/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Three forces act on a particle t... [FREE SOLUTION] | 91Ó°ÊÓ

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Three forces act on a particle that moves with unchanging velocity \(\vec{v}=(2 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}-(7 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{j}}\). Two of the forces are \(\vec{F}_{1}=(2 \mathrm{~N}) \hat{\mathrm{i}}+\) \((3 \mathrm{~N}) \hat{\mathrm{j}}+(-2 \mathrm{~N}) \hat{\mathrm{k}}\) and \(\vec{F}_{2}=(-5 \mathrm{~N}) \hat{\mathrm{i}}+(8 \mathrm{~N}) \hat{\mathrm{j}}+(-2 \mathrm{~N}) \hat{\mathrm{k}}\). What is the third force?

Short Answer

Expert verified
The third force is \( \vec{F}_3 = (3 \mathrm{~N}) \hat{\mathrm{i}} - (11 \mathrm{~N}) \hat{\mathrm{j}} + (4 \mathrm{~N}) \hat{\mathrm{k}} \).

Step by step solution

01

Understand the Problem

We have a particle moving with a constant velocity, meaning there is no net force acting on it. The sum of all forces acting on the particle is zero.
02

Write the Force Equation

According to Newton's First Law of motion, since the velocity is constant, the sum of forces acting on the particle is zero: \( \vec{F}_1 + \vec{F}_2 + \vec{F}_3 = 0 \). We need to find \( \vec{F}_3 \).
03

Rearrange the Equation for \( \vec{F}_3 \)

Rearrange the equation to solve for the third force: \( \vec{F}_3 = -\vec{F}_1 - \vec{F}_2 \).
04

Substitute the Given Forces

Substitute \( \vec{F}_1 = (2 \mathrm{~N}) \hat{\mathrm{i}} + (3 \mathrm{~N}) \hat{\mathrm{j}} + (-2 \mathrm{~N}) \hat{\mathrm{k}} \) and \( \vec{F}_2 = (-5 \mathrm{~N}) \hat{\mathrm{i}} + (8 \mathrm{~N}) \hat{\mathrm{j}} + (-2 \mathrm{~N}) \hat{\mathrm{k}} \) into our rearranged equation.
05

Perform the Vector Addition

Calculate \( \vec{F}_3 \) by adding the opposite vectors: \[ \vec{F}_3 = -[(2 \mathrm{~N}) \hat{\mathrm{i}} + (3 \mathrm{~N}) \hat{\mathrm{j}} + (-2 \mathrm{~N}) \hat{\mathrm{k}}] - [(-5 \mathrm{~N}) \hat{\mathrm{i}} + (8 \mathrm{~N}) \hat{\mathrm{j}} + (-2 \mathrm{~N}) \hat{\mathrm{k}}] \].
06

Simplify the Equation

Simplify each component: \( \hat{\mathrm{i}} \) component: \(-2 + 5 = 3 \mathrm{~N}\); \( \hat{\mathrm{j}} \) component: \(-3 - 8 = -11 \mathrm{~N}\); \( \hat{\mathrm{k}} \) component: \(2 + 2 = 4 \mathrm{~N}\). Thus, \( \vec{F}_3 = (3 \mathrm{~N}) \hat{\mathrm{i}} + (-11 \mathrm{~N}) \hat{\mathrm{j}} + (4 \mathrm{~N}) \hat{\mathrm{k}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
When dealing with forces acting in various directions, it is essential to understand how to add vectors. Vectors are not like regular numbers; they have both magnitude and direction. To add them, we consider their components individually. Each force acting on an object can be broken down into its respective components using unit vectors
  • \(\hat{\mathrm{i}}\) - Representing the x-component.
  • \(\hat{\mathrm{j}}\) - Representing the y-component.
  • \(\hat{\mathrm{k}}\) - Representing the z-component.
When we add forces, we sum the components separately. This means that for any vectors \( \vec{A} \) and \( \vec{B} \), the resulting vector \( \vec{A} + \vec{B} \) has components:
  • \(A_x + B_x\) for the x-direction,
  • \(A_y + B_y\) for the y-direction,
  • \(A_z + B_z\) for the z-direction.
In the exercise, the vectors \(\vec{F}_1\) and \(\vec{F}_2\) are added by first finding their negative, as required by the equation to solve for the third force.
Net Force
The net force on an object is the vector sum of all the forces acting upon it. According to Newton's First Law, if an object moves with a constant velocity, the net force is zero. This means all the forces acting on it are balanced, resulting in no change in motion. To maintain a state of motion or rest, the forces must align in such a manner that their sum cancels out.
In the exercise, understanding that the particle moves with constant velocity leads to setting the net force equation to zero:
  • \(\vec{F}_1 + \vec{F}_2 + \vec{F}_3 = 0\)
Solving for \(\vec{F}_3\) involves ensuring the sum of the x, y, and z components collectively cancel out. This embodies the definition of a net force being zero by resolving each directional component.
Constant Velocity
Constant velocity in physics implies that an object is moving in a straight line at a uniform speed. There is no acceleration. In terms of forces, achieving constant velocity requires a balance of all forces, meaning the net force acting is zero.
Newton's First Law explains that an object will move at a constant velocity unless acted upon by an external force. If a particle's speed and direction remain unaltered, it signifies no unbalanced forces are acting on it. In the given exercise, the particle maintains this constant velocity, revealing all exerted forces, including the third unknown force, come together to create equilibrium. The components of these forces precisely balance, maintaining the particle's state of steady motion.

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Most popular questions from this chapter

A \(1400 \mathrm{~kg}\) jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice). Assume that each bolt supports one-third of the load. (a) Calculate the force on each bolt as the plane waits in line for clearance to take off. (b) During flight, the plane encounters turbulence, which suddenly imparts an upward vertical acceleration of \(2.6 \mathrm{~m} / \mathrm{s}^{2}\) to the plane. Calculate the force on each bolt now.

A \(52 \mathrm{~kg}\) circus performer is to slide down a rope that will break if the tension exceeds \(425 \mathrm{~N}\). (a) What happens if the performer hangs stationary on the rope? (b) At what magnitude of acceleration does the performer just avoid breaking the rope?

The Zacchini family was renowned for their human-cannonball act in which a family member was shot from a cannon using either elastic bands or compressed air. In one version of the act, Emanuel Zacchini was shot over three Ferris wheels to land in a net at the same height as the open end of the cannon and at a range of \(69 \mathrm{~m}\). He was propelled inside the barrel for \(5.2 \mathrm{~m}\) and launched at an angle of \(53^{\circ} .\) If his mass was \(85 \mathrm{~kg}\) and he underwent constant acceleration inside the barrel, what was the magnitude of the force propelling him? (Hint: Treat the launch as though it were along a ramp at \(53^{\circ} .\) Neglect air drag.)

Using a rope that will snap if the tension in it exceeds \(387 \mathrm{~N}\), you need to lower a bundle of old roofing material weighing \(449 \mathrm{~N}\) from a point \(6.1 \mathrm{~m}\) above the ground. Obviously if you hang the bundle on the rope, it will snap. So, you allow the bundle to accelerate downward. (a) What magnitude of the bundle's acceleration will put the rope on the verge of snapping? (b) At that acceleration, with what speed would the bundle hit the ground?

An elevator cab that weighs \(27.8 \mathrm{kN}\) moves upward. What is the tension in the cable if the cab's speed is (a) increasing at a rate of \(1.22 \mathrm{~m} / \mathrm{s}^{2}\) and (b) decreasing at a rate of \(1.22 \mathrm{~m} / \mathrm{s}^{2} ?\)

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