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A baseball player with mass \(m=79 \mathrm{~kg}\), sliding into second base, is retarded by a frictional force of magnitude \(470 \mathrm{~N}\). What is the coefficient of kinetic friction \(\mu_{k}\) between the player and the ground?

Short Answer

Expert verified
The coefficient of kinetic friction \(\mu_k\) is approximately 0.607.

Step by step solution

01

Understanding the Problem

We are given the mass of the baseball player \(m = 79 \text{ kg}\) and the frictional force \(F_k = 470 \text{ N}\). We need to find the coefficient of kinetic friction \( \mu_k \) between the player and the ground.
02

Recall the Formula for Friction Force

The formula for the kinetic frictional force is given by \(F_k = \mu_k \cdot N\), where \(\mu_k\) is the coefficient of kinetic friction and \(N\) is the normal force exerted on the player.
03

Calculate the Normal Force

Since the player is on a horizontal surface, the normal force \(N\) is equal to the gravitational force acting on the player. Thus, \(N = m \cdot g\), where \(g \approx 9.8 \text{ m/s}^2\). Substituting the values, we get \(N = 79 \cdot 9.8 = 774.2 \text{ N}\).
04

Solve for the Coefficient of Kinetic Friction

Using the formula \(F_k = \mu_k \cdot N\), solve for \(\mu_k\):\[ \mu_k = \frac{F_k}{N} = \frac{470}{774.2} \approx 0.607 \].
05

Conclusion

The coefficient of kinetic friction \(\mu_k\) is approximately 0.607.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Frictional Force
Frictional force is the resistance encountered when one surface slides or attempts to slide across another. It's an essential concept in physics, as it plays a pivotal role in the movement of objects. To understand how it works, imagine trying to slide an object across a surface. The frictional force acts in the opposite direction to the motion, opposing it. In the context of this exercise, the baseball player experiences a frictional force of 470 N as he slides into second base. This force results from the interaction between the player's clothing and the ground.

The frictional force can be broken down into two types: static and kinetic. Static friction prevents the start of motion, while kinetic friction acts once movement has already begun. In this scenario, we are dealing with kinetic friction, as the player is already in motion.

The magnitude of the frictional force, often represented by the equation \( F_k = \mu_k \cdot N \), depends on two main factors:
  • The coefficient of kinetic friction \(\mu_k\), which is a dimensionless value representing the different properties of the surfaces in contact.
  • The normal force \(N\), which acts perpendicular to the surfaces in contact.
By understanding these, we can determine how much resistance the player faces as he slides.
The Role of Normal Force
Normal force is a fundamental concept when analyzing forces in physics. It acts perpendicular to the surface that an object is resting on. When objects, like our baseball player, remain on horizontal surfaces, the normal force counteracts the gravitational pull downwards, keeping the object stable.

In our problem, the normal force \(N\) can be derived from the formula \( N = m \cdot g \), where \(m\) is the mass of the object (79 kg for the player) and \(g\) is the acceleration due to gravity (approximately 9.8 \(\text{m/s}^2\)).

By substituting these values, we find that the normal force acting on the player is roughly 774.2 N. This force is crucial as it is directly used to calculate the frictional force, helping to understand how the player slides across the base and interacts with the ground. Normal force is not just limited to horizontal surfaces. On inclined planes, its computation adjusts with respect to the angle of inclination, making force analysis more complex.
Solving Physics Problems Effectively
Solving physics problems like determining the coefficient of kinetic friction involves a systematic approach. Firstly, start by identifying all the given data and what you need to find. This sets the groundwork for your problem-solving journey.

Next, recall and apply relevant physics formulas. In this case, to find the coefficient of kinetic friction \(\mu_k\), you use the relation between frictional force and normal force \( F_k = \mu_k \cdot N \). This step involves more than just memory; understanding why and how each formula works is crucial.

Subsequent to having the right formulas, it's essential to carefully substitute the given values, perform calculations accurately, and interpret the results. Like solving for \(\mu_k\), the formula becomes \(\mu_k = \frac{F_k}{N}\), with our values resulting in approximately 0.607.

Finally, make sure to approach problem-solving with curiosity and patience. Analyze each component thoroughly, check your work for mistakes, and ensure your final answer aligns with the question. Mastering physics requires practice, but with diligence, it becomes manageable.

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Most popular questions from this chapter

A \(1.5 \mathrm{~kg}\) box is initially at rest on a horizontal surface when at \(t=0\) a horizontal force \(\vec{F}=(1.8 t) \hat{\mathrm{i}} \mathrm{N}\) (with \(t\) in seconds) is applied to the box. The acceleration of the box as a function of time \(t\) is given by \(\vec{a}=0\) for \(0 \leq t \leq 2.8 \mathrm{~s}\) and \(\vec{a}=(1.2 t-2.4) \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}^{2}\) for \(t>\) \(2.8 \mathrm{~s}\). (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface?

A police officer in hot pursuit drives her car through a circular turn of radius \(300 \mathrm{~m}\) with a constant speed of \(80.0 \mathrm{~km} / \mathrm{h}\). Her mass is \(55.0 \mathrm{~kg}\). What are (a) the magnitude and (b) the angle (relative to vertical) of the net force of the officer on the car seat? (Hint: Consider both horizontal and vertical forces.)

A child weighing \(140 \mathrm{~N}\) sits at rest at the top of a playground slide that makes an angle of \(25^{\circ}\) with the horizontal. The child keeps from sliding by holding onto the sides of the slide. After letting go of the sides, the child has a constant acceleration of \(0.86 \mathrm{~m} / \mathrm{s}^{2}\) (down the slide, of course). (a) What is the coefficient of kinetic friction between the child and the slide? (b) What maximum and minimum values for the coefficient of static friction between the child and the slide are consistent with the information given here?

A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the box on the plank and gradually raises one end of the plank. When the angle of inclination with the horizontal reaches \(30^{\circ}\), the box starts to slip, and it then slides \(2.5 \mathrm{~m}\) down the plank in \(4.0 \mathrm{~s}\) at constant acceleration. What are (a) the coefficient of static friction and (b) the coefficient of kinetic friction between the box and the plank?

A bicyclist travels in a circle of radius \(25.0 \mathrm{~m}\) at a constant speed of \(9.00 \mathrm{~m} / \mathrm{s}\). The bicycle-rider mass is \(85.0 \mathrm{~kg} .\) Calculate the magnitudes of (a) the force of friction on the bicycle from the road and (b) the net force on the bicycle from the road.

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