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\(.\Rightarrow F\) A circular-motion addict of mass \(80 \mathrm{~kg}\) rides a Ferris wheel around in a vertical circle of radius \(10 \mathrm{~m}\) at a constant speed of \(6.1 \mathrm{~m} / \mathrm{s}\). (a) What is the period of the motion? What is the magnitude of the normal force on the addict from the seat when both go through (b) the highest point of the circular path and (c) the lowest point?

Short Answer

Expert verified
(a) The period is approximately 10.3 seconds. (b) At the highest point, the normal force is about 432 N. (c) At the lowest point, the normal force is about 1282 N.

Step by step solution

01

Calculate the Circumference of the Ferris Wheel

The circumference of the Ferris wheel (the circular path) is given by the formula: \( C = 2\pi r \), where \( r \) is the radius of the circle. Here, \( r = 10 \text{ m} \). So, \( C = 2\pi \times 10 = 20\pi \text{ m} \).
02

Determine the Period of the Circular Motion

The period \( T \) is the time it takes to complete one full circle. It can be calculated using the formula: \( T = \frac{C}{v} \), where \( v \) is the speed of the object. Here, \( v = 6.1 \text{ m/s} \), so \( T = \frac{20\pi}{6.1} \approx 10.3 \text{ seconds}.\)
03

Calculate the Centripetal Force at the Highest Point

At the highest point, the centripetal force \( F_c \) is provided by the gravitational force and the normal force, which can be expressed as: \( F_c = mg - N_h \). The centripetal force also follows: \( F_c = \frac{mv^2}{r} \). Equating both, we get: \( \frac{mv^2}{r} = mg - N_h \). Use \( m = 80 \text{ kg}, v = 6.1 \text{ m/s}, r = 10 \text{ m} \), and \( g = 9.8 \text{ m/s}^2 \).Solve for \( N_h \): \( N_h = mg - \frac{mv^2}{r} \). Substitute the values to get \( N_h = 80 \times 9.8 - \frac{80 \times 6.1^2}{10} \approx 432 \text{ N}.\)
04

Calculate the Centripetal Force at the Lowest Point

At the lowest point, the normal force \( N_l \) and gravitational force add to provide the centripetal force: \( N_l = \frac{mv^2}{r} + mg \). Use same values as before and solve for \( N_l \):\( N_l = \frac{80 \times 6.1^2}{10} + 80 \times 9.8 \approx 1282 \text{ N}.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
Centripetal force is a crucial concept in understanding circular motion. It is the force that keeps an object moving in a circular path, pointing towards the center around which the object is rotating. Essentially, it is the "center-seeking" force that ensures the object doesn't fly outwards. Without centripetal force, a rider on a Ferris wheel would not be able to complete the circular path smoothly.
For an object moving in a circle of radius \( r \) with constant speed \( v \), the centripetal force \( F_c \) is calculated using the formula:
  • \( F_c = \frac{mv^2}{r} \)
where \( m \) is the mass of the object. At any point on the path, other forces like gravitational and normal can contribute to the centripetal force, as seen when the rider is at the highest or lowest points of the Ferris wheel.
Ferris Wheel
A Ferris wheel is essentially a large vertical rotating circular structure. It's not just for amusement rides; it illustrates fundamental physics concepts such as circular motion. In the context of physics, a Ferris wheel provides a great example of how forces like gravity and normal force interact to create motion along a vertical circle.
Riding a Ferris wheel involves moving through both the top (highest point) and bottom (lowest point) of a circular path. This motion leads to varying experiences of force, as gravity either assists or opposes the normal force applied by the seat on the rider. By understanding these experiences, students can visualize how different forces change as they move along the circular path.
Normal Force
The normal force is another vital piece in the puzzle of circular motion in a Ferris wheel. It's the supportive force exerted by a surface to support the weight of an object resting on it, perpendicularly to the surface. When you're at the highest point of a Ferris wheel, the normal force is what feels like it's holding you in the seat.
At the highest point, the normal force \( N_h \) is less due to gravity acting in the same direction as the centripetal force. It is calculated as:
  • \( N_h = mg - \frac{mv^2}{r} \)
Whereas at the lowest point, the normal force \( N_l \) becomes greater because gravity acts opposite to the centripetal force, calculated with:
  • \( N_l = \frac{mv^2}{r} + mg \)
This knowledge helps in understanding why you feel lighter at the top and heavier at the bottom of the ride.
Vertical Circle
A vertical circle is a special type of circular motion where an object moves in a circle in a vertical plane. Examples include looking at a Ferris wheel from the side or watching a gymnast doing a loop. This concept is integral to understanding the behavior of the forces acting on an object, like a Ferris wheel rider, over different segments of the circular path.
As with horizontal circles, the centripetal force keeps the object moving in the circle. However, in vertical circles, gravity plays a significant role in changing the effective force experienced by the object. The combination of gravitational force and centripetal force results in variations in the normal force at different points of the circle. The highest and lowest points in a vertical circle exercise different force interactions, key to the experience of the circular motion.
Period of Motion
The period of motion is an important factor in circular motion. It refers to the time taken for an object to complete one full cycle of its path. For a Ferris wheel, this would be the time it takes to make one full rotation. Mathematically, the period \( T \) can be expressed through the relationship between velocity \( v \) and circumference \( C \):
  • \( T = \frac{C}{v} \)
where \( C \) is the circumference of the circle, given by \( 2\pi r \). Understanding the period helps us comprehend how quickly or slowly an object, like a Ferris wheel, completes its circular path.
In practical terms, examining the period provides insight into optimizing the speed for comfort and synchronization, important in designing amusement park rides to ensure they are enjoyable and safe for all riders.

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Most popular questions from this chapter

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