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A diffraction grating 1.00 cm wide has 10 000 parallel slits. Monochromatic light that is incident normally is diffracted through 30° in the first order. What is the wavelength of the light?

Short Answer

Expert verified

The wavelength of light is 500 nm.

Step by step solution

01

Identification of given data

The given data can be listed below,

  • The width of the diffraction grating is,D=1.00cm
  • The number of slits used in grating are,N=10000
  • The angle of diffraction is,θ=30°
02

Concept/Significance of wavelength

The separation between two successive wave crests or troughs is known as a wavelength. It is determined by measuring the wave's direction.

03

Determination of the wavelength of the light

The separation of slits is given by,

d=DN

Here,D is the width grating and N is the number of slits.

According to brag’s law, the wavelength of the light is given by,

dsinθ=mλλ=DsinθNm

Substitute all the values in the above,

λ=1.0×107nmsin30°1×10000=500nm

Thus, the wavelength of light is 500 nm.

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Most popular questions from this chapter

Floaters. The floaters you see when viewing a bright, featureless background are diffraction patterns of defects in the vitreous humor that fills most of your eye. Sighting through a pinhole sharpens the diffraction pattern. If you also view a small circular dot, you can approximate the defect’s size. Assume that the defect diffracts light as a circular aperture does. Adjust the dot’s distance L from your eye (or eye lens) until the dot and the circle of the first minimum in the diffraction pattern appear to have the same size in your view. That is, until they have the same diameter D'on the retina at distance L'=2cmfrom the front of the eye, as suggested in Fig. 36-42a, where the angles on the two sides of the eye lens are equal. Assume that the wavelength of visible light is λ=550nm. If the dot has diameter D=2.0mmand is distance L=45.0cmfrom the eye and the defect is x=6.0mm in front of the retina (Fig. 36-42b), what is the diameter of the defect?


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