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A motorcyclist who is moving along an \(x\) axis directed toward the east has an acceleration given by \(a=(6.1-1.2 t) \mathrm{m} / \mathrm{s}^{2}\) for \(0 \leq t \leq 6.0 \mathrm{~s}\). At \(t=0\), the velocity and position of the cyclist are \(2.7 \mathrm{~m} / \mathrm{s}\) and \(7.3 \mathrm{~m} .\) (a) What is the maximum speed achieved by the cyclist? (b) What total distance does the cyclist travel between \(t=0\) and \(6.0 \mathrm{~s} ?\)

Short Answer

Expert verified
(a) 17 m/s; (b) 53.96 m.

Step by step solution

01

Finding the Time when Velocity is Maximum

The velocity of the motorcyclist is maximum when the acceleration is zero, so set the given acceleration equation to zero: \( 6.1 - 1.2t = 0 \). Solve for \( t \): \( 1.2t = 6.1 \), which simplifies to \( t = \frac{6.1}{1.2} \approx 5.08 \text{ s} \).
02

Calculating the Velocity Function

Velocity is obtained by integrating the acceleration function \( a(t) = 6.1 - 1.2t \). Integrate to get \( v(t) = \int (6.1 - 1.2t) \, dt = 6.1t - 0.6t^2 + C \). Use the initial condition \( v(0) = 2.7 \) to solve for \( C \). So, \( 2.7 = 6.1(0) - 0.6(0)^2 + C \), therefore \( C = 2.7 \). Thus, the velocity function is \( v(t) = 6.1t - 0.6t^2 + 2.7 \).
03

Finding Maximum Velocity

Substitute \( t = 5.08 \text{ s} \) into the velocity function \( v(t) = 6.1t - 0.6t^2 + 2.7 \) to find the maximum velocity: \( v(5.08) = 6.1(5.08) - 0.6(5.08)^2 + 2.7 \). Simplifying gives \( v(5.08) \approx 17 \text{ m/s} \).
04

Computing the Position Function

Position is obtained by integrating the velocity function \( v(t) = 6.1t - 0.6t^2 + 2.7 \). Integrate to find \( x(t) = \int (6.1t - 0.6t^2 + 2.7) \, dt = 3.05t^2 - 0.2t^3 + 2.7t + C \). Use the initial condition \( x(0) = 7.3 \) to find \( C \). So, \( 7.3 = 3.05(0)^2 - 0.2(0)^3 + 2.7(0) + C \), thus \( C = 7.3 \). The position function is \( x(t) = 3.05t^2 - 0.2t^3 + 2.7t + 7.3 \).
05

Calculating Total Distance Traveled

Find the position at \( t=6 \) using \( x(t) = 3.05t^2 - 0.2t^3 + 2.7t + 7.3 \): \( x(6) = 3.05(6)^2 - 0.2(6)^3 + 2.7(6) + 7.3 \). Simplifying this gives \( x(6) \approx 61.26 \text{ m} \). The total distance traveled is \( x(6) - x(0) = 61.26 - 7.3 = 53.96 \text{ m} \).
06

Verify Interval Checks for Distance

Since the velocity function has no zeros between \( t=0 \) and \( t=6 \), the cyclist's motion is monotonic in that range, confirming no direction change. Thus, total distance is indeed \( 53.96 \text{ m} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration
Acceleration is a measure of how quickly the velocity of an object changes with time. In this exercise, the acceleration of the motorcyclist is expressed as a function of time: \( a(t) = 6.1 - 1.2t \). This equation shows that the acceleration decreases as time increases, because the negative \(-1.2t\) component reduces the acceleration over time.
It's important to understand that when acceleration is positive, it means that the velocity of the motorcyclist is increasing. Conversely, when acceleration is negative, the velocity is decreasing. At the moment when the acceleration becomes zero, the cyclist achieves their maximum velocity, since the velocity will no longer be increasing or decreasing.
Velocity
Velocity represents the speed of an object and the direction of its movement. In our problem, the velocity function is derived by integrating the given acceleration function. The formula is integrated to yield \( v(t) = 6.1t - 0.6t^2 + 2.7 \), where the term \(2.7\) is the initial velocity at \( t = 0 \).
This equation tells us that the motorcyclist's velocity is influenced by both time and the initial velocity. The presence of the \(-0.6t^2\) term implies that the velocity doesn't simply increase indefinitely. After a certain period, it begins to decrease, which is what happens after reaching maximum velocity.
  • Velocity is a vector, meaning it has both magnitude and direction.
  • In this scenario, the direction is towards the east.
Position
Position defines where an object is located along a specific axis at any given time. The position function, derived from integrating the velocity function, is given by \( x(t) = 3.05t^2 - 0.2t^3 + 2.7t + 7.3 \). Here, \(7.3\) reflects the initial position of the cyclist.
Understanding position involves recognizing how the accumulated velocity over time affects where the cyclist is on the \(x\) axis. By substituting the time variable \(t\) into the position equation, we can track the location of the cyclist along the axis at any particular moment.
  • Position is usually measured in meters.
  • It provides a reference point to describe an object's displacement.
Integration
Integration is a mathematical process that helps us find the accumulated change given a rate of change, such as the relationship between acceleration, velocity, and position. In kinematics, integrating an acceleration function gives us the velocity function, and further integrating the velocity function yields the position function.
During this exercise, we integrated the acceleration function \( a(t) = 6.1 - 1.2t \) to acquire the velocity function \( v(t) = 6.1t - 0.6t^2 + 2.7 \). Another integration step from the velocity function helped us find the position function \( x(t) = 3.05t^2 - 0.2t^3 + 2.7t + 7.3 \). Remember, in kinematics, integration is a crucial tool for linking initial conditions with the motion of objects.
  • Integration requires the consideration of initial conditions to solve for constants in the functions.
  • It can be visualized as the opposite operation of differentiation.
Motion along an axis
Motion along an axis refers to how an object moves in a straight line, either increasing or decreasing its position over time. In this exercise, the motion of the cyclist along the \( x \) axis encompasses all three of the primary kinematic equations through the use of the given functions for acceleration, velocity, and position.
Kinematics focuses on describing how the object moves without attributing its cause. Understanding motion along an axis requires analyzing the specific directions (positive or negative) and changes in velocity to establish a complete view of how the object travels along the axis over time.
  • Axis-based motion simplifies analysis by focusing on one-dimensional movement.
  • This type of motion is commonplace in physics problems, represented by simple linear paths.

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