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Chapter 27: Q28P (page 796)

Question: The ideal battery in Figure (a) has emf 蔚=6.0V. Plot 1 in Figure (b) gives the electric potential difference v that can appear across resistor 1 of the circuit versus the current i in that resistor. The scale of the v axis is set byVs=18.0V , and the scale of the i axis is set byis=3.00mA . Plots 2 and 3 are similar plots for resistors 2 and 3, respectively. What is the current in resistor 2 in

the circuit of Fig. 27-39a?

Short Answer

Expert verified

Answer:

The current through the resistor R2 is 0.82mA.

Step by step solution

01

Given data:

Thevoltage,蔚=6.0VThevoltage,Vs=18.0VThecurrent,Is=3.00mA

02

Understanding the concept:

Use Kirchhoff鈥檚 voltage law. In Kirchhoff鈥檚 voltage law addition of the voltage in the loop is zero. Also, you can find the individual resistance values from the slope of the graphs given.

Formula:

V=IR

The voltage is define by using following formula.

The equivalent resistor of the parallel resistance is define by,

R12=R1R2R1+R2

03

Calculate the equivalent resistance:

Here, the slope of the voltage vs the current graph is the resistance so,

The resistors are,

R1=6000惟,R2=4000惟andR3=2000惟.

Here, R1 and R2 are in parallel. So, the equivalent of these two R12 is as follow

R12=R1R2R1+R2=4000惟脳6000惟4000+6000惟=2400惟

Now, R12 and R3 are in series. So, the equivalent is R

R=R12+R3=2000+2400惟=4400惟

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Most popular questions from this chapter

When resistors 1 and 2 are connected in series, the equivalent resistance is 16.0 鈩�. When they are connected in parallel, the equivalent resistance is 3.0 鈩�. What are the smaller resistance and the larger resistance of these two resistors?

In Fig. 27-62, a voltmeter of resistance RV=300惟and an ammeter of resistance RA=3.00惟are being used to measure a resistance Rin a circuit that also contains a resistance R0=100惟and an ideal battery of emf role="math" localid="1664352839658" 蔚=12.0V. Resistance Ris given byR=V/i , where V is the voltmeter reading and is the current in resistance R. However, the ammeter reading is inot but rather i', which is iplus the current through the voltmeter. Thus, the ratio of the two meter readings is notR but only an apparent resistanceR'=V/i' . IfR=85.0惟 , what are (a) the ammeter reading, (b) the voltmeter reading, and (c) R'? (d) IfRV is increased, does the difference between R'and Rincrease, decrease, or remain the same?

A copper wire of radius a=0.250mmhas an aluminium jacket of outer radiusb=0.380mm. There is a currenti=2.00Ain the composite wire. Using Table 26-1, calculate the current in (a) the copper and (b) the aluminium. (c) If a potential differenceV=12.0Vbetween the ends maintains the current, what is the length of the composite wire?

A total resistance of 3.00 鈩� is to be produced by connecting an unknown resistance to a 12.0 鈩� resistance.

  1. What must be the value of the unknown resistance, and
  2. (b) Should it be connected in series or in parallel?

A1.0渭贵capacitor with an initial stored energy of0.50Jis discharged through a1.0惭惟resistor. (a) What is the initial charge on the capacitor? (b) What is the current through the resistor when the discharge starts? Find an expression that gives, as a function of timet, (c) the potential differenceVcacross the capacitor, (d) the potential differenceVRacross the resistor, and (e) the rate at which thermal energy is produced in the resistor.
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