/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 A \(75 \mathrm{~kg}\) person rec... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(75 \mathrm{~kg}\) person receives a whole-body radiation dose of \(2.4 \times 10^{-4}\) Gy, delivered by alpha particles for which the RBE factor is 12. Calculate (a) the absorbed energy in joules and the dose equivalent in (b) sieverts and (c) rem.

Short Answer

Expert verified
Absorbed energy: 0.018 J, Dose equivalent: 0.00288 Sv, 0.288 rem.

Step by step solution

01

Determine Absorbed Energy

The absorbed energy in joules can be calculated using the formula:\[ E = D imes m \]where:- \( E \) is the absorbed energy in joules,- \( D = 2.4 \times 10^{-4} \) Gy (absorbed dose),- \( m = 75 \) kg (mass of the person).Substitute the values:\[ E = 2.4 \times 10^{-4} \times 75 = 0.018 \text{ joules} \]
02

Calculate Dose Equivalent in Sieverts

The dose equivalent \( H \) in sieverts is calculated by multiplying the absorbed dose \( D \) by the RBE (Relative Biological Effectiveness) factor:\[ H = D \times ext{RBE} \]Given that the RBE for alpha particles is 12:\[ H = 2.4 \times 10^{-4} \times 12 = 2.88 \times 10^{-3} \text{ Sv} \]
03

Convert Sieverts to Rem

To convert from sieverts to rem, use the conversion factor \( 1 \text{ Sv} = 100 \text{ rem} \):\[ H_{\text{rem}} = H_{\text{Sv}} \times 100 \]So, the dose equivalent in rem is:\[ H_{\text{rem}} = 2.88 \times 10^{-3} \times 100 = 0.288 \text{ rem} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absorbed Energy
Absorbed energy refers to the amount of radiation energy absorbed by a substance, in this case, a human body. It is measured in joules and represents the energy deposited in body tissues by radiation. This is significant because the absorbed energy determines the biological effect of radiation on tissues. The formula to calculate absorbed energy is: \[ E = D \times m \]where:
  • \(E\) is the absorbed energy in joules,
  • \(D\) is the absorbed dose in gray (Gy),
  • \(m\) is the mass of the subject in kilograms.
For example, a person weighing 75 kg receiving an absorbed dose of \(2.4 \times 10^{-4}\) Gy has an absorbed energy of \(0.018\) joules.Understanding absorbed energy helps gauge the potential damage radiation might cause, which is crucial for designing protection measures.
Dose Equivalent
Dose equivalent provides a measure of the biological harm caused by ionizing radiation. It takes into account not just the energy absorbed but also the type of radiation. This helps in assessing the potential biological risk posed by different kinds of radiation. The formula used to calculate the dose equivalent is:\[ H = D \times \text{RBE} \]where:
  • \(H\) is the dose equivalent measured in sieverts (Sv),
  • \(D\) is the absorbed dose in gray (Gy),
  • \(\text{RBE}\) is the Relative Biological Effectiveness factor.
In the context of the given problem, the dose equivalent is \(2.88 \times 10^{-3}\) Sv. It reflects not just energy absorption but also the radiobiological impact of alpha particles with a high RBE factor.
Conversion Factor
Conversion factors are constants used to switch between different units of measurement. When dealing with radiation, conversion factors allow us to translate dose equivalents between sieverts (Sv) and rems. A fundamental conversion to remember is:\[ 1 \text{ Sv} = 100 \text{ rem} \]To convert the dose equivalent from sieverts to rem, multiply the value in sieverts by 100. For instance, if the dose is \(2.88 \times 10^{-3}\) Sv, it converts to \(0.288\) rem. Conversion factors such as these help ensure measurements are understandable worldwide in various units, facilitating global communication in safety practices.
Relative Biological Effectiveness (RBE)
Relative Biological Effectiveness (RBE) is a factor used to compare the biological effects of different types of radiation. It provides insight into how damaging a particular type of radiation might be when compared to a standard reference, usually X-rays or gamma rays. RBE is vital because it accounts for the different ways that the same amount of absorbed energy can cause various levels of biological harm depending on radiation type. For example, alpha particles have a much higher RBE compared to beta particles or gamma rays, indicating more biological damage per absorbed energy unit.In calculations, RBE is used in determining dose equivalents:\[ H = D \times \text{RBE} \]Hence, understanding RBE is critical in radiological protection, ensuring the right measures are taken when dealing with different types of radiation exposure.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(.\) co An \(\alpha\) particle \(\left({ }^{4} \mathrm{He}\right.\) nucleus \()\) is to be taken apart in the following steps. Give the energy (work) required for each step: (a) remove a proton, (b) remove a neutron, and (c) separate the remaining proton and neutron. For an \(\alpha\) particle, what are (d) the total binding energy and (e) the binding energy per nucleon? (f) Does either match an answer to (a), (b), or (c)? Here are some atomic masses and the neutron mass. \(\begin{array}{llll}{ }^{4} \mathrm{He} & 4.00260 \mathrm{u} & { }^{2} \mathrm{H} & 2.01410 \mathrm{u} \\ { }^{3} \mathrm{H} & 3.01605 \mathrm{u} & { }^{1} \mathrm{H} & 1.00783 \mathrm{u} \\ \mathrm{n} & 1.00867 \mathrm{u} & & \end{array}\)

A \(5.00 \mathrm{~g}\) charcoal sample from an ancient fire pit has a \({ }^{14} \mathrm{C}\) activity of \(63.0\) disintegrations \(/ \mathrm{min}\). A living tree has a \({ }^{14} \mathrm{C}\) activity of \(15.3\) disintegrations \(/\) min per \(1.00 \mathrm{~g}\). The half-life of \({ }^{14} \mathrm{C}\) is \(5730 \mathrm{y}\). How old is the charcoal sample?

A measurement of the energy \(E\) of an intermediate nucleus must be made within the mean lifetime \(\Delta t\) of the nucleus and necessarily carries an uncertainty \(\Delta E\) according to the uncertainty principle $$ \Delta E \cdot \Delta t=\hbar . $$ (a) What is the uncertainty \(\Delta E\) in the energy for an intermediate nucleus if the nucleus has a mean lifetime of \(10^{-22} \mathrm{~s} ?(\mathrm{~b})\) Is the nucleus a compound nucleus?

A radium source contains \(1.00 \mathrm{mg}\) of \({ }^{226} \mathrm{Ra}\), which decays with a half-life of \(1600 \mathrm{y}\) to produce \({ }^{222} \mathrm{Rn}\), a noble gas. This radon isotope in turn decays by alpha emission with a half-life of \(3.82 \mathrm{~d}\). If this process continues for a time much longer than the half-life of \({ }^{222} \mathrm{Rn}\), the \({ }^{222}\) Rn decay rate reaches a limiting value that matches the rate at which \({ }^{222} \mathrm{Rn}\) is being produced, which is approximately constant because of the relatively long half-life of \({ }^{226} \mathrm{Ra}\). For the source under this limiting condition, what are (a) the activity of \({ }^{226} \mathrm{Ra},(\mathrm{b})\) the activity of \({ }^{222} \mathrm{Rn}\), and \((\mathrm{c})\) the total mass of \({ }^{222} \mathrm{Rn}\) ?

The half-life of a radioactive isotope is \(140 \mathrm{~d}\). How many days would it take for the decay rate of a sample of this isotope to fall to one- fourth of its initial value?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.