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A certain sound source is increased in sound level by \(30.0 \mathrm{~dB}\). By what multiple is (a) its intensity increased and (b) its pressure amplitude increased?

Short Answer

Expert verified
(a) Intensity increases by a factor of 1000. (b) Pressure amplitude increases by a factor of approximately 31.62.

Step by step solution

01

Understanding Decibel Increase

The sound level increase is given as 30 dB. The formula for sound level in decibels is \( L = 10 \log_{10}(\frac{I}{I_0}) \), where \( I \) is the intensity and \( I_0 \) is the reference intensity. An increase of 30 dB means \( L = 10 \log_{10}(\frac{I}{I_0}) + 30 \). This implies \( 10 \log_{10}(\frac{I'}{I_0}) = 10 \log_{10}(\frac{I}{I_0}) + 30 \).
02

Simplifying the Intensity Equation

The equation \( 10 \log_{10}(\frac{I'}{I_0}) = 10 \log_{10}(\frac{I}{I_0}) + 30 \) can be simplified to \( \log_{10}(\frac{I'}{I_0}) = \log_{10}(\frac{I}{I_0}) + 3 \) (by dividing both sides by 10). Therefore, \( \log_{10}(\frac{I'}{I}) = 3 \).
03

Solving for Intensity Multiple

To find the intensity multiple, we use \( \log_{10}(\frac{I'}{I}) = 3 \). This implies \( \frac{I'}{I} = 10^3 \). Therefore, the intensity is increased by a factor of 1000.
04

Understanding Pressure Amplitude Relationship

The intensity \( I \) is proportional to the square of the pressure amplitude \( P \). Therefore, \( I \propto P^2 \). When the intensity increases by a factor, the pressure amplitude increases by the square root of that factor.
05

Calculating Pressure Amplitude Increase

Since the intensity increases by a factor of 1000, the pressure amplitude increases by \( \sqrt{1000} \). Calculating \( \sqrt{1000} \) gives approximately 31.62. Thus, the pressure amplitude is increased by a factor of approximately 31.62.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Intensity
Sound intensity is a measure of how much sound energy passes through a certain area in a set period of time. It is usually expressed in watts per square meter \(\left( \text{W/m}^2 \right)\). When we talk about sound intensity, we are referring to the power carried by sound waves per unit area in a direction perpendicular to the surface.
Sound intensity plays a crucial role in how we perceive loudness, but it's important to note that different people may perceive sound levels differently even if the intensity is the same.
A common reference point for measuring sound intensity is the threshold of hearing, which is the quietest sound a typical human ear can detect. Understanding this concept helps us to decode the increase of sound level using decibels, which is a logarithmic unit used to describe the ratio of intensity levels.
Pressure Amplitude
Pressure amplitude refers to the maximum deviation of pressure in a sound wave from the ambient air pressure. In simpler terms, it's the loudest point in the wave cycle. The relationship between intensity and pressure amplitude is crucial; intensity is proportional to the square of the pressure amplitude.
This means that if you increase the pressure amplitude, the intensity of the sound increases at a much higher rate.
For example, if the intensity increases by a certain factor, the pressure amplitude increases by the square root of that factor. To put it in context, if you have an intensity increase by a factor of 1000, like in the exercise, the pressure amplitude increases by the square root of 1000, which is approximately 31.62.
Understanding this relationship helps greatly in various applications, such as music production and speaker design, where maintaining the balance between intensity and clarity is key.
Sound Level Formula
The sound level formula provides a way to express the relative loudness of a sound in a unit called decibels (dB). The formula commonly used is \[L = 10 \log_{10}\left(\frac{I}{I_0}\right)\]where:
  • \(L\) is the sound level in decibels,
  • \(I\) is the sound intensity, and
  • \(I_0\) is the reference intensity, often defined as \(1 \times 10^{-12} \text{W/m}^2\), the threshold of hearing.
This logarithmic equation shows how sound levels increase with intensity. For instance, an increase of 10 dB means the sound intensity has increased by a factor of 10.
In the context of the exercise, an increase of 30 dB corresponds to increasing the original intensity by a factor of 1000, which is significant.
This logarithmic nature of the formula allows for a wide range of sound intensities to be conveniently expressed in a smaller numerical range, helping us understand changes in sound clearly and succinctly.
Logarithmic Scale
A logarithmic scale is a nonlinear scale used for a large range of quantities. In the context of sound, it is used to compute decibels, which can handle the vast range of human hearing.
Human ears can detect sounds from extremely soft whispers to loud explosions, spanning many orders of magnitude in terms of intensity.
The logarithmic scale separates these intensities into more manageable numbers. For example, every increase of 10 decibels represents a tenfold increase in sound intensity.
  • This means 10 dB is 10 times more intense than 0 dB, 20 dB is 100 times more intense, and so on.
  • Therefore, a 30 dB increase implies a thousandfold increase in sound intensity, which is exactly the situation presented in our exercise.
Using a logarithmic scale simplifies complex multiplications into easier additions and helps compare vastly different quantities without confusion.

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Most popular questions from this chapter

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