Chapter 2: Problem 26
A muon (an elementary particle) enters a region with a speed of \(5.00 \times 10^{6} \mathrm{~m} / \mathrm{s}\) and then is slowed at the rate of \(1.25 \times 10^{14} \mathrm{~m} / \mathrm{s}^{2}\). (a) How far does the muon take to stop? (b) Graph \(x\) versus \(t\) and \(v\) versus \(t\) for the muon.
Short Answer
Step by step solution
Identify Known Values
Determine Final Velocity
Apply the Kinematic Equation
Solve for Distance
Graph Position versus Time
Graph Velocity versus Time
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Deceleration
Elementary Particles
Kinematic Equations
Graphing Motion
- Position versus Time: This graph helps visualize how far the muon travels over time. Initially, the position increases, reflecting the muon's movement. As the muon decelerates, the rate of change of position decreases until it stops, showing a plateau.
- Velocity versus Time: This graph depicts how the muon's speed changes due to deceleration. Starting at a high velocity, the graph shows a linear decrease to zero, indicating steady deceleration. The slope of the graph equals the deceleration rate (\(-1.25 \times 10^{14}\, \text{m/s}^2\)).