/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Two vectors are given by and ... [FREE SOLUTION] | 91Ó°ÊÓ

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Two vectors are given by and $$\begin{aligned}&\vec{a}=(4.0 \mathrm{~m}) \hat{\mathrm{i}}-(3.0 \mathrm{~m}) \hat{\mathrm{j}}+(1.0 \mathrm{~m}) \hat{\mathrm{k}} \\ &\vec{b}=(-1.0 \mathrm{~m}) \hat{\mathrm{i}}+(1.0 \mathrm{~m}) \hat{\mathrm{j}}+(4.0 \mathrm{~m}) \hat{\mathrm{k}}\end{aligned}$$ In unit-vector notation, find (a) \(\vec{a}+\vec{b}\), (b) \(\vec{a}-\vec{b}\), and \((\mathrm{c})\) a third vector \(\vec{c}\) such that \(\vec{a}-\vec{b}+\vec{c}=0\)

Short Answer

Expert verified
(a) \(\vec{a} + \vec{b} = (3.0 \hat{\imath}, -2.0 \hat{\jmath}, 5.0 \hat{k})\); (b) \(\vec{a} - \vec{b} = (5.0 \hat{\imath}, -4.0 \hat{\jmath}, -3.0 \hat{k})\); (c) \(\vec{c} = (-5.0 \hat{\imath}, 4.0 \hat{\jmath}, 3.0 \hat{k})\)."

Step by step solution

01

Calculate \(\vec{a} + \vec{b}\)

To find \(\vec{a} + \vec{b}\), add the corresponding components of vectors \(\vec{a}\) and \(\vec{b}\). The \(i\), \(j\), and \(k\) components are added separately:\[\vec{a} + \vec{b} = (4.0 \hat{\imath} - 3.0 \hat{\jmath} + 1.0 \hat{k}) + ((-1.0) \hat{\imath} + 1.0 \hat{\jmath} + 4.0 \hat{k})\]Simplifying each component:- For \(\hat{\imath}\): \(4.0 + (-1.0) = 3.0\)- For \(\hat{\jmath}\): \(-3.0 + 1.0 = -2.0\)- For \(\hat{k}\): \(1.0 + 4.0 = 5.0\)Thus, \(\vec{a} + \vec{b} = (3.0 \hat{\imath} - 2.0 \hat{\jmath} + 5.0 \hat{k})\).
02

Calculate \(\vec{a} - \vec{b}\)

To find \(\vec{a} - \vec{b}\), subtract the corresponding components of vectors \(\vec{a}\) and \(\vec{b}\). The \(i\), \(j\), and \(k\) components are subtracted separately:\[\vec{a} - \vec{b} = (4.0 \hat{\imath} - 3.0 \hat{\jmath} + 1.0 \hat{k}) - ((-1.0) \hat{\imath} + 1.0 \hat{\jmath} + 4.0 \hat{k})\]Simplifying each component:- For \(\hat{\imath}\): \(4.0 - (-1.0) = 5.0\)- For \(\hat{\jmath}\): \(-3.0 - 1.0 = -4.0\)- For \(\hat{k}\): \(1.0 - 4.0 = -3.0\)Thus, \(\vec{a} - \vec{b} = (5.0 \hat{\imath} - 4.0 \hat{\jmath} - 3.0 \hat{k})\).
03

Find \(\vec{c}\) such that \(\vec{a} - \vec{b} + \vec{c} = 0\)

For the equation to hold, \(\vec{a} - \vec{b} + \vec{c} = 0\), the vector \(\vec{c}\) must be the negative of \(\vec{a} - \vec{b}\):\[\vec{c} = - (\vec{a} - \vec{b}) = - (5.0 \hat{\imath} - 4.0 \hat{\jmath} - 3.0 \hat{k})\]Negating each component:- For \(\hat{\imath}\): \(-5.0\)- For \(\hat{\jmath}\): \(4.0\)- For \(\hat{k}\): \(3.0\)Thus, \(\vec{c} = (-5.0 \hat{\imath} + 4.0 \hat{\jmath} + 3.0 \hat{k})\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Vector
A unit vector is a vector with a magnitude of one. It is used to denote direction. When we consider a vector in 3D space, it generally has three components: \( \hat{\mathbf{i}}, \hat{\mathbf{j}}, \text{and} \hat{\mathbf{k}} \).

Unit vectors are often written in the form \( \hat{\mathbf{v}} = \frac{\mathbf{v}}{\|\mathbf{v}\|} \), where \( \|\mathbf{v}\| \) is the magnitude of vector \( \mathbf{v} \).

This equation normalizes the given vector to a unit length, thus maintaining the direction but reducing the vector's magnitude to exactly one.
  • The unit vector in the direction of the x-axis is represented by \( \hat{\mathbf{i}} \).
  • Similarly, \( \hat{\mathbf{j}} \) and \( \hat{\mathbf{k}} \) point in the direction of the y-axis and z-axis, respectively.
These vectors are crucial in not just expressing vectors in component form, but also in simplifying mathematical problems related to direction and magnitude in physics and engineering.
Vector Subtraction
Vector subtraction involves finding the difference between two vectors by subtracting their corresponding components. In 3D space, vectors have \( \hat{\mathbf{i}}, \hat{\mathbf{j}}, \text{and} \hat{\mathbf{k}} \) components.

To subtract one vector from another, simply subtract each of the corresponding components: the \( \hat{\mathbf{i}} \) component from the \( \hat{\mathbf{i}} \) component, the \( \hat{\mathbf{j}} \) from the \( \hat{\mathbf{j}} \), and the \( \hat{\mathbf{k}} \) from the \( \hat{\mathbf{k}} \).
  • For example, if vector \( \mathbf{a} = a_1 \hat{\mathbf{i}} + a_2 \hat{\mathbf{j}} + a_3 \hat{\mathbf{k}} \) and vector \( \mathbf{b} = b_1 \hat{\mathbf{i}} + b_2 \hat{\mathbf{j}} + b_3 \hat{\mathbf{k}} \), the subtraction \( \mathbf{a} - \mathbf{b} \) will be \( (a_1 - b_1) \hat{\mathbf{i}} + (a_2 - b_2) \hat{\mathbf{j}} + (a_3 - b_3) \hat{\mathbf{k}} \).
Vector subtraction is extremely useful in physics to find relative displacement, velocity, or when calculating forces.
3D Vectors
Vectors in three-dimensional (3D) space are essential for representing quantities that have both magnitude and direction.

These vectors have three components often aligned with the x, y, and z axes, represented by \( \hat{\mathbf{i}} \), \( \hat{\mathbf{j}} \), and \( \hat{\mathbf{k}} \). Each component signifies the projection of the vector along the respective axis.
  • The general form of a 3D vector is \( \mathbf{v} = v_x \hat{\mathbf{i}} + v_y \hat{\mathbf{j}} + v_z \hat{\mathbf{k}} \), where \( v_x \), \( v_y \), and \( v_z \) denote scalar quantities.
  • 3D vectors can represent various physical concepts, such as velocity, acceleration, and force in space.
Understanding 3D vectors is crucial for solving problems involving spatial considerations and is widely used in fields like physics, computer graphics, and engineering.

The ability to manipulate these vectors using addition, subtraction, and scalar multiplication allows one to solve complex real-world challenges effectively.

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Most popular questions from this chapter

If \(\vec{a}-\vec{b}=2 \vec{c}, \vec{a}+\vec{b}=4 \vec{c}\), and \(\vec{c}=3 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}\), then what are (a) \(\vec{a}\) and \((\mathrm{b}) \vec{b} ?\)

Three vectors are given by \(\vec{a}=3.0 \hat{\mathrm{i}}+3.0 \hat{\mathrm{j}}-2.0 \hat{\mathrm{k}}\), \(\vec{b}=-1.0 \hat{\mathrm{i}}-4.0 \hat{\mathrm{j}}+2.0 \hat{\mathrm{k}}\), and \(\vec{c}=2.0 \hat{\mathrm{i}}+2.0 \hat{\mathrm{j}}+1.0 \hat{\mathrm{k}}\). Find (a) \(\vec{a} \cdot(\vec{b} \times \vec{c})\), (b) \(\vec{a} \cdot(\vec{b}+\vec{c})\), and \((\mathrm{c}) \vec{a} \times(\vec{b}+\vec{c})\)

For the following three vectors, what is \(3 \vec{C} \cdot(2 \vec{A} \times \vec{B}) ?\) $$\begin{aligned} &\vec{A}=2.00 \hat{\mathrm{i}}+3.00 \hat{\mathrm{j}}-4.00 \hat{\mathrm{k}} \\ &\vec{B}=-3.00 \hat{\mathrm{i}}+4.00 \hat{\mathrm{j}}+2.00 \hat{\mathrm{k}} \quad \vec{C}=7.00 \hat{\mathrm{i}}-8.00 \hat{\mathrm{j}}\end{aligned}$$

(a) In unit-vector notation, what is the sum \(\vec{a}+\vec{b}\) if \(\vec{a}=(4.0 \mathrm{~m}) \hat{\mathrm{i}}+(3.0 \mathrm{~m}) \hat{\mathrm{j}}\) and \(\vec{b}=(-13.0 \mathrm{~m}) \hat{\mathrm{i}}+(7.0 \mathrm{~m}) \hat{\mathrm{j}} ? \quad\) What are the (b) magnitude and (c) direction of \(\vec{a}+\vec{b}\) ?

Consider two displacements, one of magnitude \(3 \mathrm{~m}\) and another of magnitude \(4 \mathrm{~m}\). Show how the displacement vectors may be combined to get a resultant displacement of magnitude (a) \(7 \mathrm{~m}\), (b) \(1 \mathrm{~m}\), and (c) \(5 \mathrm{~m}\).

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