/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 A positron undergoes a displacem... [FREE SOLUTION] | 91Ó°ÊÓ

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A positron undergoes a displacement \(\Delta \vec{r}=2.0 \hat{\mathrm{i}}-3.0 \hat{\mathrm{j}}+6.0 \hat{\mathrm{k}}\), ending with the position vector \(\vec{r}=3.0 \hat{\mathrm{j}}-4.0 \hat{\mathrm{k}}\), in meters. What was the positron's initial position vector? w.4 The minute hand of a wall clock measures \(10 \mathrm{~cm}\) from its tip to the axis about which it rotates. The magnitude and angle of the displacement vector of the tip are to be determined for three time intervals. What are the (a) magnitude and (b) angle from a quarter after the hour to half past, the (c) magnitude and (d) angle for the next half hour, and the (e) magnitude and (f) angle for the hour after that?

Short Answer

Expert verified
The initial position vector is \( \vec{r}_0 = -2.0 \hat{\mathrm{i}} + 6.0 \hat{\mathrm{j}} - 10.0 \hat{\mathrm{k}} \).

Step by step solution

01

Identify the Final Position Vector Components

The final position vector of the positron is given as \( \vec{r} = 3.0 \hat{\mathrm{j}} - 4.0 \hat{\mathrm{k}} \). This means the components of the final position vector are \( x_f = 0 \), \( y_f = 3.0 \), and \( z_f = -4.0 \).
02

Identify the Displacement Vector Components

The displacement vector \( \Delta \vec{r} \) is given as \( \Delta \vec{r} = 2.0 \hat{\mathrm{i}} - 3.0 \hat{\mathrm{j}} + 6.0 \hat{\mathrm{k}} \). This means the components of the displacement vector are \( \Delta x = 2.0 \), \( \Delta y = -3.0 \), and \( \Delta z = 6.0 \).
03

Apply the Displacement Formula

To find the initial position vector \( \vec{r}_0 \), we use the equation \( \vec{r} = \vec{r}_0 + \Delta \vec{r} \). This can be rearranged to find \( \vec{r}_0 = \vec{r} - \Delta \vec{r} \). Substitute the final position vector and displacement vector components into the equation.
04

Calculate the Initial Position Vector Components

Calculate each component of the initial position vector:\[ x_0 = x_f - \Delta x = 0 - 2.0 = -2.0 \]\[ y_0 = y_f - \Delta y = 3.0 - (-3.0) = 6.0 \]\[ z_0 = z_f - \Delta z = -4.0 - 6.0 = -10.0 \]
05

Write the Initial Position Vector

The initial position vector \( \vec{r}_0 \) can now be written as:\[ \vec{r}_0 = -2.0 \hat{\mathrm{i}} + 6.0 \hat{\mathrm{j}} - 10.0 \hat{\mathrm{k}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Position Vector
In physics, understanding the initial position vector is crucial in describing the motion of an object. The initial position vector, usually denoted as \( \vec{r}_0 \), represents the starting point of an object in three-dimensional space. It is typically expressed in terms of its components in the x, y, and z directions: \( \vec{r}_0 = x_0\hat{\mathrm{i}} + y_0\hat{\mathrm{j}} + z_0\hat{\mathrm{k}} \).

When dealing with problems involving motion or displacement, knowing the initial position vector allows us to track how much an object has moved from its starting point. In the exercise, the positron's initial position vector is determined by subtracting the displacement vector from its final position vector. Each component of the position vector provides detailed information about the object's initial position in each of the three axes:
  • \( x_0 = x_f - \Delta x \)
  • \( y_0 = y_f - \Delta y \)
  • \( z_0 = z_f - \Delta z \)
This calculated initial position vector gives a comprehensive snapshot of where the positron began its journey in space.
Final Position Vector
The final position vector is a key concept in vector displacement problems, indicating the object's position after undergoing a movement. Notated as \( \vec{r} \), it provides the coordinates of an object at the conclusion of its motion. For three-dimensional spaces, the vector is expressed as \( \vec{r} = x_f\hat{\mathrm{i}} + y_f\hat{\mathrm{j}} + z_f\hat{\mathrm{k}} \).

Understanding the final position vector is essential for both tracking movement and calculating other vectors such as displacement or initial position. In the problem, the final position vector of the positron is given with components: \( x_f = 0 \), \( y_f = 3.0 \), and \( z_f = -4.0 \). These values reflect the ending location along each axis after the motion has occurred.

To find the initial position vector using the given final position, we incorporate the displacement vector. The relationship and computations between these vectors highlight how the object moved and set the stage for analyzing its path through space.
Displacement Vector Components
The displacement vector is a fundamental vector concept that describes how an object's position changes over time. It is represented as \( \Delta \vec{r} = \Delta x\hat{\mathrm{i}} + \Delta y\hat{\mathrm{j}} + \Delta z\hat{\mathrm{k}} \), and is found by subtracting the initial position vector from the final position vector.

In the given exercise, the displacement vector signifies the movement of the positron through space, with the components being \( \Delta x = 2.0 \), \( \Delta y = -3.0 \), and \( \Delta z = 6.0 \). Each part of this vector tells us how far and in what direction the positron has shifted along those axes.
  • The positive \( \Delta x \) indicates a move rightward along the x-axis.
  • The negative \( \Delta y \) shows a downward movement along the y-axis.
  • The positive \( \Delta z \) points to an upward movement along the z-axis.
This vector plays a pivotal role in both determining the object's initial position and understanding its trajectory during the movement. It connects the initial and final positions, allowing us to back-calculate and interpret the positron's journey in a clear, component-based manner.

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Most popular questions from this chapter

A soccer ball is kicked from the ground with an initial speed of \(19.5 \mathrm{~m} / \mathrm{s}\) at an upward angle of \(45^{\circ} .\) A player \(55 \mathrm{~m}\) away in the direction of the kick starts running to meet the ball at that instant. What must be his average speed if he is to meet the ball just before it hits the ground?

A particle starts from the origin at \(t=0\) with a velocity of \(8.0 \hat{\mathrm{j}} \mathrm{m} / \mathrm{s}\) and moves in the \(x y\) plane with constant acceleration \((4.0 \hat{\mathrm{i}}+2.0 \mathrm{j}) \mathrm{m} / \mathrm{s}^{2} .\) When the particle's \(x\) coordinate is \(29 \mathrm{~m}\), what are its (a) \(y\) coordinate and (b) speed?

A projectile is fired horizontally from a gun that is \(45.0 \mathrm{~m}\) above flat ground, emerging from the gun with a speed of \(250 \mathrm{~m} / \mathrm{s}\). (a) How long does the projectile remain in the air? (b) At what horizontal distance from the firing point does it strike the ground? (c) What is the magnitude of the vertical component of its velocity as it strikes the ground?

A particle \(P\) travels with constant speed on a circle of radius \(r=\) \(3.00 \mathrm{~m}\) (Fig. \(4-56)\) and completes one revolution in \(20.0 \mathrm{~s}\). The particle passes through \(O\) at time \(t=0 .\) State the following vectors in magnitudeangle notation (angle relative to the positive direction of \(x\) ). With respect to \(O\), find the particle's position vector at the times \(t\) of (a) \(5.00 \mathrm{~s}\), (b) \(7.50 \mathrm{~s}\), and \((\mathrm{c}) 10.0 \mathrm{~s}\). (d) For the \(5.00 \mathrm{~s}\) interval from the end of the fifth second to the end of the tenth second, find the particle's displacement. For that interval, find (e) its average velocity and its velocity at the (f) beginning and (g) end. Next, find the acceleration at the (h) beginning and (i) end of that interval.

The fast French train known as the TGV (Train à Grande Vitesse) has a scheduled average speed of \(216 \mathrm{~km} / \mathrm{h} .\) (a) If the train goes around a curve at that speed and the magnitude of the acceleration experienced by the passengers is to be limited to \(0.050 \mathrm{~g}\), what is the smallest radius of curvature for the track that can be tolerated? (b) At what speed must the train go around a curve with a \(1.00 \mathrm{~km}\) radius to be at the acceleration limit?

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