.5 鈭� 1.5)}^{2}}$

$d = 5.59 鈥塩尘$

$d = 0.0559 鈥尘$

The net work done:

$W = \frac{1}{4 {蟺蔚}_{o}} 鈰� \frac{q_{1} q_{2}}{d}$

Substitute the values and solve as:

$鈬� W = 9.0 脳 10^{9} 脳 \frac{(3.0 脳 10^{鈭� 6}) (鈭� 4 脳 10^{鈭� 6})}{(0.0559)}$

$鈬� W = 鈭� 1.39 鈥塉$

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Short Answer

Step by step solution

Given

Determine the concept

Calculate how much work must be done to locate these charges at their given positions

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