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Chapter 36: Q10P (page 1109)

Manufacturers of wire (and other objects of small dimension) sometimes use a laser to continually monitor the thickness of the product. The wire intercepts the laser beam, producing a diffraction pattern like that of a single slit of the same width as the wire diameter (Fig.36-37). Suppose a helium 鈥� neon laser, of wavelength 632.8nm, illuminates a wire, and the diffraction pattern appears on a screen at distance L=2.60m. If the desired wire diameter is 1.37mm, what is the observed distance between the two tenth-order minima (one on each side of the central maximum)?

Short Answer

Expert verified

The distance between two tenth order diffraction minima on both side is 24mm.

Step by step solution

01

Identification of given data

The wavelength of the laser is 位=632.8nm

The distance of screen from laser is L=2.60m.

The diameter of wire is d=1.37mm.

The order of tenth minima is m=10.

02

Concept used

The distance between two successive diffraction minima is called the fringe width. It varies with the wavelength, slit width and distance of screen from slit.

03

Determination of distance between two observed tenth diffraction minima on both side

The distance between two tenth order diffraction minima on both side is given as:

w=2m位Ld

Substitute all the values in equation.

w=210632.8nm10-9m1nm2.60m1.37mm10-3m1mm=24脳10-3m=24脳10-3m1mm10-3m=24mm

Therefore, the distance between two tenth order diffraction minima on both side is 24mm.

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Most popular questions from this chapter

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