Chapter 19: Problem 7
Suppose \(1.80 \mathrm{~mol}\) of an ideal gas is taken from a volume of \(3.00 \mathrm{~m}^{3}\) to a volume of \(1.50 \mathrm{~m}^{3}\) via an isothermal compression at \(30^{\circ} \mathrm{C} .\) (a) How much energy is transferred as heat during the compression, and (b) is the transfer to or from the gas?
Short Answer
Step by step solution
Identify the Type of Process
Apply the First Law of Thermodynamics
Calculate the Work Done
Conduct the Calculation
Determine Heat Transfer Direction
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas
Because real gases behave almost ideally at high temperatures and low pressures, the ideal gas law is a useful approximation. This law is usually expressed as:
- PV = nRT
- **V** is the volume
- **n** is the number of moles of the gas
- **R** is the ideal gas constant
- **T** is the absolute temperature measured in Kelvin.
In the exercise, 1.80 mols of an ideal gas is compressed, allowing us to assume that its behavior can be described using these principles effectively. This approximation helps us simplify and solve thermodynamic problems efficiently.
Isothermal Process
- The internal energy of an ideal gas depends solely on its temperature.
- For an isothermal process, this means the internal energy does not change.
- **V_f** is the final volume
- **V_i** is the initial volume.
In the example, this understanding helps determine how much energy is exchanged between the system and its surroundings, leading to calculations of heat transfer.
First Law of Thermodynamics
- \( \Delta U = Q - W \)
- \( Q = -3143.5 \) J, indicating heat of this amount was released from the gas into its surroundings.