Chapter 3: Problem 47
Vector \(\vec{a}\) has a magnitude of \(5.0 \mathrm{~m}\) and is directed east. Vector \(\vec{b}\) has a magnitude of \(4.0 \mathrm{~m}\) and is directed \(35^{\circ}\) west of due north. What are (a) the magnitude and (b) the direction of \(\vec{a}+\vec{b}\) ? What are (c) the magnitude and (d) the direction of \(\vec{b}-\vec{a} ?\) (e) Draw a vector diagram for each combination.
Short Answer
Step by step solution
Understanding vector components
Calculate vector components
Calculate \( \vec{a} + \vec{b} \) components
Magnitude of \( \vec{a} + \vec{b} \)
Direction of \( \vec{a} + \vec{b} \)
Calculate \( \vec{b} - \vec{a} \) components
Magnitude of \( \vec{b} - \vec{a} \)
Direction of \( \vec{b} - \vec{a} \)
Draw vector diagrams
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Addition
For example, consider vectors \( \vec{a} \) and \( \vec{b} \). If vector \( \vec{a} \) is directed east with components \( (a_x, a_y) \) and vector \( \vec{b} \) is inclined at an angle, transforming it into components \( (b_x, b_y) \), their sum is given by:
- \((\vec{a} + \vec{b})_x = a_x + b_x\)
- \((\vec{a} + \vec{b})_y = a_y + b_y\)
This creates a new vector whose direction and magnitude we calculate using trigonometry. The graphical method often visualizes this as 'tip-to-tail' where the tail of one vector connects to the tip of another.
Vector Subtraction
Take vectors \( \vec{b} \) and \( \vec{a} \), the subtraction \( \vec{b} - \vec{a} \) first requires you to reverse \( \vec{a} \) (changing all its components signs), and then add:
- \((\vec{b} - \vec{a})_x = b_x - a_x\)
- \((\vec{b} - \vec{a})_y = b_y - a_y\)
Magnitude and Direction
\[ |\vec{v}| = \sqrt{x^2 + y^2} \]
The direction is an angle that indicates where the vector points. Calculated as the angle \( \theta \) from a reference direction, often the positive x-axis, the expression is:
- \( \theta = \tan^{-1}\left(\frac{y}{x}\right)\)
Trigonometry in Physics
When a vector \( \vec{b} \) has a magnitude and an angle \( \theta \) to a reference axis, its components are:
- \( b_x = b \cos(\theta) \)
- \( b_y = b \sin(\theta) \)
Such trigonometric practice enables concise solutions in physics problems, including calculating forces, displacements, and various physical phenomena.