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Chapter 21: Q66P (page 629)

An electron is in a vacuum near Earth鈥檚 surface and located aty=0on a vertical yaxis. At what value of yshould a second electronbe placed such that its electrostatic force on the first electron balancesthe gravitational force on the first electron?

Short Answer

Expert verified

y=鈭�5.1m

Step by step solution

01

Given

Electron is in a vacuum near Earth鈥檚 surface and located at y = 0

02

Understanding the concept

Use Coulomb鈥檚 law to solve the problem.

03

Calculate the value of y

with,F=meg

y2=ke2meg=(9.00脳109Nm2/C2)(1.60脳10鈭�19C)2(9.11脳10鈭�31kg)(9.8m/s2)

Which leads toy=卤5.1m . We choose y=鈭�5.1msince the second electron must be below the first one, so that the repulsive force (acting on the first) is in the direction opposite to the pull of Earth鈥檚 gravity.

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Most popular questions from this chapter

A neutron consists of one 鈥渦p鈥� quark of charge +2e/3and two 鈥渄own鈥� quarks each having charge鈭�e/3. If we assume that the down quarks are2.6脳10鈭�15mapart inside the neutron, what is the magnitude of the electrostatic force between them?

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