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A Carnot refrigerator extracts \(35.0 \mathrm{~kJ}\) as heat during each cycle, operating with a coefficient of performance of \(4.60\). What are (a) the energy per cycle transferred as heat to the room and (b) the work done per cycle?

Short Answer

Expert verified
(a) 42.61 kJ (b) 7.61 kJ

Step by step solution

01

Understanding Coefficient of Performance

The coefficient of performance (COP) for a refrigerator is given by the formula \( \text{COP} = \frac{Q_c}{W} \), where \( Q_c \) is the heat extracted from inside the refrigerator and \( W \) is the work done per cycle. In this case, the COP is 4.60.
02

Applying COP to find Work done (W)

Rearrange the formula to solve for \( W \): \( W = \frac{Q_c}{\text{COP}} \). Substitute \( Q_c = 35.0 \text{ kJ} \) and \( \text{COP} = 4.60 \) to get \( W = \frac{35.0}{4.60} \text{ kJ} = 7.61 \text{ kJ} \).
03

Calculating Heat Transferred to the Room (Q_h)

The energy per cycle transferred to the room as heat, \( Q_h \), is the sum of the heat extracted from inside and the work done: \( Q_h = Q_c + W \). Substitute \( Q_c = 35.0 \text{ kJ} \) and \( W = 7.61 \text{ kJ} \) to find \( Q_h = 35.0 + 7.61 \text{ kJ} = 42.61 \text{ kJ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Performance
The coefficient of performance (COP) is a key concept in understanding how efficient a refrigerator is. It measures the effectiveness of a refrigerator's energy consumption. The COP is defined as the ratio between the heat extracted (cooling effect) and the work input required to achieve that cooling, mathematically expressed as \( \text{COP} = \frac{Q_c}{W} \). Here, \( Q_c \) is the heat removed from the refrigerated space, while \( W \) is the work done by the refrigerator during a cycle.
The higher the COP, the more efficient the refrigeration process is, because it means more cooling is done per unit of work input. This is crucial when considering the overall energy management in any cooling system, such as a refrigerator or air conditioning unit.
Heat Transfer
Heat transfer in the context of a Carnot refrigerator refers to the movement of heat energy from the space being cooled to the surrounding environment. In our scenario, the heat extracted is \( 35.0 \text{ kJ} \) per cycle. This occurs because the refrigerant absorbs heat from the interior, effectively lowering the temperature.
However, energy conservation law implies that this extracted heat doesn't disappear. Instead, it is transferred to the surrounding area outside the refrigerator, known as \( Q_h \). The total energy transferred to the surroundings is the combination of the extracted heat and the work done: \( Q_h = Q_c + W \). This ensures that the refrigerator system complies with the first law of thermodynamics, emphasizing the energy conservation principle.
Thermodynamics
Thermodynamics is the study of energy, heat, and their transformations. In the refrigerator's operation, various thermodynamic principles come into play. It operates based on a cycle, often described by the Carnot cycle, which is an idealized thermodynamic cycle proposed by Nicolas Léonard Sadi Carnot.
The Carnot refrigerator operates between two thermal reservoirs: a cooler inside and a warmer outside environment. The efficiency of such a system is greatly dependent on these temperature differences and the specific design factors involved. Understanding thermodynamics principles and their applications helps in optimizing energy usage and enhancing the performance of devices like refrigerators.
Work Done
Work done in a refrigerator cycle pertains to the energy used by the refrigerator's compressor to remove heat from the inside of the refrigerator. This energy input is fundamental for understanding energy consumption patterns in refrigeration.
To find the work done per cycle, use the relationship derived from the COP: \( W = \frac{Q_c}{\text{COP}} \). In this specific example, substituting \( Q_c = 35.0 \text{ kJ} \) and \( \text{COP} = 4.60 \) into the formula gives us \( W = 7.61 \text{ kJ} \). This energy input is required each cycle to maintain the cooling function, making it a critical aspect of energy efficiency analysis.

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