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A source containing a mixture of hydrogen and deuterium atoms emits red light at two wavelengths whose mean is \(656.3 \mathrm{~nm}\) and whose separation is \(0.180 \mathrm{~nm} .\) Find the minimum number of lines needed in a diffraction grating that can resolve these lines in the first order.

Short Answer

Expert verified
A minimum of 3646 lines is needed in the diffraction grating to resolve these lines in the first order.

Step by step solution

01

Identify Key Information

We are given the mean wavelength \( \lambda_m = 656.3 \text{ nm} \) and the separation between wavelengths \( \Delta \lambda = 0.180 \text{ nm} \). Recall that diffraction and resolution need these values.
02

Recall the Resolution Formula

The resolution condition for minimum resolving power \( R \) of the diffraction grating is given by \( R = \frac{\lambda}{\Delta \lambda} \). This condition relates to the order \( m \) and the number of lines \( N \) on the grating with \( R = mN \).
03

Calculate Resolving Power

Using the resolution condition, \( R = \frac{\lambda_m}{\Delta \lambda} = \frac{656.3}{0.180} \). Calculate this to find the required resolving power.
04

Compute the Number of Lines Needed

Assuming first-order diffraction (\( m = 1 \)), plug the resolving power \( R \) from Step 3 into the equation \( R = mN \), giving \( N = \frac{R}{m} \). Solve for \( N \) to find the minimum number of lines.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resolution Formula
The resolution formula is a crucial concept when dealing with diffraction gratings. It helps us understand how well a system can distinguish between closely spaced wavelengths of light. The formula is:\[ R = \frac{\lambda}{\Delta \lambda} \]Where:- \( R \) is the resolving power.- \( \lambda \) is the average wavelength of the light.- \( \Delta \lambda \) is the separation between the wavelengths.This equation highlights the relationship between the wavelength difference and the system's ability to resolve them as distinct lines. A higher resolving power indicates that the system can decipher closer wavelengths more effectively. In applied problems, knowing the resolution formula allows one to determine the capabilities of a diffraction grating in discerning specific light spectrums.
Resolving Power
Resolving power is an essential feature of a diffraction grating. It quantifies how well a grating can differentiate between two nearby wavelengths. This property is vital for applications like spectroscopy, where precise measurements are needed.Resolving power can be calculated using the equation:\[ R = mN \]- \( R \) is the resolving power.- \( m \) is the order of diffraction.- \( N \) represents the number of lines in the grating.The larger the resolving power, the better the diffraction grating is at distinguishing between close spectral lines. In our exercise, calculating resolving power helps figure out the number of lines necessary for resolving two wavelengths in the first order.
Wavelength Separation
Wavelength separation refers to the difference in wavelengths that we aim to resolve with a diffraction grating. It is denoted as \( \Delta \lambda \) in physics.In our problem, the separation between the two wavelengths is given as 0.180 nm. This small separation challenges the resolving power of the grating. Wavelength separation is a crucial factor because:- It determines the resolution needed from the grating.- Smaller separations require higher resolving powers.- It influences the choice of grating based on the application's sensitivity requirements.By plugging the given separation into the resolution formula, one can better grasp the physical constraints and identify the grating specifications needed.
First Order Diffraction
First order diffraction occurs when the diffracted light forms a pattern at the primary angle for constructive interference. It is characterized by \( m = 1 \), indicating that the path difference between adjacent lines is one full wavelength.This order is significant because:- It typically provides the clearest and most distinct spectral lines.- Calculations in first order (\( m = 1 \)) are often used as a starting point for determining grating characteristics.- The resolving power obtained here can guide more complex analyses in higher orders.In the given exercise, first order diffraction is chosen to determine the minimum number of lines required. By using \( m = 1 \), the relationship between resolving power and the number of lines is simplified, easing the computation for educational purposes.

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Most popular questions from this chapter

The wall of a large room is covered with acoustic tile in which small holes are drilled \(5.0 \mathrm{~mm}\) from center to center. How far can a person be from such a tile and still distinguish the individual holes, assuming ideal conditions, the pupil diameter of the observer's eye to be \(4.0 \mathrm{~mm}\), and the wavelength of the room light to be \(550 \mathrm{~nm}\) ?

Find the separation of two points on the Moon's surface that can just be resolved by the 200 in. \((=5.1 \mathrm{~m})\) telescope at Mount Palomar, assuming that this separation is determined by diffraction effects. The distance from Earth to the Moon is \(3.8 \times\) \(10^{5} \mathrm{~km}\). Assume a wavelength of \(550 \mathrm{~nm}\) for the light.

What is the smallest Bragg angle for \(x\) rays of wavelength \(30 \mathrm{pm}\) to reflect from reflecting planes spaced \(0.30 \mathrm{~nm}\) apart in a calcite crystal?

The wings of tiger beetles (Fig. \(36-41\) ) are colored by interference due to thin cuticle-like layers. In addition, these layers are arranged in patches that are \(60 \mu \mathrm{m}\) across and produce different colors. The color you see is a pointillistic mixture of thin-film interference colors that varies with perspective. Approximately what viewing distance from a wing puts you at the limit of resolving the different colored patches according to Rayleigh's criterion? Use \(550 \mathrm{~nm}\) as the wavelength of light and \(3.00 \mathrm{~mm}\) as the diameter of your pupil.

In a single-slit diffraction experiment, there is a minimum of intensity for orange light \((\lambda=600 \mathrm{~nm})\) and a minimum of intensity for blue- green light \((\lambda=500 \mathrm{~nm})\) at the same angle of \(1.00\) mrad. For what minimum slit width is this possible?

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