/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 127 A frightened rabbit moving at \(... [FREE SOLUTION] | 91Ó°ÊÓ

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A frightened rabbit moving at \(6.00 \mathrm{~m} / \mathrm{s}\) due east runs onto a large area of level ice of negligible friction. As the rabbit slides across the ice, the force of the wind causes it to have a constant acceleration of \(1.40 \mathrm{~m} / \mathrm{s}^{2}\), due north. Choose a coordinate system with the origin at the rabbit's initial position on the ice and the positive \(x\) axis directed toward the east. In unit-vector notation, what are the rabbit's (a) velocity and (b) position when it has slid for \(3.00 \mathrm{~s}\) ?

Short Answer

Expert verified
Velocity: \(6.00 \, \hat{i} + 4.20 \, \hat{j} \, \mathrm{m/s}\); Position: \(18.00 \, \hat{i} + 6.30 \, \hat{j} \, \mathrm{m}\).

Step by step solution

01

Analyze the Initial Conditions

The rabbit starts with an initial velocity of \(6.00 \, \mathrm{m/s}\) to the east, which corresponds to the positive \(x\)-axis direction. Hence, the initial velocity vector is \(\vec{v}_0 = 6.00 \, \hat{i} \). The acceleration is \(1.40 \, \mathrm{m/s^2}\) to the north, which corresponds to the positive \(y\)-axis direction, making the acceleration vector \(\vec{a} = 1.40 \, \hat{j} \). These vectors define the initial state of the rabbit on the coordinate plane.
02

Calculate the Rabbit's Velocity After 3 Seconds

The formula to find velocity as a function of time when starting with an initial velocity and a constant acceleration is: \( \vec{v}(t) = \vec{v}_0 + \vec{a} t \).Substitute the known values: \(\vec{v}_0 = 6.00 \, \hat{i}\), \(\vec{a} = 1.40 \, \hat{j}\), and \(t = 3.00 \, \mathrm{s}\).\[ \vec{v}(3.00 \, \mathrm{s}) = 6.00 \, \hat{i} + (1.40 \, \hat{j}) \times 3.00 \]\[ \vec{v} = 6.00 \, \hat{i} + 4.20 \, \hat{j} \]Therefore, the velocity of the rabbit in unit-vector notation after 3 seconds is \(\vec{v} = 6.00 \, \hat{i} + 4.20 \, \hat{j} \, \mathrm{m/s}\).
03

Calculate the Rabbit's Position After 3 Seconds

To find the position, use the formula \( \vec{r}(t) = \vec{r}_0 + \vec{v}_0 t + \frac{1}{2} \vec{a} t^2 \). Here, the initial position \(\vec{r}_0\) is the origin, so \(\vec{r}_0 = 0\).Substitute the values: \(\vec{v}_0 = 6.00 \, \hat{i}\), \(\vec{a} = 1.40 \, \hat{j}\), and \(t = 3.00 \, \mathrm{s}\).\[ \vec{r}(3.00 \, \mathrm{s}) = 6.00 \, \hat{i} \times 3.00 + \frac{1}{2} \times 1.40 \, \hat{j} \times (3.00)^2 \]\[ \vec{r} = 18.00 \, \hat{i} + 6.30 \, \hat{j} \]Thus, the position of the rabbit in unit-vector notation after 3 seconds is \(\vec{r} = 18.00 \, \hat{i} + 6.30 \, \hat{j} \, \mathrm{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Velocity
In the study of projectile motion, the concept of "Initial Velocity" is fundamental. When an object begins its journey, the speed and direction at which it is launched are critical initial conditions. For our example, the rabbit starts running on the ice with an initial velocity of \(6.00 \ \mathrm{m/s}\) due east. This means that from the very beginning, the rabbit is moving at a constant speed in the x direction. We express this initial motion in unit-vector notation as \(6.00\ \hat{i} \ \mathrm{m/s}\).
This vector notation helps us understand the direction—east here is represented by the \(\hat{i}\) component of the vector. By clearly identifying the initial velocity, we set the stage for calculating subsequent changes in speed and direction, especially when other forces, such as wind, come into play. Understanding initial velocity as a vector quantity allows for a clearer appreciation of how multiple influences interact over time.
Constant Acceleration
"Constant Acceleration" is a key player in altering an object's velocity over time. Acceleration occurs when a force is applied, causing the object to speed up, slow down, or change direction. In the case of the rabbit, a wind force provides an acceleration of \(1.40 \ \mathrm{m/s^2}\) northward, characterized in unit-vector form as \(1.40\ \hat{j}\ \text{m/s}^2\).
Understanding acceleration in vector form is crucial, as it signifies both magnitude and direction—north in this scenario is represented by \(\hat{j}\). Because this acceleration is constant, it simplifies our calculations, allowing us to use the formula \( \vec{v}(t) = \vec{v}_0 + \vec{a} t \) to find the velocity at any given time. This means that after every instant, the rabbit's velocity in the northward direction increases by a constant amount every second—1.40 meters per second.
In projectile motion, the consistency of acceleration often relates to gravity, but in this example, it's the consistent wind force causing deviation from the initial straight path.
Position Vector
The "Position Vector" describes the object's location at a given time. For the rabbit, which started at the origin of the coordinate system, the position at any minute can be calculated using the formula: \[ \vec{r}(t) = \vec{r}_0 + \vec{v}_0 t + \frac{1}{2} \vec{a} t^2 \]The initial position \(\vec{r}_0 \) is zero, since the rabbit begins sliding at the origin. The term \(\vec{v}_0 t\) accounts for the distance covered due to initial velocity, while \(\frac{1}{2} \vec{a} t^2\) represents the additional distance due to acceleration.
For example, after 3 seconds, these calculations show the rabbit is at position \(18.00 \hat{i} + 6.30 \hat{j} \ \mathrm{m}\). This vector indicates movement 18 meters east and 6.3 meters north due to the initial velocity and influence of constant acceleration. Understanding the position vector provides a comprehensive picture of motion, incorporating the influences of speed, time, and directional forces.

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Most popular questions from this chapter

In a jump spike, a volleyball player slams the ball from overhead and toward the opposite floor. Controlling the angle of the spike is difficult. Suppose a ball is spiked from a height of \(2.30\) \(\mathrm{m}\) with an initial speed of \(20.0 \mathrm{~m} / \mathrm{s}\) at a downward angle of \(18.00^{\circ} .\) How much farther on the opposite floor would it have landed if the downward angle were, instead, \(8.00^{\circ} ?\)

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