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The luxury liner Queen Elizabeth 2 has a diesel-electric power plant with a maximum power of \(92 \mathrm{MW}\) at a cruising speed of \(32.5\) knots. What forward force is exerted on the ship at this speed? \((1 \mathrm{knot}=1.852 \mathrm{~km} / \mathrm{h} .)\)

Short Answer

Expert verified
The forward force exerted is approximately \(5.494 \times 10^6\) N.

Step by step solution

01

Convert the Speed

First, convert the cruising speed from knots to meters per second. Since \(1 \text{ knot} = 1.852 \text{ km/h}\), we multiply \(32.5 \text{ knots} \times 1.852= 60.26 \text{ km/h}\). To convert \(60.26 \text{ km/h}\) to meters per second, use the conversion \(1\text{ km/h} = \frac{1}{3.6} \text{ m/s}\). Therefore, \(60.26 \div 3.6 = 16.74 \text{ m/s}\).
02

Understand Power and Force Relation

Recall the power formula, \(P = F \cdot v\), where \(P\) is power, \(F\) is the force, and \(v\) is velocity. Here, power \(P = 92 \times 10^6 \text{ W}\) and velocity \(v = 16.74 \text{ m/s}\).
03

Calculate Forward Force

Rearrange the formula \(P = F \cdot v\) to solve for force, \(F = \frac{P}{v}\). Substitute the known values: \(F = \frac{92 \times 10^6}{16.74} = 5.494 \times 10^6 \text{ N}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power conversion
In physics, power conversion is the process of changing one form of energy into another. For instance, electrical energy can be converted into mechanical energy. In the case of the Queen Elizabeth 2, the diesel-electric power plant converts chemical energy from diesel fuel into electrical energy, and then into mechanical power to propel the ship forward. This conversion is measured in watts (W), and the ship can generate a substantial power level, reaching up to 92 megawatts (MW). Understanding power conversion is vital for analyzing how efficiently energy is utilized in any system or process, especially in large machinery like ships where each unit of fuel translates directly into force and movement in the water.
Force calculation
To calculate the force exerted by a power source, such as a ship's engine, you need to apply the formula relating power, force, and velocity: \( P = F \cdot v \). In this equation,
  • \( P \) is the power in watts,
  • \( F \) is the force in newtons,
  • \( v \) is the velocity in meters per second.
For the Queen Elizabeth 2, we already know the ship's power output (92 MW) and the converted speed (16.74 m/s). Rearranging the formula gives us \( F = \frac{P}{v} \). By inserting the known values, we find that the force exerted is approximately 5.494 million newtons. This force represents the thrust needed to move the vessel at a constant cruising speed against the resistance encountered in the water.
Velocity conversion
Velocity conversion is essential when dealing with different units in physics, specifically when calculating power and force. In many cases, like with the Queen Elizabeth 2, speeds are often given in non-standard units such as knots due to maritime conventions. To solve the problem efficiently, it's crucial to convert these speeds into meters per second (m/s).
  • First, convert knots to kilometers per hour (km/h), knowing that 1 knot equals 1.852 km/h.
  • Multiply the given knots (32.5 knots) by 1.852 to find the speed in km/h, which yields 60.26 km/h.
  • Next, convert kilometers per hour into meters per second by dividing by 3.6, resulting in a speed of 16.74 m/s.
This conversion is a standard practice in physics to ensure consistency and accuracy when applying formulas such as those for power and force.
Mechanical power
Mechanical power is the rate at which work is done or energy is transferred in a mechanical system. It is often the critical factor when designing and operating engines and machines. The mechanical power of a ship like the Queen Elizabeth 2, calculated in watts, indicates how much work the ship's engine can perform over time. Given the ship's engine generates up to 92 MW, this is a substantial capability for moving such a large vessel. Understanding mechanical power helps engineers to design engines that efficiently translate energy into motion and manage the vessel's performance across different speeds and conditions. The connection between power, force, and velocity ties these concepts together, giving a comprehensive picture of how energy is used in locomotion.

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Most popular questions from this chapter

The spring in the muzzle of a child's spring gun has a spring constant of \(700 \mathrm{~N} / \mathrm{m}\). To shoot a ball from the gun, first the spring is compressed and then the ball is placed on it. The gun's trigger then releases the spring, which pushes the ball through the muzzle. The ball leaves the spring just as it leaves the outer end of the muzzle. When the gun is inclined upward by \(30^{\circ}\) to the horizontal, a \(57 \mathrm{~g}\) ball is shot to a maximum height of \(1.83 \mathrm{~m}\) above the gun's muzzle. Assume air drag on the ball is negligible. (a) At what speed does the spring launch the ball? (b) Assuming that friction on the ball within the gun can be neglected, find the spring's initial compression distance.

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The magnitude of the gravitational force between a particle of mass \(m_{1}\) and one of mass \(m_{2}\) is given by $$ F(x)=G \frac{m_{1} m_{2}}{x^{2}} $$ where \(G\) is a constant and \(x\) is the distance between the particles. (a) What is the corresponding potential energy function \(U(x)\) ? Assume that \(U(x) \rightarrow 0\) as \(x \rightarrow \infty\) and that \(x\) is positive. (b) How much work is required to increase the separation of the particles from \(x=x_{1}\) to \(x=x_{1}+d ?\)

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