/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 A radioactive nuclide has a half... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A radioactive nuclide has a half-life of \(30.0 \mathrm{y} .\) What fraction of an initially pure sample of this nuclide will remain undecayed at the end of (a) \(60.0 \mathrm{y}\) and (b) \(90.0 \mathrm{y}\) ?

Short Answer

Expert verified
(a) \(\frac{1}{4}\); (b) \(\frac{1}{8}\).

Step by step solution

01

Understand Half-Life

The half-life of a substance is the time required for half of the nuclei in a sample to undergo radioactive decay. For this problem, the nuclide has a half-life of 30 years.
02

Calculate Number of Half-Lives for Part (a)

To find out how many half-lives have passed by 60 years, divide 60 by the half-life of 30 years: \( \frac{60}{30} = 2 \) half-lives.
03

Determine Remaining Fraction for Part (a)

Each half-life reduces the remaining quantity by half. After 2 half-lives, the remaining fraction is computed as \( \left( \frac{1}{2} \right)^2 = \frac{1}{4} \).
04

Calculate Number of Half-Lives for Part (b)

For 90 years, divide 90 by the half-life of 30 years: \( \frac{90}{30} = 3 \) half-lives.
05

Determine Remaining Fraction for Part (b)

After 3 half-lives, the remaining fraction is \( \left( \frac{1}{2} \right)^3 = \frac{1}{8} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life
In the intriguing world of radioactive decay, understanding the concept of half-life is crucial. The half-life of a substance is the period it takes for half of its radioactive nuclei to disintegrate. This time frame remains constant for each type of radioactive nuclide. For example, if you have a sample with a half-life of 30 years, like the nuclide in our problem, it will consistently take 30 years for half of the nuclides in the sample to decay.
Simply put, half-life helps us determine how long it will take for a specific amount of a substance to decay to half its original quantity. It doesn't matter how much of the substance you start with; this time frame remains consistent, making it a reliable measure in predicting the decay process of radioisotopes.
Radioactive Nuclide
A radioactive nuclide, often referred to as a radionuclide, is an atom with an unstable nucleus that loses energy through radiation. When discussing radioactive nuclides like the one in our exercise, these specific radioactive isotopes undergo decay, resulting in the emission of particles or electromagnetic radiation.
Key characteristics to consider when studying radioactive nuclides include:
  • They are unstable and tend to release energy to achieve a more stable form.
  • Each has a unique half-life, which helps determine the rate at which it decays.
  • They play significant roles in various fields, ranging from medicine to energy production.
Understanding radioactive nuclides is essential for comprehending processes involving nuclear reactions and their practical applications.
Fraction Remaining
The term 'fraction remaining' in the context of radioactive decay refers to the amount of the original radioactive sample that still has not decayed. Calculating this fraction is essential to understanding how much of the original radioactive nuclide remains after a certain period.
To find the fraction remaining after a given time, you can use the formula based on the number of elapsed half-lives: \[\text{Fraction remaining} = \left( \frac{1}{2} \right)^n\]where \(n\) is the number of half-lives that have passed.
For example, after 2 half-lives, as seen with 60 years in the exercise, the fraction remaining is \(\left( \frac{1}{2} \right)^2 = \frac{1}{4}\). This means only a quarter of the original sample remains undecayed.
Undecayed Sample
The undecayed sample refers to the portion of the original radioactive material that remains unchanged after a certain time period. This part of the sample has not yet undergone any radioactive decay process and still retains its original properties.
In radioactive decay experiments such as our exercise, the undecayed sample is calculated to observe how much of the radioactive nuclide is left after a series of half-lives.
  • The larger the number of half-lives completed, the smaller the undecayed fraction will be.
  • For our nuclide with a 30-year half-life, only \(\frac{1}{4}\) of the sample remains undecayed after 60 years, and only \(\frac{1}{8}\) after 90 years.
Understanding the concept of an undecayed sample is crucial for calculating how long a substance will remain active or potent in its original form as it gradually decays over time.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The electric potential energy of a uniform sphere of charge \(q\) and radius \(r\) is given by $$ U=\frac{3 q^{2}}{20 \pi \varepsilon_{0} r} $$ (a) Does the energy represent a tendency for the sphere to bind together or blow apart? The nuclide \({ }^{239} \mathrm{Pu}\) is spherical with radius \(6.64\) \(\mathrm{fm}\). For this nuclide, what are (b) the electric potential energy \(U\) according to the equation, (c) the electric potential energy per proton, and (d) the electric potential energy per nucleon? The binding energy per nucleon is \(7.56 \mathrm{MeV}\). (e) Why is the nuclide bound so well when the answers to \((\mathrm{c})\) and \((\mathrm{d})\) are large and positive?

When aboveground nuclear tests were conducted, the explosions shot radioactive dust into the upper atmosphere. Global air circulations then spread the dust worldwide before it settled out on ground and water. One such test was conducted in October \(1976 .\) What fraction of the \({ }^{90}\) Sr produced by that explosion still existed in October 2006? The half-life of \({ }^{90} \mathrm{Sr}\) is \(29 \mathrm{y}\).

What is the mass excess \(\Delta_{1}\) of \({ }^{1} \mathrm{H}\) (actual mass is \(\left.1.007825 \mathrm{u}\right)\) in (a) atomic mass units and (b) \(\mathrm{MeV} / \mathrm{c}^{2}\) ? What is the mass excess \(\Delta_{\mathrm{n}}\) of a neutron (actual mass is \(1.008665 \mathrm{u}\) ) in (c) atomic mass units and (d) \(\mathrm{MeV} / \mathrm{c}^{2} ?\) What is the mass excess \(\Delta_{120}\) of \({ }^{120} \mathrm{Sn}\) (actual mass is \(119.902197 \mathrm{u})\) in (e) atomic mass units and (f) \(\mathrm{MeV} / \mathrm{c}^{2}\) ?

A typical chest x-ray radiation dose is \(250 \mu \mathrm{Sv}\), delivered by \(\mathrm{x}\) rays with an \(\mathrm{RBE}\) factor of \(0.85\). Assuming that the mass of the exposed tissue is one-half the patient's mass of \(88 \mathrm{~kg}\), calculate the energy absorbed in joules.

A neutron star is a stellar object whose density is about that of nuclear matter, \(2 \times 10^{17} \mathrm{~kg} / \mathrm{m}^{3}\). Suppose that the Sun were to collapse and become such a star without losing any of its present mass. What would be its radius?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.