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A rectangular corral of widths \(L_{x}=L\) and \(L_{y}=2 L\) holds an electron. What multiple of \(h^{2} / 8 m L^{2}\), where \(m\) is the electron mass, gives (a) the energy of the electron's ground state, (b) the energy of its first excited state, (c) the energy of its lowest degenerate states, and (d) the difference between the energies of its second and third excited states?

Short Answer

Expert verified
(a) \(\frac{5}{4}\), (b) \(\frac{17}{4}\), (c) \(\frac{17}{4}\), (d) \(\frac{5}{8}\).

Step by step solution

01

Understanding the problem

We have a rectangular corral with dimensions \(L_x = L\) and \(L_y = 2L\). We need to find different energy states of an electron in this corral. The energy levels in a two-dimensional box are given by the formula \(E_{n_x, n_y} = \frac{h^2}{8m} \left(\frac{n_x^2}{L_x^2} + \frac{n_y^2}{L_y^2}\right)\). Here, \(n_x\) and \(n_y\) are quantum numbers.
02

Ground state energy calculation

The ground state corresponds to the lowest possible energy values, which are \(n_x = 1\) and \(n_y = 1\). Plug these into the energy formula: \(E_{1,1} = \frac{h^2}{8m} \left(\frac{1^2}{L^2} + \frac{1^2}{(2L)^2}\right) = \frac{h^2}{8m} \left(\frac{1}{L^2} + \frac{1}{4L^2}\right) = \frac{h^2}{8mL^2} \left(\frac{5}{4}\right)\). Thus the energy is \(\frac{5}{4} \times \frac{h^2}{8mL^2}\).
03

First excited state energy calculation

The first excited state will have the next lowest total energy, typically with quantum numbers \(n_x = 2, n_y = 1\) or \(n_x = 1, n_y = 2\). Calculate: \(E_{2,1} = \frac{h^2}{8m} \left(\frac{2^2}{L^2} + \frac{1^2}{(2L)^2}\right) = \frac{h^2}{8mL^2} \left(\frac{4}{1} + \frac{1}{4}\right) = \frac{h^2}{8mL^2} \times \frac{17}{4}\).
04

Lowest degenerate states energy calculation

Degenerate states have the same energy. The lowest degenerate states occur when \(n_x = 2, n_y = 1\) and \(n_x = 1, n_y = 2\). Both yield \(E = \frac{h^2}{8mL^2} \times \frac{17}{4}\), confirming their degeneracy.
05

Energy difference between second and third excited states

The second excited state \(E_{2,1}\) and \(n_x = 3, n_y = 1\) or \(n_x = 1, n_y = 3\) as the third results in \(E_{1,3} = E_{3,1} = \frac{h^2}{8m} \left(\frac{1}{L^2} + \frac{9}{4L^2}\right) = \frac{h^2}{8mL^2}\times \frac{37}{4} \). Therefore, the difference \(\Delta E = \frac{h^2}{8mL^2} \times \left(\frac{37}{4} - \frac{17}{4}\right) = \frac{5h^2}{8mL^2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy States
In quantum mechanics, energy states refer to the specific levels of energy that a quantum system, like an electron in a box, can have. These states are quantized, meaning that the energy levels are discrete rather than continuous.
Energy states are determined based on quantum numbers that describe the system. In a rectangular corral, such as the one described in the problem, the energy of the electron is calculated using an equation that incorporates these quantum numbers and the dimensions of the corral:
  • The energy formula for a two-dimensional region is given by \[ E_{n_x, n_y} = \frac{h^2}{8m} \left(\frac{n_x^2}{L_x^2} + \frac{n_y^2}{L_y^2}\right) \]where \(h\) is Planck's constant, \(m\) is the mass of the electron, and \(n_x\) and \(n_y\) are quantum numbers corresponding to the system's state.

  • The simplest energy state, called the ground state, occurs at the lowest energy level with quantum numbers \(n_x = 1\) and \(n_y = 1\).
    For the given corral dimensions, it computes to an energy level of \(\frac{5}{4} \times \frac{h^2}{8mL^2}\).
Degenerate States
Degenerate states in a quantum system occur when two or more energy states have the same energy level. This is a fascinating occurrence because, despite different configurations of quantum numbers, the states share identical energy values.
In the given problem, we encounter degenerate states for the electron held in a rectangular corral. The two known lowest degenerate states are defined by the pairs \( (n_x = 2, n_y = 1) \) and \( (n_x = 1, n_y = 2) \).
To understand why this happens, consider how the energy formula involves summing two contributions:
  • The term \(n_x^2/L_x^2\) arising from the x-dimension, and
  • The term \(n_y^2/L_y^2\) from the y-dimension.

When these sums yield the same total energy, degenerate states occur. For this specific problem, each of the quantum number sets leads to the same calculated energy: \(\frac{h^2}{8mL^2} \times \frac{17}{4}\). Identifying these states helps in understanding the symmetry and behavior of quantum systems.
Quantum Numbers
In quantum mechanics, quantum numbers play a crucial role in defining the unique quantum state of a system. Each quantum number corresponds to a specific property of the quantum system. In a two-dimensional rectangular system, as presented in the problem, quantum numbers determine the energy states and the specific characteristics of the electron's behavior.
  • \(n_x\) and \(n_y\) are the quantum numbers that designate the x and y dimensional states respectively.
    They take on positive integer values (e.g., 1, 2, 3, ...), representing the allowable energy levels in each direction.

  • Their values directly factor into the energy equations. By adjusting \(n_x\) and \(n_y\), you define the quantum state that the electron occupies.

These numbers are not just mathematical constructs; they represent the allowed conditions the electron can exist in while bounded by the confines of the corral. In essence, quantum numbers are the keys to understanding how the intricacies of quantum systems work under specific constraints and conditions.

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Most popular questions from this chapter

A neutron with a kinetic energy of \(6.0 \mathrm{eV}\) collides with a stationary hydrogen atom in its ground state. Explain why the collision must be elastic-that is, why kinetic energy must be conserved. (Hint: Show that the hydrogen atom cannot be excited as a result of the collision.)

In a simple model of a hydrogen atom, the single electron orbits the single proton (the nucleus) in a circular path. Calculate (a) the electric potential set up by the proton at the orbital radius of \(52.9 \mathrm{pm},(\mathrm{b})\) the electric potential energy of the atom, and (c) the kinetic energy of the electron. (d) How much energy is required to ionize the atom (that is, to remove the electron to an infinite distance with no kinetic energy)? Give the energies in electron-volts.

An electron is confined to a narrow evacuated tube of length \(3.0 \mathrm{~m}\); the tube functions as a one-dimensional infinite potential well. (a) What is the energy difference between the electron's ground state and its first excited state? (b) At what quantum number \(n\) would the energy difference between adjacent energy levels be \(1.0 \mathrm{eV}-\) which is measurable, unlike the result of (a)? At that quantum number, (c) what multiple of the electron's rest energy would give the electron's total energy and (d) would the electron be relativistic?

An atom (not a hydrogen atom) absorbs a photon whose associated frequency is \(6.2 \times 10^{14} \mathrm{~Hz} .\) By what amount does the energy of the atom increase?

Suppose that an electron trapped in a one-dimensional infinite well of width \(250 \mathrm{pm}\) is excited from its first excited state to its third excited state. (a) What energy must be transferred to the electron for this quantum jump? The electron then de-excites back to its ground state by emitting light. In the various possible ways it can do this, what are the (b) shortest, (c) second shortest, (d) longest, and (e) second longest wavelengths that can be emitted? (f) Show the various possible ways on an energy-level diagram. If light of wavelength \(29.4 \mathrm{~nm}\) happens to be emitted, what are the \((\mathrm{g})\) longest and \((\mathrm{h})\) shortest wavelength that can be emitted afterwards?

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