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The atomic numbers of the elements are given as,

1. Selenium, Z = 34
2. Bromine, Z = 35
3. Krypton, Z = 36

The arrangement of electrons at the energy level around the nucleus of an atom is an electronic configuration, commonly referred to as an electronic structure.

The distribution of electrons at various molecular orbitals in a molecule is called an electronic configuration. It is important about the molecule. From the electronic activation of a molecule or molecular ion, it is possible to determine the number of electrons in the linking of molecular orbitals and anti-bonding molecular orbitals.

Using the concept of the electronic configuration of an element of maximum electrons accommodated in each subshell, define the required value of the highest occupied shell and the electrons in the shell for each element.

The electronic configuration of the element Selenium with atomic number is given by:

$\left[\mathrm{Ar}\right]3{\mathrm{d}}^{10}4{\mathrm{s}}^{2}4{\mathrm{p}}^4$x

Hence, the value of the highest occupied subshell is 4p.

From the configuration of the above part (a), the number of electrons in the highest subshell of Selenium is found to be 4.

The electronic configuration of the element Bromine with atomic number is given by:

$\left[\mathrm{Ar}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^{10}4{\mathrm{p}}^5$

Hence, the value of the highest occupied subshell is 4p.

From the configuration of the above part (a), the number of electrons in the highest subshell of Bromine is found to be 5.

The electronic configuration of the element Krypton with atomic number is given by:

$\left[\mathrm{Ar}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^{10}4{\mathrm{p}}^6$

Hence, the value of the highest occupied subshell is 4p.

From the configuration of the above part (a), the number of electrons in the highest subshell of Krypton is found to be 6.