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A space vehicle is traveling at \(4300 \mathrm{~km} / \mathrm{h}\) relative to Earth when the exhausted rocket motor (mass \(4 m\) ) is disengaged and sent backward with a speed of \(82 \mathrm{~km} / \mathrm{h}\) relative to the command module (mass \(m\) ). What is the speed of the command module relative to Earth just after the separation?

Short Answer

Expert verified
The command module's speed relative to Earth is 4365.6 km/h.

Step by step solution

01

Identifying the Initial Conditions

The problem states that the mass of the rocket motor is \(4m\), and the mass of the command module is \(m\). The vehicle's initial speed is \(4300 \, \text{km/h}\), and the rocket motor is ejected backward at \(82 \, \text{km/h}\) relative to the command module.
02

Setting Up the Conservation of Momentum Equation

In a closed system, momentum is conserved before and after the event. Let \(v_c\) be the final speed of the command module relative to Earth. The total momentum before the separation is \((4m + m) \times 4300\). After the separation, the motor with mass \(4m\) has a speed \((v_c - 82)\) and the command module has speed \(v_c\).
03

Expression of Conservation of Momentum

The conservation of momentum gives us the equation: \[ (4m + m) \times 4300 = 4m \times (v_c - 82) + m \times v_c. \] Simplify this equation to solve for \(v_c\).
04

Solving for the Command Module's Speed

Combine and simplify the terms in the equation: \[ 4300 \times 5m = 4m(v_c - 82) + m v_c. \] Expand and simplify: \[ 21500m = 4mv_c - 328m + mv_c. \] This simplifies to \[ 21500 = 5v_c - 328. \] Solving for \(v_c\): \[ v_c = \frac{21500 + 328}{5}. \] Calculate the final speed of the command module.
05

Calculating the Final Speed

Solve \( v_c = \frac{21828}{5} = 4365.6 \, \text{km/h}. \) Thus, the speed of the command module relative to Earth just after the separation is \( 4365.6 \, \text{km/h}. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rocket Propulsion
Rocket propulsion is based on Newton's third law of motion which states that for every action, there is an equal and opposite reaction. In the context of rockets, the action is the expulsion of gas molecules out of the rocket, and the reaction is the forward thrust that propels the rocket. This mechanism is crucial in traveling through space where other propulsion methods like conventional engines are ineffective.
When a rocket motor is expelled, as in this exercise, it demonstrates this principle by using the mass of the ejected part and the speed at which it's jettisoned. The mass of the rocket motor and its ejection speed affect the remaining module's velocity. Since the entire system must conserve momentum, the backward force exerted by the motor being expelled results in a forward increase in speed of the remaining craft. Engage with this concept by reflecting on how changes in mass and expulsion velocity impact a spaceship's new trajectory.
Relative Velocity
Relative velocity is a measure of the velocity of one object as observed from another moving object. It illustrates how speeds are perceived differently depending on reference frames. In the example exercise, the rocket motor's speed after separation is given relative to the command module. Understanding relative velocity is crucial in scenarios where different parts of a spacecraft move with respect to each other.
To find the true speed of the command module post-separation, a shared frame of reference must be established, which in most cases is the Earth. By transitioning from one reference frame to another—first within the craft and then to Earth—students can track how motion blends or separates. Recognizing relative velocity's role helps to ease into complex spacecraft maneuvers where various components break away or dock.
Spacecraft Dynamics
Spacecraft dynamics deals with the forces and movements involved in sending vehicles into and through space. It includes understanding velocity changes, rotational motion, and the balancing act required to achieve desired orbits. This exercise focuses specifically on one aspect: ejecting parts of a spacecraft to alter its motion.
In spaceship dynamics, knowing how to apply the conservation of momentum is key. By shedding mass in a particular direction, the spacecraft can accelerate differently than initially planned. This tactic is valuable not just in speed adjustment but also in fine-tuning orbital paths to enable specific missions. By practicing exercises involving separation of parts, students can learn about how physical laws guide modern space travel, keeping spacecraft on the correct trajectory for short-term operations and long-term missions.

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Most popular questions from this chapter

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