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How much work must be done to increase the speed of an electron (a) from \(0.18 c\) to \(0.19 c\) and (b) from \(0.98 c\) to \(0.99 c\) ? Note that the speed increase is \(0.01 c\) in both cases.

Short Answer

Expert verified
Work needed increases significantly as speed approaches the speed of light.

Step by step solution

01

Understanding the Problem

We need to calculate the work done to change the speed of an electron from one velocity to another. Work done can be generally expressed as the change in kinetic energy, which in relativistic terms requires using the relativistic kinetic energy formula.
02

Relativistic Kinetic Energy Formula

The relativistic kinetic energy is given by the formula \[ KE = ( rac{1}{ ext{sqrt}(1- rac{v^2}{c^2})}-1)m_ec^2 \]where \( m_e \) is the electron rest mass \(= 9.11 \times 10^{-31} \text{ kg} \), and \( c \) is the speed of light \(= 3 \times 10^8 \text{ m/s} \).
03

Calculate Initial and Final Kinetic Energy (Part A)

To find the work done from increasing speed from \( 0.18c \) to \( 0.19c \), calculate the initial and final kinetic energies:Initial speed \( v_i = 0.18c \), \[ KE_i = ( rac{1}{ ext{sqrt}(1-(0.18)^2)}-1)m_ec^2 \]Final speed \( v_f = 0.19c \), \[ KE_f = ( rac{1}{ ext{sqrt}(1-(0.19)^2)}-1)m_ec^2 \]
04

Calculate Work Done (Part A)

The work done is the change in kinetic energy;\[ W = KE_f - KE_i \]Substitute the values of \( KE_f \) and \( KE_i \) from part A calculations.
05

Calculate Initial and Final Kinetic Energy (Part B)

For the speed increase from \( 0.98c \) to \( 0.99c \), determine the kinetic energies similarly:Initial speed \( v_i = 0.98c \),\[ KE_i = ( rac{1}{ ext{sqrt}(1-(0.98)^2)}-1)m_ec^2 \]Final speed \( v_f = 0.99c \),\[ KE_f = ( rac{1}{ ext{sqrt}(1-(0.99)^2)}-1)m_ec^2 \]
06

Calculate Work Done (Part B)

Now calculate the work needed;\[ W = KE_f - KE_i \]Input the values for \( KE_f \) and \( KE_i \) computed for Part B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work-Energy Principle
The Work-Energy Principle is a fundamental concept in physics that states that the work done on an object is equal to the change in its kinetic energy. This principle can be expressed mathematically as:
  • Work Done (W) = Final Kinetic Energy (KEf) - Initial Kinetic Energy (KEi)
In simpler terms, when you apply a force to an object and it moves, you're doing work on the object, which results in a change in its kinetic energy. This principle applies universally, whether you're dealing with everyday speeds or high-speed particles like electrons.
In the realm of classical physics, kinetic energy calculations are straightforward. However, as velocities approach the speed of light, classical physics is no longer sufficient. Instead, we enter the domain of relativistic physics, where the computations and principles require adjustments to incorporate the effects predicted by Einstein's Theory of Relativity.
Relativistic Physics
Relativistic Physics comes into play when dealing with velocities that are a significant fraction of the speed of light. Classical mechanics assumptions break down, and the principles of relativity must be considered. According to Einstein’s Theory of Relativity, mass increases with speed, leading to adjustments in kinetic energy calculations.
This means the relativistic kinetic energy can't be calculated using the simple \( KE = \frac{1}{2}mv^2 \) formula. Instead, it involves a correction factor accounting for the velocity's proximity to the speed of light (c), expressed as:
  • \( KE = \left(\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}-1\right)m_ec^2 \)
where:
- \( m_e \) is the rest mass of the electron.
- \( v \) is the velocity of the electron.
These corrections ensure that calculations like those for an electron's change in speed adhere to the relativistic restrictions that keep velocities from surpassing the speed of light. This consideration is vital in high-speed environments, such as particle accelerators.
Kinetic Energy Calculation
Kinetic energy calculation in a relativistic context requires understanding both how speed changes affect energy and how to apply the relativistic formula accurately. To calculate the work done to increase an electron's speed, follow these steps:
  • Determine initial and final velocities in terms of the speed of light \( (v_i, v_f) \).
  • Plug these velocities into the relativistic kinetic energy formula \( KE = \left(\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}-1\right)m_ec^2 \).
  • Calculate the kinetic energy for both initial and final speeds.
  • Subtract the initial kinetic energy from the final kinetic energy to find the work done (\( W = KE_f - KE_i \)).
In the exercise, the velocities were given as fractions of \( c \), specifically \( 0.18c \) to \( 0.19c \) and \( 0.98c \) to \( 0.99c \). Despite the same speed increment, the energy required to change the electron's speed increases substantially as it nears the speed of light because the relativistic effects become more pronounced.

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Most popular questions from this chapter

An unstable high-energy particle enters a detector and leaves a track of length \(1.05 \mathrm{~mm}\) before it decays. Its speed relative to the detector was \(0.992 c .\) What is its proper lifetime? That is, how long would the particle have lasted before decay had it been at rest with respect to the detector?

An airplane has rest length \(40.0 \mathrm{~m}\) and speed \(630 \mathrm{~m} / \mathrm{s}\). To a ground observer, (a) by what fraction is its length contracted and (b) how long is needed for its clocks to be \(1.00 \mu \mathrm{s}\) slow.

What are (a) \(K,(\) b) \(E\), and \((\mathrm{c}) p(\) in \(\mathrm{GeV} / c)\) for a proton moving at speed \(0.990 c\) ? What are (d) \(K\), (e) \(E\), and (f) \(p\) (in \(\mathrm{MeV} / c\) ) for an electron moving at speed \(0.990 c ?\)

The car-in-the-garage problem. Carman has just purchased the world's longest stretch limo, which has a proper length of \(L_{c}=30.5 \mathrm{~m}\). In Fig. \(37-32 a\), it is shown parked in front of a garage with a proper length of \(L_{g}=6.00 \mathrm{~m} .\) The garage has a front door (shown open) and a back door (shown closed). The limo is obviously longer than the garage. Still, Garageman, who owns the garage and knows something about relativistic length contraction, makes a bet with Carman that the limo can fit in the garage with both doors closed. Carman, who dropped his physics course before reaching special relativity, says such a thing, even in principle, is impossible. To analyze Garageman's scheme, an \(x_{c}\) axis is attached to the limo, with \(x_{c}=0\) at the rear bumper, and an \(x_{g}\) axis is attached to the garage, with \(x_{g}=0\) at the (now open) front door. Then Carman is to drive the limo directly toward the front door at a velocity of \(0.9980 \mathrm{c}\) (which is, of course, both technically and financially impossible). Carman is stationary in the \(x_{c}\) reference frame; Garageman is stationary in the \(x_{g}\) reference frame. There are two events to consider. Event \(1:\) When the rear bumper clears the front door, the front door is closed. Let the time of this event be zero to both Carman and Garageman: \(t_{g 1}=t_{c 1}=0\). The event occurs at \(x_{c}=x_{g}=0\). Figure \(37-32 b\) shows event 1 according to the \(x_{g}\) reference frame. Event 2 : When the front bumper reaches the back door, that door opens. Figure \(37-32 c\) shows event 2 according to the \(\bar{x}_{8}\) reference frame. According to Garageman, (a) what is the length of the limo, and what are the spacetime coordinates (b) \(x_{g^{2}}\) and (c) \(t_{g 2}\) of event \(2 ?\) (d) For how long is the limo temporarily "trapped" inside the garage with both doors shut? Now consider the situation from the \(x_{c}\) reference frame, in which the garage comes racing past the limo at a velocity of \(-0.9980 c\). According to Carman, (e) what is the length of the passing garage, what are the spacetime coordinates (f) \(x_{c 2}\) and (g) \(t_{c 2}\) of event \(2,(\mathrm{~h})\) is the limo ever in the garage with both doors shut, and (i) which event occurs first? (j) Sketch events 1 and 2 as seen by Carman. (k) Are the events causally related; that is, does one of them cause the other? (I) Finally, who wins the bet?

A meter stick in frame \(S^{\prime}\) makes an angle of \(30^{\circ}\) with the \(x^{\prime}\) axis. If that frame moves parallel to the \(x\) axis of frame \(S\) with speed \(0.90 c\) relative to frame \(S\), what is the length of the stick as measured from \(S ?\)

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