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a charge of \(6.0 \mu \mathrm{C}\) is to be split into two parts that are then separated by \(3.0 \mathrm{~mm}\). What is the maximum possible magnitude of the electrostatic force between those two parts?

Short Answer

Expert verified
The maximum force is 9 N.

Step by step solution

01

Understand Coulomb's Law

Coulomb's Law calculates the electrostatic force between two charges. It is given by the equation \( F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \), where \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the separation distance.
02

Define the Charges

Since the total initial charge is \( 6.0 \mu C \), we define the two parts as \( q_1 = x \cdot 10^{-6} \) and \( q_2 = (6-x) \cdot 10^{-6} \), where \( x \) is the charge of one part in microcoulombs.
03

Write the Force Equation

Substitute the defined charges into the force equation to get \( F = \frac{k \cdot x \cdot (6-x) \cdot 10^{-12}}{r^2} \). Here, \( r = 3 \times 10^{-3} \) m and \( k = 8.99 \times 10^9 \) N·m²/C².
04

Simplify the Force Formula

Plug in the values for \( k \) and \( r \) to simplify: \( F = \frac{8.99 \times 10^9 \cdot x \cdot (6-x) \cdot 10^{-12}}{(3 \times 10^{-3})^2} \). Simplifying further gives \( F = 1 \times 10^6 \cdot x \cdot (6-x) \).
05

Find the Maximum Force

Since \( F \) is quadratic in the form \( ax(b-x) \), the maximum occurs at \( x = b/2 \). Thus, the charges should be \( 3 \mu C \) each for maximum force.
06

Calculate Maximum Force

Substitute \( x = 3 \) into the simplified force equation: \( F = 1 \times 10^6 \cdot 3 \cdot (6-3) = 9 \times 10^6 \) Newtons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is central to understanding how charged particles interact. It calculates the electrostatic force (F) acting between two point charges. According to Coulomb's Law, this force is directly proportional to the product of the magnitudes of the two charges and inversely proportional to the square of the distance between them. The mathematical formula is:\[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \]where:
  • \( k \) is Coulomb’s constant (~8.99 x 10^9 N·m²/C²)
  • \( q_1 \) and \( q_2 \) are the charges
  • \( r \) is the distance separating the charges
This law helps predict how strong or weak the force will be based on how large the charges are and how far apart they are. It's a fundamental concept that helps in solving many physics problems, involving charge interactions.
Charge Distribution
Charge distribution refers to how electric charges are arranged or divided. In the exercise, we split a single charge of 6.0 μC into two separate parts.
  • The total initial charge is 6.0 μC.
  • We can express the two charges as \( q_1 = x \cdot 10^{-6} \) and \( q_2 = (6-x) \cdot 10^{-6} \), where \( x \) is a variable representing the charge of one part in microcoulombs.
This step is crucial because it allows us to model how changing the distribution affects the electrostatic force between the two charges.Understanding charge distribution is key for optimizing forces and understanding behavior in systems where charges influence each other.
Optimization in Physics
Optimization in physics involves finding the most efficient, effective, or largest/minimum value of a physical quantity. In the problem, we aim to maximize the electrostatic force between two charges by choosing the optimal distribution.The force equation simplifies to a quadratic function: \[ F = 1 \times 10^6 \cdot x \cdot (6-x) \]To find the maximum F, we use the property of quadratic functions. The maximum value of a function \( ax(b-x) \) occurs at \( x = b/2 \). Here, \( b = 6 \), so the optimal value for each charge \( x \) is 3 μC.This optimization helps achieve maximum interaction strength. It serves as an example of how mathematical approaches can solve real-world physics problems effectively.
Quadratic Functions in Physics
Quadratic functions frequently appear in physics due to their natural occurrence in various phenomena. In optics, projectile motion, and energy systems, quadratic equations often model real-world behavior.In our example, the force equation can be written as:\[ F = 1 \times 10^6 \cdot x \cdot (6-x) \].This function describes how the electrostatic force varies with different charge distributions \( x \). The graph of a quadratic equation is a parabola, which can open upwards or downwards. When optimizing, it's crucial to determine whether you're seeking maxima or minima.In this context, we focus on maximizing force. Understanding quadratic relationships in physics provides insight into optimizing systems and predicting outcomes, especially when dealing with forces and energy problems.

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Most popular questions from this chapter

A \(100 \mathrm{~W}\) lamp has a steady current of \(0.83 \mathrm{~A}\) in its filament. How long is required for 1 mol of electrons to pass through the lamp?

The charges and coordinates of two charged particles held fixed in an \(x y\) plane are \(q_{1}=+3.0 \mu \mathrm{C}, x_{1}=3.5 \mathrm{~cm}, y_{1}=0.50 \mathrm{~cm}\), and \(q_{2}=-4.0 \mu \mathrm{C}, x_{2}=-2.0 \mathrm{~cm}, y_{2}=1.5 \mathrm{~cm}\). Find the (a) magni- tude and (b) direction of the electrostatic force on particle 2 due to particle 1 . At what (c) \(x\) and (d) \(y\) coordinates should a third particle of charge \(q_{3}=+4.0 \mu \mathrm{C}\) be placed such that the net electrostatic force on particle 2 due to particles 1 and 3 is zero?

We know that the negative charge on the electron and the positive charge on the proton are equal. Suppose, however, that these magnitudes differ from each other by \(0.00010 \%\). With what force would two copper coins, placed \(1.0 \mathrm{~m}\) apart, repel each other? Assume that each coin contains \(3 \times 10^{22}\) copper atoms. (Hint: \(\mathrm{A}\) neutral copper atom contains 29 protons and 29 electrons.) What do you conclude?

Of the charge \(Q\) initially on a tiny sphere, a portion \(q\) is to be transferred to a second, nearby sphere. Both spheres can be treated as particles and are fixed with a certain separation. For what value of \(q / Q\) will the electrostatic force between the two spheres be maximized?

If a cat repeatedly rubs against your cotton slacks on a dry day, the charge transfer between the cat hair and the cotton can leave you with an excess charge of \(-2.00 \mu \mathrm{C}\). (a) How many electrons are transferred between you and the cat? You will gradually discharge via the floor, but if instead of waiting, you immediately reach toward a faucet, a painful spark can suddenly appear as your fingers near the faucet. (b) In that spark, do electrons flow from you to the faucet or vice versa? (c) Just before the spark appears, do you induce positive or negative charge in the faucet? (d) If, instead, the cat reaches a paw toward the faucet, which way do electrons flow in the resulting spark? (e) If you stroke a cat with a bare hand on a dry day, you should take care not to bring your fingers near the cat's nose or you will hurt it with a spark. Considering that cat hair is an insulator, explain how the spark can appear.

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