/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 A sinusoidal wave of frequency \... [FREE SOLUTION] | 91Ó°ÊÓ

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A sinusoidal wave of frequency \(500 \mathrm{~Hz}\) has a speed of \(350 \mathrm{~m} / \mathrm{s}\). (a) How far apart are two points that differ in phase by \(\pi / 3\) rad? (b) What is the phase difference between two displacements at a certain point at times \(1.00 \mathrm{~ms}\) apart?

Short Answer

Expert verified
(a) The points are 0.1167 m apart. (b) The phase difference is \( \pi \) rad.

Step by step solution

01

Calculate Wavelength

First, determine the wavelength of the wave using the formula \( \lambda = \frac{v}{f} \), where \( \lambda \) is the wavelength, \( v \) is the speed of the wave, and \( f \) is the frequency. Here, \( v = 350 \, \mathrm{m/s} \) and \( f = 500 \, \mathrm{Hz} \). \[ \lambda = \frac{350}{500} = 0.7 \, \mathrm{m} \]
02

Calculate Distance for Phase Difference (a)

To find the distance between two points with a phase difference of \( \frac{\pi}{3} \), use the formula for phase difference: \( \text{Phase difference} = \frac{2\pi}{\lambda} \times \Delta x \). Solve for \( \Delta x \) where the phase difference equals \( \frac{\pi}{3} \). Rearrange to find \( \Delta x \):\[ \Delta x = \frac{\lambda}{2\pi} \times \frac{\pi}{3} = \frac{0.7}{6} = 0.1167 \, \mathrm{m} \]
03

Calculate Angular Frequency

To determine the phase difference at a single point over time, calculate the angular frequency \( \omega \) using \( \omega = 2\pi f \). Here, \( f = 500 \, \mathrm{Hz} \).\[ \omega = 2\pi \times 500 = 1000\pi \approx 3141.59 \, \mathrm{rad/s} \]
04

Calculate Phase Difference Over Time (b)

The phase difference due to a time difference \( \Delta t \) is given by \( \Delta \phi = \omega \Delta t \). Here, \( \Delta t = 1.00 \, \mathrm{ms} = 1.00 \times 10^{-3} \, \mathrm{s} \).\[ \Delta \phi = 3141.59 \times 1.00 \times 10^{-3} \approx 3.142 \, \mathrm{rad} = \pi \, \mathrm{rad} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sinusoidal Wave
A sinusoidal wave is a type of wave that oscillates back and forth in a smooth, repetitive manner. It's often visualized as a wave with a curved shape, like the sine function in mathematics. This type of wave is important in physics because it represents many real-world phenomena such as sound waves, light waves, and even water waves. Sinusoidal waves have several key characteristics:

  • Amplitude: This is the height of the wave's peaks. It determines the wave's maximum value.
  • Frequency: The number of complete cycles the wave goes through in one second. Measured in Hertz (Hz).
  • Wavelength: The distance between two consecutive peaks or troughs of the wave.
Understanding sinusoidal waves is critical for analyzing wave-related problems, as they help explain how different waves interact and propagate through various mediums.
Phase Difference
Phase difference refers to the difference in the phase (or position within a cycle) between two points on a wave or between two waves. It's usually measured in radians or degrees.

In the context of a sinusoidal wave, phase difference can tell us how much one wave leads or lags behind another. This concept is crucial when dealing with waves that overlap or interfere with one another. Phase differences impact the resultant amplitude and intensity of the overlapping waves.

In exercises like the original one given, calculating phase differences helps determine physical distances or timings that produce different wave interactions, such as constructive or destructive interference. For example, knowing the phase difference between points on a wave can allow us to find the physical distance between these points, as demonstrated by the formula:
\[\text{Phase difference} = \frac{2\pi}{\lambda} \times \Delta x\]
where \(\Delta x\) represents the distance between points.
Wavelength
Wavelength is a fundamental property of waves, representing the distance over which the wave's shape repeats. It's typically denoted by \(\lambda\), and it plays a critical role in the behavior and classification of waves.

The wavelength can be found using the formula:
\[\lambda = \frac{v}{f}\]
where \(v\) is the speed of the wave and \(f\) is its frequency. In real-world terms, shorter wavelengths mean that the wave peaks are closer together, which often correlates with higher frequencies. Conversely, longer wavelengths suggest a lower frequency.

Understanding wavelength is essential for solving problems such as determining the positions of nodes and antinodes in standing waves or finding distances corresponding to certain phase differences, as we've seen in the original problem.
Angular Frequency
Angular frequency is a concept closely related to the frequency of a wave. It refers to how quickly the phase of the wave changes and is measured in radians per second. Angular frequency, denoted by \(\omega\), can be calculated using the formula:
\[\omega = 2\pi f\]
where \(f\) is the standard frequency in Hertz.

A high angular frequency indicates that the wave cycles rapidly within a short period, meaning quick phase changes and possibly high energy, as seen in waves like gamma rays. On the other hand, a low angular frequency suggests slower oscillations, such as with radio waves.

In the given exercise, knowing the angular frequency helps determine the phase difference over time intervals, which is useful for understanding wave propagation and predicting how waves will behave at different moments in time.

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Most popular questions from this chapter

A sand scorpion can detect the motion of a nearby beetle (its prey) by the waves the motion sends along the sand surface (Fig. 16-30). The waves are of two types: transverse waves traveling at \(v_{t}=50 \mathrm{~m} / \mathrm{s}\) and longitudinal waves traveling at \(v_{l}=150 \mathrm{~m} / \mathrm{s}\). If a sudden motion sends out such waves, a scorpion can tell the distance of the beetle from the difference \(\Delta t\) in the arrival times of the waves at its leg nearest the beetle. If \(\Delta t=4.0 \mathrm{~ms}\) what is the beetle's distance?

A sinusoidal transverse wave traveling in the positive direction of an \(x\) axis has an amplitude of \(2.0 \mathrm{~cm}\), a wavelength of \(10 \mathrm{~cm}\), and a frequency of \(400 \mathrm{~Hz}\). If the wave equation is of the form \(y(x, t)=y_{m} \sin (k x \pm \omega t)\), what are (a) \(y_{m}\), (b) \(k\), (c) \(\omega\), and (d) the correct choice of sign in front of \(\omega ?\) What are (e) the maximum transverse speed of a point on the cord and (f) the speed of the wave?

The function \(y(x, t)=(15.0 \mathrm{~cm}) \cos (\pi x-15 \pi t)\), with \(x\) in meters and \(t\) in seconds, describes a wave on a taut string. What is the transverse speed for a point on the string at an instant when that point has the displacement \(y=+12.0 \mathrm{~cm}\) ?

What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a wire that is \(10.0 \mathrm{~m}\) long, has a mass of \(100 \mathrm{~g}\), and is stretched under a tension of \(250 \mathrm{~N}\) ?

93 A traveling wave on a string is described by $$ y=2.0 \sin \left[2 \pi\left(\frac{t}{0.40}+\frac{x}{80}\right)\right] $$ where \(x\) and \(y\) are in centimeters and \(t\) is in seconds. (a) For \(t=0\), plot \(y\) as a function of \(x\) for \(0 \leq x \leq 160 \mathrm{~cm} .\) (b) Repeat (a) for \(t=0.05 \mathrm{~s}\) and \(t=0.10 \mathrm{~s}\). From your graphs, determine (c) the wave speed and (d) the direction in which the wave is traveling.

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