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The area \(A\) of a rectangular plate is \(a b=1.4 \mathrm{~m}^{2} .\) Its coefficient of linear expansion is \(\alpha=32 \times 10^{-6} / \mathrm{C}^{\circ} .\) After a temperature rise \(\Delta T=89^{\circ} \mathrm{C}\), side \(a\) is longer by \(\Delta a\) and side \(b\) is longer by \(\Delta b\) (Fig. 18-61). Neglecting the small quantity \((\Delta a \Delta b) / a b\), find \(\Delta A\).

Short Answer

Expert verified
The change in area \( \Delta A \) is approximately 0.008 m².

Step by step solution

01

Understand Thermal Expansion

The thermal expansion of a material when the temperature changes can be determined by the coefficient of linear expansion. For a rectangular plate, each side expands linearly by \( \Delta L = \alpha L \Delta T \), where \( L \) is the original length of the side.
02

Calculate the Change in Each Side

Determine \( \Delta a \) and \( \Delta b \), the changes in lengths of sides \( a \) and \( b \), respectively. Use the formula \( \Delta a = \alpha a \Delta T \) and \( \Delta b = \alpha b \Delta T \).
03

Express the New Area of the Plate

The new area \( A' \) of the plate can be expressed as \((a + \Delta a)(b + \Delta b) \). By expanding this, we find \( A' = ab + a \Delta b + b \Delta a + \Delta a\Delta b \).
04

Simplify the Expression for the Change in Area

The change in area \( \Delta A \) is given by \( \Delta A = A' - A \). From Step 3, this becomes \( \Delta A = a \Delta b + b \Delta a + \Delta a \Delta b \). Since \( \Delta a \Delta b / ab\) is a small quantity, it is neglected, simplifying to \( \Delta A = a \Delta b + b \Delta a \).
05

Substitute Known Values

Substitute \( a b = 1.4 \), \( \alpha = 32 \times 10^{-6} \), and \( \Delta T = 89 \) into the equation from Step 4: \( \Delta A = (b \alpha a \Delta T) + (a \alpha b \Delta T) = 2 ab \alpha \Delta T \).
06

Calculate \( \Delta A \)

Calculate \( \Delta A \) using the simplified formula \( \Delta A = 2 ab \alpha \Delta T = 2 \times 1.4 \times 32 \times 10^{-6} \times 89 \). The result is \( \Delta A = 0.0079872 \; m^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Linear Expansion
When materials are heated, they expand, and when cooled, they contract. This physical reaction is described by the *coefficient of linear expansion*, denoted as \(\alpha\). The value of \(\alpha\) quantifies how much a material's length changes in response to a temperature change (\(\Delta T\)).
The formula used is:\[ \Delta L = \alpha L \Delta T \]Here, \(\Delta L\) is the change in length, \(L\) is the original length, and \(\Delta T\) is the change in temperature.
Examples of everyday applications include:
  • Expansion joints in bridges
  • Snug fits in machinery where temperature changes are expected
This concept is crucial in designing and evaluating materials that experience temperature fluctuations.
Rectangular Plate
Understanding the geometric properties of a **rectangular plate** is essential when studying thermal expansion effects. A rectangular plate, characterized by its length (a) and width (b), forms a simple basis for calculating area changes due to thermal expansion.
When subjected to a temperature increase, each side of the rectangle- \(a\) and \(b\), - expands by \(\Delta a\) and \(\Delta b\) respectively.
This expansion, together with temperature change, affects the overall size and area. By applying the thermal expansion formula to each side, we can predict how much larger the plate will be under different temperature scenarios.
Change in Area
The concept of **Change in Area** is pivotal when considering how thermal expansion affects objects like a rectangular plate. After each side, i.e., length \(a\) and width \(b\), expands by \(\Delta a\) and \(\Delta b\), the new area \(A'\) of the plate increases. The new area is calculated as:\[ A' = (a + \Delta a)(b + \Delta b) \]This equation expands to- \(A' = ab + a \Delta b + b \Delta a + \Delta a \Delta b\).- Here, \(ab\) is the original area, - while the other terms represent additional area due to side extensions.
To make calculations simpler in scenarios where\(\Delta a \Delta b\) is very small, we typically neglect it, resulting in- a simplified version for the change in area:\[ \Delta A = a \Delta b + b \Delta a \]
Temperature Change Effects
**Temperature Change Effects** stretch beyond simple linear expansion and involve understanding how materials react when temperature fluctuates. The thermal expansion of an object depends on:
  • The object's original dimensions
  • It's coefficient of linear expansion \(\alpha\)
  • The degree of temperature change \(\Delta T\)
In our rectangular plate example, after a temperature increase of \(\Delta T = 89\, ^{\circ}\text{C}\), significant yet predictable changes in area can be calculated.
In general, the temperature change effects play a crucial role in:
  • Material choice for engineering projects, where dimensional stability is key
  • Weather-dependent applications
Hence, understanding how temperature affects size and stability can guide choices in design and material selection.

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Most popular questions from this chapter

Calculate the specific heat of a metal from the following data. A container made of the metal has a mass of \(3.6 \mathrm{~kg}\) and contains \(14 \mathrm{~kg}\) of water. A \(1.8 \mathrm{~kg}\) piece of the metal initially at a temperature of \(180^{\circ} \mathrm{C}\) is dropped into the water. The container and water initially have a temperature of \(16.0^{\circ} \mathrm{C}\), and the final temperature of the entire (insulated) system is \(18.0^{\circ} \mathrm{C}\).

(a) Two \(50 \mathrm{~g}\) ice cubes are dropped into \(200 \mathrm{~g}\) of water in a thermally insulated container. If the water is initially at \(25^{\circ} \mathrm{C}\), and the ice comes directly from a freezer at \(-15^{\circ} \mathrm{C}\), what is the final temperature at thermal equilibrium? (b) What is the final temperature if only one ice cube is used?

Suppose the temperature of a gas is \(373.15 \mathrm{~K}\) when it is at the boiling point of water. What then is the limiting value of the ratio of the pressure of the gas at that boiling point to its pressure at the triple point of water? (Assume the volume of the gas is the same at both temperatures.)

On a linear \(X\) temperature scale, water freezes at \(-125.0^{\circ} \mathrm{X}\) and boils at \(375.0^{\circ} \mathrm{X}\). On a linear \(\mathrm{Y}\) temperature scale, water freezes at \(-70.00^{\circ} \mathrm{Y}\) and boils at \(-30.00^{\circ} \mathrm{Y}\). A temperature of \(50.00^{\circ} \mathrm{Y}\) corresponds to what temperature on the \(X\) scale?

An insulated Thermos contains \(130 \mathrm{~cm}^{3}\) of hot coffee at \(80.0^{\circ} \mathrm{C}\). You put in a \(12.0 \mathrm{~g}\) ice cube at its melting point to cool the coffee. By how many degrees has your coffee cooled once the ice has melted and equilibrium is reached? Treat the coffee as though it were pure water and neglect energy exchanges with the environment.

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