/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 A \(1.50 \mathrm{~kg}\) snowball... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(1.50 \mathrm{~kg}\) snowball is fired from a cliff \(12.5 \mathrm{~m}\) high. The snowball's initial velocity is \(14.0 \mathrm{~m} / \mathrm{s}\), directed \(41.0^{\circ}\) above the horizontal. (a) How much work is done on the snowball by the gravitational force during its flight to the flat ground below the cliff? (b) What is the change in the gravitational potential energy of the snowball-Earth system during the flight? (c) If that gravitational potential energy is taken to be zero at the height of the cliff, what is its value when the snowball reaches the ground?

Short Answer

Expert verified
(a) 183.75 J work done by gravity. (b) Change in potential energy is -183.75 J. (c) Ground potential energy is -183.75 J.

Step by step solution

01

- Understanding the Problem

The snowball is launched from a cliff and influenced by gravitational force. We need to find the work done by gravity, change in gravitational potential energy, and its value at certain points during the flight.
02

- Calculating Work Done by Gravity

The work done by gravity can be calculated using the formula: \( W = mgh \), where \( m \) is the mass, \( g \) is the acceleration due to gravity (approximated as \( 9.8 \ m/s^2 \)), and \( h \) is the height of the cliff. For the snowball: \( W = 1.50 \, \mathrm{kg} \times 9.8 \, \mathrm{m/s}^2 \times 12.5 \, \mathrm{m} = 183.75 \, \mathrm{J} \). The work done by gravity is 183.75 J.
03

- Calculating Change in Gravitational Potential Energy

The change in gravitational potential energy \( \Delta U \) is equal to the negative of the work done by gravity, given by \( \Delta U = -mgh \). Therefore, \( \Delta U = -183.75 \, \mathrm{J} \). The change in gravitational potential energy is \(-183.75 \, \mathrm{J}\).
04

- Calculating Gravitational Potential Energy at Ground Level

If gravitational potential energy is zero at the cliff's height, at ground level it becomes \( U = -mgh \). At the ground level: \( U = -183.75 \, \mathrm{J} \). This means the gravitational potential energy at the ground with reference zero at the cliff is \(-183.75 \, \mathrm{J}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work Done by Gravity
When we think about work done in physics, it usually involves a force causing an object to move. In the case of the snowball falling from the cliff, gravity is responsible for this force. Work done by gravity is defined as the force of gravity acting on an object as it travels across a certain distance. In our example, gravity does work on the snowball by pulling it downwards from the height of the cliff to the ground. This can be quantified using the equation:\[ W = mgh \]where:
  • \( W \) is the work done by gravity
  • \( m \) is the mass of the snowball (1.50 kg)
  • \( g \) is the acceleration due to gravity (approximately 9.8 m/s²)
  • \( h \) is the height of the cliff (12.5 m)
Plug in the values and calculate: \( W = 1.50 \times 9.8 \times 12.5 = 183.75 \) Joules. The positive sign indicates that gravity is doing positive work in the direction of the motion.
Gravitational Potential Energy
Gravitational potential energy is the energy stored by an object due to its position relative to the ground. This energy is released when the object moves and can be computed using the formula: \[ U = mgh \]This represents the potential energy at a height above a reference point. For the snowball launched from the cliff, the potential energy at the top is non-zero since it is elevated.When the snowball falls to the ground, the gravitational potential energy is converted into kinetic energy. The change in gravitational potential energy corresponds to the work done by gravity. Therefore, \[ \Delta U = -mgh \]This indicates that 183.75 Joules of potential energy are lost when the snowball descends to ground level, and a negative sign simply shows this decrease.
Kinematics in Projectile Motion
Projectile motion describes the movement of an object thrown into space under the influence of gravity. It's a combination of two motions:
  • Horizontal motion at a constant speed
  • Vertical motion under constant acceleration due to gravity
In our exercise, the snowball is fired with an initial velocity at an angle of 41° above the horizontal. This initial velocity can be broken into horizontal and vertical components using trigonometry:- Horizontal component: \( v_{x} = v\cos(\theta) \)- Vertical component: \( v_{y} = v\sin(\theta) \)where \( v \) is the initial speed (14.0 m/s) and \( \theta \) is the angle of projection (41°). Calculating these components allows us to analyze how the snowball travels through the air.As it moves, the snowball is accelerated vertically by gravity, affecting the trajectory until it reaches the flat ground. Understanding these principles helps in comprehending the motion and behavior of projectiles.

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Most popular questions from this chapter

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