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Chapter 27: Q28P (page 796)

Question: The ideal battery in Figure (a) has emf 蔚=6.0V. Plot 1 in Figure (b) gives the electric potential difference v that can appear across resistor 1 of the circuit versus the current i in that resistor. The scale of the v axis is set byVs=18.0V , and the scale of the i axis is set byis=3.00mA . Plots 2 and 3 are similar plots for resistors 2 and 3, respectively. What is the current in resistor 2 in

the circuit of Fig. 27-39a?

Short Answer

Expert verified

Answer:

The current through the resistor R2 is 0.82mA.

Step by step solution

01

Given data:

Thevoltage,蔚=6.0VThevoltage,Vs=18.0VThecurrent,Is=3.00mA

02

Understanding the concept:

Use Kirchhoff鈥檚 voltage law. In Kirchhoff鈥檚 voltage law addition of the voltage in the loop is zero. Also, you can find the individual resistance values from the slope of the graphs given.

Formula:

V=IR

The voltage is define by using following formula.

The equivalent resistor of the parallel resistance is define by,

R12=R1R2R1+R2

03

Calculate the equivalent resistance:

Here, the slope of the voltage vs the current graph is the resistance so,

The resistors are,

R1=6000惟,R2=4000惟andR3=2000惟.

Here, R1 and R2 are in parallel. So, the equivalent of these two R12 is as follow

R12=R1R2R1+R2=4000惟脳6000惟4000+6000惟=2400惟

Now, R12 and R3 are in series. So, the equivalent is R

R=R12+R3=2000+2400惟=4400惟

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Most popular questions from this chapter

Figure 27-63 shows an ideal battery of emf e= 12V, a resistor of resistanceR=4.0惟,and an uncharged capacitor of capacitance C=4.0渭贵 . After switch S is closed, what is the current through the resistor when the charge on the capacitor 8.0渭颁?

Question: In Fig. 27-61,Rsis to be adjusted in value by moving the sliding contact across it until points and are brought to the same potential. (One tests for this condition by momentarily connecting a sensitive ammeter between a and b; if these points are at the same potential, the ammeter will not deflect.) Show that when this adjustment is made, the following relation holds: Rx=RsR2/R1. An unknown resistance (RX)can be measured in terms of a standard using this device, which is called a Wheatstone bridge.

In Fig. 27-25, the ideal batteries have emfs 蔚1=12vand 蔚2=6.0v. What are (a) the current, the dissipation rate in (b) resistor 1?(4惟)And (c) resistor 2 (8惟), and the energy transfer rate in (d) battery 1 and (e) battery 2? Is energy being supplied or absorbed by (f) battery 1 and (g) battery 2?

Question: Switch S in Fig. 27-63 is closed at time t=0, to begin charging an initially uncharged capacitor of capacitance C= 150渭F through a resistor of resistanceR =20.0惟. At what time is the potential across the capacitor equal to that across the resistor?

In Fig. 27-33,Battery1 has emf V and internal resistancer1=0.016and battery 2has emf V and internal resistancer2=0.012.The batteries are connected in series with an external resistance R.

(a) What R-value makes the terminal-to-terminal potential difference of one of the batteries zero?

(b) Which battery is that?
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