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A small spaceship with a mass of only \(1.5 \times 10^{3} \mathrm{~kg}\) (including an astronaut) is drifting in outer space with negligible gravitational forces acting on it. If the astronaut turns on a \(10 \mathrm{~kW}\) laser beam, what speed will the ship attain in \(1.0\) day because of the momentum carried away by the beam?

Short Answer

Expert verified
The speed attained by the ship is approximately \(1.92 \times 10^{-3} \text{ m/s}\).

Step by step solution

01

Understand Laser Power and Momentum Relationship

First, understand that the power of a laser beam is related to the momentum carried away by the beam. The power (P) of the laser is given as 10 kW, which is equivalent to 10,000 J/s. The momentum of a photon is related to its energy by the equation \( p = \frac{E}{c} \), where \( E \) is the energy and \( c \) is the speed of light \( 3 \times 10^{8} \) m/s.
02

Calculate Total Energy Output

Over the course of 1.0 day, calculate the total energy output of the laser. Since there are 86,400 seconds in a day, the total energy output \( E \) is given by \( E = P \times \text{time} = 10,000 \text{ J/s} \times 86,400 \text{ s} = 8.64 \times 10^{8} \text{ J} \).
03

Calculate Total Momentum Carried Away

Use the total energy output to calculate the total momentum carried away by the laser beam. Using \( p = \frac{E}{c} \), the momentum is \( p = \frac{8.64 \times 10^{8} \text{ J}}{3 \times 10^{8} \text{ m/s}} \approx 2.88 \text{ kg} \cdot \text{m/s} \).
04

Apply Momentum Conservation

The momentum gained by the spaceship is equal to the momentum carried away by the laser beam due to conservation of momentum. If \( v \) is the final velocity of the spaceship, using \( m \cdot v = p \) where \( m = 1.5 \times 10^{3} \text{ kg} \), we have \( 1.5 \times 10^{3} \times v = 2.88 \).
05

Solve for Final Velocity

Rearrange the equation \( 1.5 \times 10^{3} \times v = 2.88 \) to find the speed of the spaceship. Thus, \( v = \frac{2.88}{1.5 \times 10^{3}} = 1.92 \times 10^{-3} \text{ m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
Momentum is a fundamental concept in physics, and it plays a critical role in understanding how objects interact and move. The law of conservation of momentum states that in a closed system, the total momentum before any event is equal to the total momentum after the event. This principle applies no matter the nature of forces at play, provided no external forces act on the system.

In the context of the spaceship question, the conservation of momentum allows us to predict how the spaceship's velocity changes when the laser is activated. As the laser emits a beam of photons, these photons carry momentum away. To conserve momentum, the spaceship must gain an equal amount of momentum in the opposite direction. This changes the spaceship's velocity, even in the vast emptiness of outer space.

Understanding this principle helps us see how momentum exchange can occur without direct contact, which is a fascinating aspect of how propulsion systems might work in space.
Photon Momentum
Photons, the particles of light, although massless, still carry energy and momentum. This might seem counterintuitive, as we often associate momentum with mass, but photons get their momentum from their energy. According to the formula, the momentum of a photon is given by \( p = \frac{E}{c} \), where \( E \) is energy and \( c \) is the speed of light.

When a laser emits photons, those photons exert a small, yet significant, pressure as they travel. This pressure is what propels the spaceship forward in our exercise, even though it seems imperceptible on Earth. Over time, and especially without gravitational interference, photon momentum becomes important for spacecraft propulsion in outer space.
  • The energy of the photons determines how much momentum they can impart.
  • The speed of light is constant, ensuring a constant translation from energy to momentum.
  • This property is a key factor in developing light-based propulsion systems.
Kinetic Energy
Kinetic energy is the energy possessed by a body due to its motion. It's calculated by the formula \( KE = \frac{1}{2}mv^2 \), where \( m \) is mass and \( v \) is velocity. Although kinetic energy is not explicitly called for in solving our spaceship problem, it’s a crucial aspect of understanding energy transfers and motions in physics.

In our context, as the spaceship gains speed due to the momentum provided by the laser, its kinetic energy also changes. However, unlike momentum, kinetic energy doesn't need to be conserved unless mechanical energy conservation is specified, which isn’t the case here. Nonetheless, the velocity calculated from conservation of momentum can help infer changes in kinetic energy.

In space, where there are fewer resistive forces like air friction, the only significant energy conversion is from the momentum exchanged between photons and the space vehicle, emphasizing the clever utilization of energy for motion.
Outer Space Physics
Outer space is a unique environment for the application of physical laws. It presents conditions unlike those on Earth, for instance, negligible gravitational forces and lack of atmosphere, affecting how physics operates. When considering the movement of objects in space, factors such as momentum and energy exchange take center stage.

In a spacecraft scenario, like in our exercise, propulsion has to rely on methods different from terrestrial vehicles because traditional fuel combustion requires an atmosphere. Vacuum conditions in space offer limitless opportunity for exploring alternative propulsion systems, such as the momentum from photons. The space's vacuum ensures that even minute thrusts, like those from a laser, can appreciably change the velocity over time.
  • No atmosphere means less drag, amplifying effects from even small forces.
  • Zero gravity conditions change how forces and motions are calculated.
  • The conservation of energy and momentum operates more visibly without Earth's interference.

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Most popular questions from this chapter

About how far apart must you hold your hands for them to be separated by \(1.0\) nano-light-second (the distance light travels in \(1.0 \mathrm{~ns}\) )?

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Frank D. Drake, an investigator in the SETI (Search for Extra-Terrestrial Intelligence) program, once said that the large radio telescope in Arecibo, Puerto Rico (Fig. 33-36), "can detect a signal which lays down on the entire surface of the earth a power of only one picowatt." (a) What is the power that would be received by the Arecibo antenna for such a signal? The antenna diameter is \(300 \mathrm{~m}\). (b) What would be the power of an isotropic source at the center of our galaxy that could provide such a signal? The galactic center is \(2.2 \times 10^{4}\) ly away. A light-year is the distance light travels in one year.

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