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Chapter 36: Q11P (page 1109)

A 0.10mmwide slit is illuminated by light of wavelength 589nm. Consider a point P on a viewing screen on which the diffraction pattern of the slit is viewed; the point is at 30掳from the central axis of the slit. What is the phase difference between the Huygens wavelets arriving at point P from the top and midpoint of the slit? (Hint: See Eq. 36-4.)

Short Answer

Expert verified

The path difference of diffraction is 85蟺rad.

Step by step solution

01

Identification of given data

The wavelength of the light is 位=589nm.

The angle of diffraction minima from center of slit is 胃=30掳.

The width of slit is d=0.10mm.

02

Concept used

The angle of the diffraction is defined as the angle of central axis from the diffraction minima of different orders.

03

Determination of path difference

The path difference of diffraction is given as:

螖x=d2sin胃

Substitute all the values in equation.

螖x=0.10mm2sin30掳螖x=0.025mm

04

Determination of phase difference

The path difference of diffraction is given as:

螖蠒=2蟺位螖x

Substitute all the values in equation.

螖蠒=2蟺589nm10-9m1nm0.025mm10-3m1mm螖蠒=85蟺rad

Therefore, the path difference of diffraction is 85蟺rad.

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Most popular questions from this chapter

In a certain two-slit interference pattern, 10 bright fringes lie within the second side peak of the diffraction envelope and diffraction minima coincide with two-slit interference maxima. What is the ratio of the slit separation to the slit width?

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