/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7P Light of wavelength 633 nm is ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Light of wavelength 633nmis incident on a narrow slit. The angle between the first diffraction minimum on one side of the central maximum and the first minimum on the other side is 1.20°. What is the width of the slit?

Short Answer

Expert verified

The width of slit is 3.023×10-5m.

Step by step solution

01

Identification of given data

The wavelength of the light is λ=633nm.

The angle of diffraction between central minima and second order minima is θ=1.20°.

The order of first minima is m=1.

02

Concept used

The diffraction is the phenomenon in which the light bends on the edges of the slit and pattern of light is formed on a screen.

03

Determination of width of slit

The width of slit is given as:

mλ=dsinθ

Substitute all the values in equation.

1633nm10-9m1nm=dsin0.429°d=3.023×10-5m

Therefore, the width of slit is 3.023×10-5m.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The pupil of a person’s eye has a diameter of 5.00 mm. According to Rayleigh’s criterion, what distance apart must two small objects be if their images are just barely resolved when they are 250 mm from the eye? Assume they are illuminated with light of wavelength 500 nm

Monochromatic light (wavelength=450nm) is incident perpendicularly on a single slit (width=0.4mm). A screen is placed parallel to the slit plane, and on it the distance between the two minima on either side of the central maximum is 1.8mm.

(a) What is the distance from the slit to the screen? (Hint:The angle to either minimum is small enough thatsinθ≈tanθ.)

(b) What is the distance on the screen between the first minimum and the third minimum on the same side of the central maximum?

Light of wavelength 440 nm passes through a double slit, yielding a diffraction pattern whose graph of intensity I versus angular position is shown in Fig. 36-44. Calculate (a) the slit width and (b) the slit separation. (c) Verify the displayed intensities of the m=1and m=2 interference fringes.

An x-ray beam of wavelength A undergoes first-order reflection (Bragg law diffraction) from a crystal when its angle of incidence to a crystal face is , and an x-ray beam of wavelength undergoes third-order reflection when its angle of incidence to that face is . Assuming that the two beams reflect from the same family of reflecting planes, find (a) the interplanar spacing and (b) the wavelength A.

A plane wave of wavelength is incident on a slit with a width of 590nm. A thin converging lens of focal length +70cm is placed between the slit and a viewing screen and focuses the light on the screen. (a) How far is the screen from the lens? (b) What is the distance on the screen from the center of the diffraction pattern to the first minimum?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.