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An electron is placed in a magnetic field \(\vec{B}\) that is directed along a \(z\) axis. The energy difference between parallel and antiparallel alignments of the \(z\) component of the electron's spin magnetic moment with \(\vec{B}\) is \(6.00 \times 10^{-25} \mathrm{~J}\). What is the magnitude of \(\vec{B}\) ?

Short Answer

Expert verified
The magnitude of the magnetic field is approximately 0.0323 T.

Step by step solution

01

Understanding the Problem

We need to find the magnitude of the magnetic field \( \vec{B} \) when an electron is placed in it. The energy difference between the electron's spin magnetic moment aligned parallel and antiparallel with the \( z \) axis is given as \( 6.00 \times 10^{-25} \) J.
02

Formula for Energy Difference

The energy difference \( \Delta E \) between the parallel and antiparallel alignments is given by the Zeeman effect. The formula is \( \Delta E = g \mu_B B \), where \( g \) is the Landé g-factor (approximately 2 for an electron), \( \mu_B \) is the Bohr magneton, and \( B \) is the magnitude of the magnetic field.
03

Value of Bohr Magneton

The Bohr magneton \( \mu_B \) is a constant given by: \( \mu_B = 9.274 \times 10^{-24} \text{ J/T} \).
04

Solve for B

Rearrange the formula \( \Delta E = g \mu_B B \) to solve for \( B \): \[ B = \frac{\Delta E}{g \mu_B} \]Substitute the values: \( \Delta E = 6.00 \times 10^{-25} \) J, \( g = 2 \), and \( \mu_B = 9.274 \times 10^{-24} \text{ J/T} \).
05

Calculate B

Plug in the values to find \( B \):\[ B = \frac{6.00 \times 10^{-25}}{2 \times 9.274 \times 10^{-24}} \]\[ B = \frac{6.00 \times 10^{-25}}{1.8548 \times 10^{-23}} \]\[ B \approx 0.0323 \text{ T} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Spin
Electron spin is a fundamental property of electrons, much like charge or mass. It can be thought of as an intrinsic form of angular momentum. Simply put, spin is a quantum mechanical feature that does not have a classical analogy, making it a unique aspect.

Electrons have two possible spin states: spin-up and spin-down. These refer to the orientation of an electron's magnetic moment.
  • Spin-up implies that the magnetic moment aligns positively with the magnetic field direction.
  • Spin-down means it aligns negatively or opposite to the field.
Spin is crucial because it induces a magnetic moment, which allows the electron to interact with external magnetic fields. To visualize it, imagine a tiny magnet that comes with each electron due to its spin.

Furthermore, when placed in a magnetic field, the electron's spin states can lead to different energy levels, which are essential components when discussing phenomena like the Zeeman effect.
Zeeman Effect
The Zeeman effect is named after Pieter Zeeman, who discovered how spectral lines are split into several components in the presence of a magnetic field. It specifically involves the interaction between the electron spin and a magnetic field.

When an external magnetic field is introduced, energy levels of electrons are not single but split based on their spin states. This happens because the magnetic field interacts with the magnetic moment of the electron, causing these energy differences.

The formula used to describe this energy difference is:\[ \Delta E = g \mu_B B \]where:
  • \( \Delta E \) is the energy difference between the two spin states.
  • \( g \) is the Landé g-factor, a dimensionless value.
  • \( \mu_B \) is the Bohr magneton.
  • \( B \) indicates the magnetic field strength.
This effect is significant as it provides insights into quantum mechanics, allowing scientists to observe the influence of the magnetic field on atomic and subatomic scales.
Bohr Magneton
The Bohr magneton, denoted as \( \mu_B \), is a constant that represents the magnetic moment of an electron due to its spin. It serves as a fundamental quantum of magnetic moment in quantum mechanics.

To put it into perspective, the Bohr magneton is calculated using the formula:\[ \mu_B = \frac{e \hbar}{2m_e} \]where \( e \) is the electron charge, \( \hbar \) is the reduced Planck's constant, and \( m_e \) is the electron mass.

Numerically, the Bohr magneton is approximately \( 9.274 \times 10^{-24} \, \text{J/T} \). This constant is essential when calculating the effects of magnetic fields at the atomic level, especially involving electron behaviors in magnetic materials.

In the context of solving problems involving magnetic fields and electron spins, the Bohr magneton simplifies the interaction terms and helps quantify the electron's magnetic moment, contributing largely to the understanding of atomic and subatomic phenomena.

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Most popular questions from this chapter

The magnitude of the magnetic dipole moment of Earth is \(8.0 \times 10^{22} \mathrm{~J} / \mathrm{T}\). (a) If the origin of this magnetism were a magnetized iron sphere at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? Assume complete alignment of the dipoles. The density of Earth's inner core is \(14 \mathrm{~g} / \mathrm{cm}^{3} .\) The magnetic dipole moment of an iron atom is \(2.1 \times 10^{-23} \mathrm{~J} / \mathrm{T}\). (Note: Earth's inner core is in fact thought to be in both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth's magnetism has been ruled out by several considerations. For one, the temperature is certainly above the Curie point.)

If an electron in an atom has orbital angular momentum with \(m_{\ell}\) values limited by \(\pm 3\), how many values of (a) \(L_{\text {orb } z}\) and (b) \(\mu_{\text {orb } z}\) can the electron have? In terms of \(h, m\), and \(e\), what is the greatest allowed magnitude for (c) \(L_{\text {orb }, z}\) and \((\) d \() \mu_{\text {orb }, z} ?\) (e) What is the greatest allowed magnitude for the \(z\) component of the electron's \(n e t\) angular momentum (orbital plus spin)? (f) How many values (signs included) are allowed for the \(z\) component of its net angular momentum?

A \(0.50 \mathrm{~T}\) magnetic field is applied to a paramagnetic gas whose atoms have an intrinsic magnetic dipole moment of \(1.0 \times\) \(10^{-23} \mathrm{~J} / \mathrm{T}\). At what temperature will the mean kinetic energy of translation of the atoms equal the energy required to reverse such a dipole end for end in this magnetic field?

The magnitude of the dipole moment associated with an atom of iron in an iron bar is \(2.1 \times 10^{-23} \mathrm{~J} / \mathrm{T}\). Assume that all the atoms in the bar, which is \(5.0 \mathrm{~cm}\) long and has a cross-sectional area of \(1.0 \mathrm{~cm}^{2}\), have their dipole moments aligned. (a) What is the dipole moment of the bar? (b) What torque must be exerted to hold this magnet perpendicular to an external field of magnitude \(1.5 \mathrm{~T} ?\) (The density of iron is \(7.9 \mathrm{~g} / \mathrm{cm}^{3} .\) )

Earth has a magnetic dipole moment of \(8.0 \times 10^{22} \mathrm{~J} / \mathrm{T}\). (a) What current would have to be produced in a single turn of wire extending around Earth at its geomagnetic equator if we wished to set up such a dipole? Could such an arrangement be used to cancel out Earth's magnetism (b) at points in space well above Earth's surface or (c) on Earth's surface?

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