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What must be the distance between point charge \(q_{1}=\) \(26.0 \mu \mathrm{C}\) and point charge \(q_{2}=-47.0 \mu \mathrm{C}\) for the electrostatic force between them to have a magnitude of \(5.70 \mathrm{~N} ?\)

Short Answer

Expert verified
The required distance is approximately 0.0397 meters (39.7 mm).

Step by step solution

01

Identify the Relevant Formula

The electrostatic force between two point charges is determined by Coulomb's Law, which is given by the formula: \[ F = k \frac{|q_1 q_2|}{r^2} \]where \( F \) is the magnitude of the force, \( k \) is Coulomb's constant \((8.99 \times 10^9 \, \mathrm{N \cdot m^2/C^2})\), \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges.
02

Plug in Known Values

Substitute the known values into the formula:\[ 5.70 = 8.99 \times 10^9 \frac{|26.0 \times 10^{-6} \times (-47.0 \times 10^{-6})|}{r^2} \]Simplify the expression by calculating the product of the charges and taking the absolute value:\[ 5.70 = 8.99 \times 10^9 \frac{(26.0 \times 47.0) \times 10^{-12}}{r^2} \]
03

Simplify the Charge Product

Calculate \( 26.0 \times 47.0 \), which equals 1222. Thus, the force equation becomes:\[ 5.70 = 8.99 \times 10^9 \frac{1222 \times 10^{-12}}{r^2} \]
04

Solve for Distance \( r \)

Rearrange the formula to solve for \( r^2 \):\[ r^2 = \frac{8.99 \times 10^9 \times 1222 \times 10^{-12}}{5.70} \]Calculate the value on the right side and then find \( r \).\[ r^2 = \frac{8.99078 \times 10^{-3}}{5.70} \approx 1.576 \times 10^{-3} \]\[ r = \sqrt{1.576 \times 10^{-3}} \approx 0.0397 \text{ meters} \]
05

Conclusion

The calculation reveals that the distance \( r \) required for the specified force is approximately 0.0397 meters or 39.7 millimeters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrostatic Force
Electrostatic force is the force of attraction or repulsion that occurs between charged particles due to their electric charges. This force acts along the line joining the centers of the charges. It is an example of a non-contact force, which means that the charged objects do not need to touch each other to experience the force. The electrostatic force is described by Coulomb's Law, which provides a formula to calculate the magnitude of this force. The strength of the electrostatic force depends on:
  • the magnitudes of both charges involved,
  • the distance between the charges,
  • and the medium in which the charges are situated.
When like charges interact, they repel each other, whereas unlike charges attract each other. In practice, the electrostatic force plays a crucial role in many everyday phenomena and technologies, like how your socks stick to each other in the dryer or in the operation of capacitors in electronic circuits.
Point Charges
Point charges are an idealization used in electrostatics to simplify calculations. A point charge is a hypothetical charge with no physical size, considered to exist at a single point in space. This concept makes it easier to apply mathematical principles to determine forces and fields since it removes complexities associated with the actual shape and size of a charged object. In real-world problems, objects are not true point charges, but if they are small or far apart enough compared to the distances involved in the system, they can be approximated as point charges. This approximation allows us to use formulas like Coulomb's Law directly without worrying about the distribution of charge over an area. In the provided exercise, the point charges carry significant charges of 26.0 µC and -47.0 µC, meaning their interactions have considerable effects.
Distance Calculation
Distance calculation is crucial for determining the electrostatic force between point charges. According to Coulomb's Law, the force between two point charges is inversely proportional to the square of the distance separating them. This relation means that even small changes in distance can result in significant changes in force magnitude. In the exercise, we were given the force magnitude and the charges, and our task was to find the distance necessary to create such a force. By rearranging the formula: \[ r^2 = \frac{k \cdot |q_1 \cdot q_2|}{F} \]we isolated the distance variable, solved for \( r \), and calculated the exact distance the charges must be apart to experience the specified force of 5.70 N. Calculating this correctly involves first finding \( r^2 \) and then taking the square root to determine \( r \). This calculation emphasizes the powerful impact distance has in electrostatic interactions.
Coulomb's Constant
Coulomb's constant, denoted as \( k \), is a fundamental part of Coulomb's Law and is key to calculating electrostatic force. It quantifies the amount of force between two unit charges separated by a unit distance in a vacuum. The value of \( k \) is approximately \(8.99 \times 10^9 \, \mathrm{N \cdot m^2/C^2}\). This constant provides the necessary scaling factor to translate charge and distance into a force value, ensuring that the attractive or repulsive force is significant enough to be measured. Its high value reflects how strong electrostatic forces can be, even over relatively large distances. In calculations like the one in our exercise, the value of \( k \) allows us to convert the product of the charges and the distance squared into a tangible force value, making it an indispensable part of the formula. Its application highlights the inherent strength of electrostatic interactions compared to gravitational forces, for instance.

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Most popular questions from this chapter

How many megacoulombs of positive charge are in \(1.00 \mathrm{~mol}\) of neutral molecular-hydrogen gas \(\left(\mathrm{H}_{2}\right)\) ?

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