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An electron is in a vacuum near Earth’s surface and located aty=0on a vertical yaxis. At what value of yshould a second electronbe placed such that its electrostatic force on the first electron balancesthe gravitational force on the first electron?

Short Answer

Expert verified

y=−5.1m

Step by step solution

01

Given

Electron is in a vacuum near Earth’s surface and located at y = 0

02

Understanding the concept

Use Coulomb’s law to solve the problem.

03

Calculate the value of y

with,F=meg

y2=ke2meg=(9.00×109Nm2/C2)(1.60×10−19C)2(9.11×10−31kg)(9.8m/s2)

Which leads toy=±5.1m . We choose y=−5.1msince the second electron must be below the first one, so that the repulsive force (acting on the first) is in the direction opposite to the pull of Earth’s gravity.

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