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Suppose two electrons in an atom have quantum numbers \(n=2\) and \(\ell=1 .\) (a) How many states are possible for those two electrons? (Keep in mind that the electrons are indistinguishable.) (b) If the Pauli exclusion principle did not apply to the electrons. how many states would be possible?

Short Answer

Expert verified
There are 15 possible states with the Pauli exclusion principle; without it, there are 45 possible states.

Step by step solution

01

Understanding Quantum Numbers

Quantum numbers specify the properties of electrons in an atom: - The principal quantum number, \(n\), indicates the energy level and can be any positive integer. Here, \(n = 2\). - The angular momentum quantum number, \(\ell\), can range from \(0\) to \(n-1\). Here, \(\ell = 1\) signifies the \(p\) subshell.
02

Calculating Magnetic Quantum Numbers

The magnetic quantum number, \(m_\ell\), can take integer values from \(-\ell\) to \(\ell\). Since \(\ell = 1\), \(m_\ell\) can be \(-1, 0,\) or \(+1\), giving us three values.
03

Considering Spin Quantum Numbers

The spin quantum number, \(m_s\), for an electron can be either \(+\frac{1}{2}\) or \(-\frac{1}{2}\). Each combination of \(n\), \(\ell\), and \(m_\ell\) can pair with both spin states, resulting in a total of 2 spin states per \(m_\ell\) value.
04

Determine Possible States with Pauli Exclusion Principle

With distinct values for \(m_\ell\) and\(m_s\), and considering the Pauli exclusion principle:- For \(m_\ell = -1\), spins \(m_s\) can be \(+\frac{1}{2}, -\frac{1}{2}\).- For \(m_\ell = 0\), spins \(m_s\) can be \(+\frac{1}{2}, -\frac{1}{2}\).- For \(m_\ell = +1\), spins \(m_s\) can be \(+\frac{1}{2}, -\frac{1}{2}\).Since Pauli exclusion states that no two electrons can have the same set of quantum numbers, we calculate combinations for distinct pairs (considering indistinguishability) by choosing a different set for each electron: "}]},{

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum Numbers
Quantum numbers are crucial in determining the identity and behavior of electrons within an atom. They work together like a unique address for each electron, describing its specific energy state and position.

For each electron in an atom, there are four quantum numbers:
  • **Principal quantum number** (\( n \)): indicates the main energy level or shell of an electron and can be any positive integer (1, 2, 3,...). For our problem, both electrons have \( n = 2 \).
  • **Angular momentum quantum number** (\( \ell \)): describes the shape of the electron's orbital and ranges from 0 to \( n-1 \). Here, \( \ell = 1 \) corresponds to a p-type orbital.
  • **Magnetic quantum number** (\( m_\ell \)): relates to the orientation of the orbital in space and ranges from \( -\ell \) to \( \ell \). Given \( \ell = 1 \), \( m_\ell \) can take the values \( -1, 0, \) or \( +1 \).
  • **Spin quantum number** (\( m_s \)): indicates the electron's spin direction. Each electron can have a spin of \( +\frac{1}{2} \) or \( -\frac{1}{2} \).
By combining these quantum numbers, we define the exact state of each electron in an atom.
Electron Configuration
Electron configuration refers to the arrangement of electrons in the orbitals of an atom, which is organized by the aforementioned quantum numbers.

When determining the electron configuration, especially for more complex atoms, it is important to keep in mind:
  • The **Aufbau principle**: Electrons fill orbitals starting at the lowest energy level before moving to higher ones.
  • The **Pauli Exclusion Principle**: No two electrons can have the same set of all four quantum numbers in a single atom. Each electron in the same orbital must have opposite spins.
  • **Hund’s Rule**: For orbitals of the same energy (degenerate orbitals), electrons fill each orbital singly before pairing up.
In our given scenario, knowing that the electrons have \( n = 2 \) and \( \ell = 1 \) situates them in the 2p subshell. Given the different possible values for \( m_\ell \) and the two possible spin states, electron configurations ensure electrons are spread according to these rules in a way that minimizes energy and respects quantum limitations.
Indistinguishable Particles
In the quantum realm, particularly when considering particles like electrons, the concept of distinguishability becomes less intuitive. Electrons are considered indistinguishable because they do not have a unique identity - one electron is identical to another in every respect according to quantum mechanics.

For two electrons in the same atom with the same principal (\( n \)) and angular momentum quantum numbers (\( \ell \)), they can still be differentiated by their other quantum numbers (\( m_\ell \) and \( m_s \)). However, due to the Pauli Exclusion Principle, they cannot share the same quantum state entirely.

With indistinguishable particles like electrons, when calculating the number of possible states, it's important to account for the fact that exchanging two electrons does not lead to a new distinct state but rather the same physical state. As a result, you must consider symmetry and antisymmetry in quantum statistics. This is reflected in our calculation of quantum states, where identical configurations do not count as separate states.

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Most popular questions from this chapter

A recently named element is darmstadtium (Ds), which has 110 electrons. Assume that you can put the 110 electrons into the atomic shells one by one and can neglect any electronelectron interaction. With the atom in ground state, what is the spectroscopic notation for the quantum number \(\ell\) for the last electron?

Comet stimulated emission. When a comet approaches the Sun, the increased warmth evaporates water from the ice on the surface of the comet nucleus, producing a thin atmosphere of water vapor around the nucleus. Sunlight can then dissociate \(\mathrm{H}_{2} \mathrm{O}\) molecules in the vapor to \(\mathrm{H}\) atoms and \(\mathrm{OH}\) molecules. The sunlight can also excite the \(\mathrm{OH}\) molecules to higher energy levels. When the comet is still relatively far from the Sun, the sunlight causes equal excitation to the \(E_{2}\) and \(E_{1}\) levels (Fig. \(40-28 a\) ). Hence, there is no population inversion between the two levels. However, as the comet approaches the Sun, the excitation to the \(E_{1}\) level decreases and population inversion occurs. The reason has to do with one of the many wavelengths - said to be Fraunhofer lines-that are missing in sunlight because, as the light travels outward through the Sun's atmosphere, those particular wavelengths are absorbed by the atmosphere. As a comet approaches the Sun, the Doppler effect due to the comet's speed relative to the Sun shifts the Fraunhofer lines in wavelength, apparently overlapping one of them with the wavelength required for excitation to the \(E_{1}\) level in OH molecules. Population inversion then occurs in those molecules, and they radiate stimulated emission (Fig. \(40-28 b\) ). For example, as comet Kouhoutek approached the Sun in December 1973 and January 1974 , it radiated stimulated emission at about 1666 MHz during mid-January. (a) What was the energy difference \(E_{2}-E_{1}\) for that emission? (b) In what region of the electromagnetic spectrum was the emission?

The wavelength of the \(K_{\alpha}\) line from iron is \(193 \mathrm{pm}\). What is the energy difference between the two states of the iron atom that give rise to this transition?

Show that the number of states with the same quantum number \(n\) is \(2 n^{2}\).

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