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The plates of a spherical capacitor have radii 38.0 mmand 40.0 mm(a) Calculate the capacitance. (b) What must be the plate area of a parallel-plate capacitor with the same plate separation and capacitance?

Short Answer

Expert verified
  1. The capacitance of the spherical capacitor is C = 84.5 pF
  2. The plate area of a parallel plate capacitor is 1.9110-2m2

Step by step solution

01

Given

The spherical capacitors have radii 38.0mm10-3m1mm=3.8010-2mandb=40.0mm10-3m1mm=4.0010-2m

The plate separation is the same.

The capacitance is also the same.

02

Determining the concept

By using the equations 25-17 and 25-9, find the capacitance and the plate area of a parallel plate capacitor

Formulae are as follows:

C=4蟿蟿蔚0ab(b-a)

Where C is capacitance, a and b are radiiis the permittivity of the medium.

03

(a) Determining the capacitance of  the spherical capacitor

From the equation 25-17, the capacitance of the spherical capacitor is given by,

C=4蟿蟿蔚0ab(b-a)=43.142(8.8510-12F/m)(3.8010-2m)(4.0010-3m)(4.0010-3m)-(3.8010-2m)=8.4510-11F1pF10-12F=84.5pF

Hence, the capacitance of the spherical capacitor is 84.5 pF.

04

(b) Determining the plate area of a parallel plate capacitor

From the equation 25-9, the plate area of a parallel plate capacitor is given by,

A=C(b-a)0Where,d=(b-a)A=8.4510-11F(4.0010-2m)-(3.8010-2m(8.8510-12F/m)=1.9110-2m2

Hence, the plate area of a parallel plate capacitor is1.9110-2m2.

Therefore, by using the formula the capacitance and the plate area of a parallel plate capacitor can be determined.

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Most popular questions from this chapter

Figure 25-54 shows capacitor 1 (C1=8.00渭贵), capacitor 2 (C2=6.00渭贵), and capacitor 3(C3=8.00渭贵) connected to a 12.0 V battery. When switch S is closed so as to connect uncharged capacitor 4 (C4=6.00渭贵), (a) how much charge passes through point Pfrom the battery and (b) how much charge shows up on capacitor 4? (c) Explain the discrepancy in those two results.

The parallel plates in a capacitor, with a plate area of 8.50cm2and an air filled separation of 3.00 mm, are charged by a 6.00 Vbattery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.00 mm. Neglecting fringing, (a) Find the potential difference between the plates (b)Find the initial stored energy (c)Find the final stored energy (d)Find the work required to separate the plates.

How much energy is stored in 1.00m3of air due to the 鈥渇air weather鈥 electric field of magnitude 150 V/m?

In figure, how much charge is stored on the parallel plate capacitors by the 12.0 Vbattery ? One is filled with air, and the other is filled with a dielectric for which k = 3.00; both capacitors have a plate area of 5.0010-3m2and a plate separation of 2.00 mm.

When a dielectric slab is inserted between the plates of one of the two identical capacitors in Fig. 25-23, do the following properties of that capacitor increase, decrease, or remain the same: (a) capacitance, (b) charge, (c) potential difference, and (d) potential energy? (e) How about the same properties of the other capacitor?

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