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A diffraction grating \(3.00 \mathrm{~cm}\) wide produces the second order at \(33.0^{\circ}\) with light of wavelength \(600 \mathrm{~nm}\). What is the total number of lines on the grating?

Short Answer

Expert verified
The grating has approximately 13,636 lines.

Step by step solution

01

Understand the Diffraction Grating Equation

The diffraction grating condition for bright fringes is given by the formula \( d \sin(\theta) = m\lambda \), where \( m \) is the order of the maximum, \( d \) is the distance between adjacent grating lines (called the grating spacing), \( \theta \) is the angle of diffraction, and \( \lambda \) is the wavelength of light.
02

Identify Given Values

We are given that the diffraction grating produces the second order (\( m = 2 \)) maximum at an angle \( \theta = 33.0^{\circ} \) with light of wavelength \( \lambda = 600 \mathrm{~nm} \). The total width of the grating is \( 3.00 \mathrm{~cm} \).
03

Use the Equation to Find Grating Spacing

Substituting the given values into the diffraction grating equation: \( d \sin(33.0^{\circ}) = 2 \times 600 \times 10^{-9} \mathrm{~m} \). First, calculate \( \sin(33.0^{\circ}) \), then solve for \( d \).
04

Calculate \( \sin(33.0^{\circ}) \) and Grating Spacing \( d \)

Calculate \( \sin(33.0^{\circ}) \approx 0.545 \). Substitute in the equation: \( d \times 0.545 = 1.2 \times 10^{-6} \). Solve for \( d \): \( d = \frac{1.2 \times 10^{-6}}{0.545} \approx 2.20 \times 10^{-6} \mathrm{~m} \).
05

Calculate Number of Lines on the Grating

The number of lines \( N \) on the grating is the total width of the grating divided by the spacing \( d \) between lines: \( N = \frac{3.00 \mathrm{~cm}}{2.20 \times 10^{-6} \mathrm{~m}} \). Convert \( 3.00 \mathrm{~cm} \) to meters (\( 3.00 \mathrm{~cm} = 0.03 \mathrm{~m} \)) and solve: \( N = \frac{0.03}{2.20 \times 10^{-6}} \approx 13636 \).
06

Round the Result

Given the precision of the measurements, round \( 13636 \) to the appropriate number of significant figures, resulting in \( 1.36 \times 10^{4} \) lines.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Grating Spacing
Grating spacing refers to the distance between two adjacent slits on a diffraction grating. This spacing is crucial as it determines how the light wave interferes and spreads after passing through the grating. The formula to find grating spacing is derived from the diffraction equation:
  • \( d \sin(\theta) = m\lambda \)
Here, \( d \) denotes the grating spacing, \( \theta \) is the angle of diffraction, \( m \) represents the order of maximum, and \( \lambda \) is the wavelength of light.
To calculate the grating spacing in our problem, use the values: angle \( \theta = 33.0^{\circ} \), order \( m = 2 \), and wavelength \( \lambda = 600 \mathrm{~nm} \). First, convert the angle to a sine value, \( \sin(33.0^{\circ}) \approx 0.545 \). Then substitute these values into the equation to find \( d \).
This practical understanding of grating spacing helps in calculating distances needed for assembling or designing optical equipment accurately.
Angle of Diffraction
The angle of diffraction is the angle at which light waves emerge after passing through a grating relative to the original direction. This angle depends on both the grating spacing and the light's wavelength. It is instrumental in determining how light bends and spreads, forming various diffraction patterns.
To find the angle of diffraction for a given setup, the diffraction equation \( d \sin(\theta) = m\lambda \) is used. In this equation, solving for \( \theta \) can help measure how much the light has spread. In practical scenarios, instruments need to be precisely aligned based on this angle to ensure optimal performance.
Measuring and understanding this angle is fundamental in applications ranging from spectroscopy to laser engineering. It allows the manipulation of light for experiments and technological innovations.
Order of Maximum
The order of maximum, denoted by \( m \), refers to the discrete levels of light intensity peaks that are observed in diffraction patterns. These are the bright fringes created as a result of constructive interference of the light waves passing through the grating.
In essence, the integer \( m \) in the equation \( d \sin(\theta) = m\lambda \) stands for different spots of maximum brightness.
  • \( m = 0 \) represents the central or zeroth order.
  • \( m = 1, 2, 3, \ldots \) are the first, second, and higher orders respectively, which means further from the center.
For our problem, the second-order maximum is given, so \( m = 2 \). Recognizing the order of maximum helps in mapping out the positions of these bright fringes on a screen or sensor, critical for analyzing optical waves.
Wavelength of Light
The wavelength of light is a measure of the distance between successive peaks of a light wave. It is an essential property that affects how light interacts with materials, including diffraction gratings. Given in nanometers (nm) or meters, the wavelength helps in identifying different types of light, such as visible, ultraviolet, or infrared.
Inserting the wavelength into the diffraction equation \( d \sin(\theta) = m\lambda \) allows us to calculate other variables like the angle of diffraction or the grating spacing.
In this case, the problem involves a wavelength \( \lambda = 600 \mathrm{~nm} \), corresponding to orange light in the visible spectrum. Recognizing and using the correct wavelength is vital in comparing experimental results and ensuring accurate calculations in scientific studies and precise engineering applications, like designing lenses and sensors.

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Most popular questions from this chapter

A beam of light consisting of wavelengths from \(460.0 \mathrm{~nm}\) to \(640.0 \mathrm{~nm}\) is directed perpendicularly onto a diffraction grating with 160 lines/mm. (a) What is the lowest order that is overlapped by another order? (b) What is the highest order for which the complete wavelength range of the beam is present? In that highest order, at what angle does the light at wavelength (c) \(460.0 \mathrm{~nm}\) and (d) \(640.0 \mathrm{~nm}\) appear? (e) What is the greatest angle at which the light at wavelength \(460.0 \mathrm{~nm}\) appears?

Light of wavelength \(633 \mathrm{~nm}\) is incident on a narrow slit. The angle between the first diffraction minimum on one side of the central maximum and the first minimum on the other side is \(1.20^{\circ} .\) What is the width of the slit?

A grating has 600 rulings/mm and is \(5.0 \mathrm{~mm}\) wide. (a) What is the smallest wavelength interval it can resolve in the third order at \(\lambda=500 \mathrm{~nm} ?\) (b) How many higher orders of maxima can be seen?

A diffraction grating is made up of slits of width \(300 \mathrm{~nm}\) with separation \(900 \mathrm{~nm}\). The grating is illuminated by monochromatic plane waves of wavelength \(\lambda=600 \mathrm{~nm}\) at normal incidence. (a) How many maxima are there in the full diffraction pattern? (b) What is the angular width of a spectral line observed in the first order if the grating has 1000 slits?

A double-slit system with individual slit widths of \(0.030 \mathrm{~mm}\) and a slit separation of \(0.18 \mathrm{~mm}\) is illuminated with \(500 \mathrm{~nm}\) light directed perpendicular to the plane of the slits. What is the total number of complete bright fringes appearing between the two first-order minima of the diffraction pattern? (Do not count the fringes that coincide with the minima of the diffraction pattern.)

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