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Visible light is incident perpendicularly on a grating with 315 rulings/mm. What is the longest wavelength that can be seen in the fifth-order diffraction?

Short Answer

Expert verified
The longest wavelength is 635 nm.

Step by step solution

01

Understand the Diffraction Grating Equation

The diffraction grating formula is given by \( d \sin \theta = m \lambda \), where \( d \) is the distance between adjacent slits, \( \theta \) is the diffraction angle, \( m \) is the order of the diffraction, and \( \lambda \) is the wavelength of the light. Since the light is incident perpendicularly, \( \theta \) becomes 90 degrees at maximum, leading \( \sin \theta = 1 \).
02

Calculate the Grating Spacing \(d\)

The grating spacing \(d\) is the distance between adjacent rulings. Since there are 315 rulings per mm, the spacing \(d\) is \( \frac{1}{315} \) mm per ruling. Convert this into meters: \( d = \frac{1}{315,000} \) m.
03

Setup the Equation for Maximum Wavelength

To find the longest wavelength at which diffraction can occur, set \( \sin \theta = 1 \) for the maximum possible angle. Substitute \( d \) and solve for \( \lambda \) in the equation: \( d \cdot 1 = m \lambda \). As we are considering the fifth-order diffraction, \( m = 5 \). Hence: \( d = 5 \lambda \).
04

Solve for Wavelength \(\lambda\)

Substituting \( d = \frac{1}{315,000} \) meters into the rearranged equation: \( \lambda = \frac{d}{5} = \frac{1}{5 \times 315,000} \) meters. Calculating this gives \( \lambda \approx 6.35 \times 10^{-7} \) meters, which translates to 635 nm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength Calculation
Understanding how to calculate the wavelength from a diffraction grating experiment is a key concept in physics. The fundamental relationship used is the diffraction grating equation: \( d \sin \theta = m \lambda \). Here, we are interested in calculating the wavelength \( \lambda \) for a given order of diffraction \( m \), using known parameters such as the grating spacing \( d \). For the maximum wavelength, where \( \theta = 90^\circ \), the value of \( \sin \theta \) simplifies to 1. Thus, the formula is reduced to \( d = m \lambda \). In our specific problem, by substituting the grating spacing \( d \) and diffraction order, we compute the wavelength for the longest possible visible light in the given order. Calculating this involves straightforward arithmetic once the equation is set up.
Diffraction Order
In any diffraction grating analysis, the concept of diffraction order \( m \) plays a vital role. When light passes through a diffraction grating, it creates patterns of maxima and minima. Each maximum corresponds to a specific diffraction order. The primary or first maximum is denoted as the first-order diffraction \( m = 1 \). For higher orders \( m \), the maxima occur at larger angles, effectively separating the light based on its wavelength. The higher the order, the greater the angle of diffraction. In our example, the fifth-order diffraction signifies that we are observing the maximum away from the central peak, at the angle where the light path difference is equal to five times its wavelength. This concept is crucial for accurately analyzing and predicting how light behaves when it interacts with a grating.
Grating Spacing
Grating spacing \( d \) is an essential parameter in diffraction experiments. It describes the distance between adjacent lines or rulings on the grating. In simpler terms, it is the inverse of the number of lines per unit length on the grating surface. To find this value, you take the reciprocal of the number of lines per millimeter or any other computational unit. In this exercise, with 315 rulings per millimeter, the grating spacing was calculated as \( d = \frac{1}{315,000} \) meters. This small distance greatly influences how the diffraction patterns form and at what angles different wavelengths will appear. The precise calculation of \( d \) is fundamental to determining the exact distribution and separation of light into its spectrum.
Visible Light Spectrum
The visible light spectrum encompasses the range of electromagnetic waves that are detectable by the human eye. This range extends approximately from 380 nm to 750 nm. When light interacts with a diffraction grating, it spreads out into its component colors, much like a rainbow. The position and visibility of each color depend on various factors, including the wavelength of the light and the order of diffraction being observed. In our case, determining the longest wavelength in the fifth-order diffraction involves understanding where this wavelength falls within the visible spectrum. It exemplifies how gratings can be used to measure and analyze visible light, producing results like our calculated 635 nm wavelength, which corresponds to a red hue in the visible spectrum. This deep understanding supports a wide range of applications, from designing optical instruments to exploring fundamental physics.

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Most popular questions from this chapter

(a) A circular diaphragm \(60 \mathrm{~cm}\) in diameter oscillates at a frequency of \(25 \mathrm{kHz}\) as an underwater source of sound used for submarine detection. Far from the source, the sound intensity is distributed as the diffraction pattern of a circular hole whose diameter equals that of the diaphragm. Take the speed of sound in water to be \(1450 \mathrm{~m} / \mathrm{s}\) and find the angle between the normal to the diaphragm and a line from the diaphragm to the first minimum. (b) Is there such a minimum for a source having an (audible) frequency of \(1.0 \mathrm{kHz}\) ?

A diffraction grating \(1.00 \mathrm{~cm}\) wide has 10000 parallel slits. Monochromatic light that is incident normally is diffracted through \(30^{\circ}\) in the first order. What is the wavelength of the light?

Entoptic halos. If someone looks at a bright outdoor lamp in otherwise dark surroundings, the lamp appears to be surrounded by bright and dark rings (hence halos) that are actually a circular diffraction pattern as in Fig. \(36-10\), with the central maximum overlapping the direct light from the lamp. The diffraction is produced by structures within the cornea or lens of the eye (hence entoptic). If the lamp is monochromatic at wavelength \(550 \mathrm{~nm}\) and the first dark ring subtends angular diameter \(2.5^{\circ}\) in the observer's view, what is the (linear) diameter of the structure producing the diffraction?

A beam of light with a narrow wavelength range centered on \(450 \mathrm{~nm}\) is incident perpendicularly on a diffraction grating with a width of \(1.80 \mathrm{~cm}\) and a line density of 1400 lines/cm across that width. For this light, what is the smallest wavelength difference this grating can resolve in the third order?

A diffraction grating \(20.0 \mathrm{~mm}\) wide has 6000 rulings. Light of wavelength \(589 \mathrm{~nm}\) is incident perpendicularly on the grating. What are the (a) largest, (b) second largest, and (c) third largest values of \(\theta\) at which maxima appear on a distant viewing screen?

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