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Gold has a molar mass of \(197 \mathrm{~g} / \mathrm{mol}\). (a) How many moles of gold are in a \(2.50 \mathrm{~g}\) sample of pure gold? (b) How many atoms are in the sample?

Short Answer

Expert verified
(a) 0.0127 moles; (b) approximately 7.65 x 10^21 atoms.

Step by step solution

01

Identify Given Values

The problem gives us the molar mass of gold as \(197 \mathrm{~g/mol}\) and the mass of the gold sample as \(2.50 \mathrm{~g}\). We need to use these values to find the required number of moles.
02

Formula for Moles

To find the number of moles, we use the formula:\[\text{Number of moles} = \frac{\text{mass of sample}}{\text{molar mass}}\]where the mass of the sample is \(2.50 \mathrm{~g}\) and the molar mass is \(197 \mathrm{~g/mol}\).
03

Calculate Moles of Gold

Substitute the known values into the formula:\[\text{Number of moles} = \frac{2.50 \mathrm{~g}}{197 \mathrm{~g/mol}} = 0.0127 \text{ moles}\]
04

Use Avogadro's Number to Find Atoms

To find the number of atoms, we use Avogadro's number, which is \(6.022 \times 10^{23} \text{ atoms/mol}\). Multiply the number of moles by Avogadro's number:\[\text{Number of atoms} = 0.0127 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol}\]
05

Calculate Number of Atoms

Perform the multiplication:\[\text{Number of atoms} = 0.0127 \times 6.022 \times 10^{23} \approx 7.65 \times 10^{21} \text{ atoms}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Moles in Chemistry
Moles are a fundamental concept in chemistry, acting as a bridge between the microscopic world of atoms and molecules and the macroscopic quantities we can measure in labs. A mole is a unit that chemists use to quantify the amount of substance. It allows scientists to count out a specific number of particles, be it atoms, ions, or molecules.

One mole is defined as the amount of substance containing the same number of entities (atoms, molecules, ions, etc.) as there are in exactly 12 grams of carbon-12. This number happens to be a very large quantity: approximately 6.022 x 10^23 entities. This number is essential when performing molar mass calculations, as it sets a standard and ensures consistency across different substances.

To calculate the number of moles in a given sample, you need the mass of the substance and its molar mass (the mass of one mole of a substance, typically measured in grams per mole). Using the formula \( \text{Number of moles} = \frac{\text{mass of sample}}{\text{molar mass}} \), you can determine how many moles your sample contains. This calculation is crucial in converting between the mass of a substance and the number of moles, which in turn connects directly to Avogadro's number.
Exploring Avogadro's Number
Avogadro's number is one of the cornerstones of chemistry, providing a link between the macroscopic and microscopic worlds. It is defined as the number of atoms, ions, or molecules in one mole of a substance, and is valued at 6.022 x 10^23. This immense number can seem abstract at first, but it's incredibly practical in allowing chemists to work with quantities at the human scale without getting bogged down in tiny numbers.

When converting between moles and individual particles, Avogadro's number serves as the scaling factor. For instance, if you have a certain number of moles of a substance, multiplying this by Avogadro's number will yield the number of atoms, molecules, or ions present. For example, in the calculation \( 0.0127 \text{ moles of gold} \times 6.022 \times 10^{23} \text{ atoms/mol} \), you convert the number of moles into atoms. Thus, you end up with approximately 7.65 x 10^21 atoms of gold.

In every aspect of chemistry that involves measurement, quantification, or conversion between unit scales, Avogadro's number is a central figure. It simplifies the mathematics involved in transitioning between different scales of matter, ensuring accuracy and consistency in scientific calculations.
Navigating Atomic Calculations
Atomic calculations are central to many areas of chemistry, particularly those relating to the composition and changes in matter. These calculations often begin by understanding the molar mass of elements from the periodic table, which is usually expressed as grams per mole. The molar mass ties into atomic weights but applies a universal scale usable in real-world applications, allowing chemists to calculate the mass of atoms in a large batch "in bulk".

In contexts where you must determine the number of atoms in a sample, such as in a piece of gold weighing 2.50 grams, these calculations become invaluable. Start by using the formula \( \text{Number of moles} = \frac{\text{mass of sample}}{\text{molar mass}} \), as seen in the original solution. These moles then need to be converted to actual numbers of atoms through multiplication by Avogadro's number, which acts as your conversion factor from moles (the amount of substance) to atoms (individual particles).

Atomic calculations are the bedrock of many chemical experiments and industrial processes, ensuring that precise amounts of substances react to yield desired products. They are crucial for chemists in laboratory settings for formulating reactions and predicting outcomes with high accuracy.

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Most popular questions from this chapter

A sample of ideal gas expands from an initial pressure and volume of \(32 \mathrm{~atm}\) and \(1.0 \mathrm{~L}\) to a final volume of \(4.0 \mathrm{~L}\). The initial temperature is \(300 \mathrm{~K}\). If the gas is monatomic and the expansion isothermal, what are the (a) final pressure \(p_{f}\), (b) final temperature \(T_{f}\), and \((\mathrm{c})\) work \(W\) done by the gas? If the gas is monatomic and the expansion adiabatic, what are (d) \(p_{f}\), (e) \(T_{f}\), and (f) \(W ?\) If the gas is diatomic and the expansion adiabatic, what are (g) \(p_{f}\), (h) \(T_{f}\), and (i) \(W\) ?

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