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One model for a certain planet has a core of radius \(R\) and mass \(M\) surrounded by an outer shell of inner radius \(R\), outer radius \(2 R\), and mass \(4 M\). If \(M=4.1 \times 10^{24} \mathrm{~kg}\) and \(R=6.0 \times 10^{6} \mathrm{~m}\), what is the gravitational acceleration of a particle at points (a) \(R\) and (b) \(3 R\) from the center of the planet?

Short Answer

Expert verified
Gravitational acceleration is 7.6 m/s² at R and 4.2 m/s² at 3R.

Step by step solution

01

Understanding Gravitational Acceleration Formula

Gravitational acceleration at a distance from a mass can be calculated using Newton's law of gravitation: \( g = \frac{G M}{r^2} \), where \( g \) is the gravitational acceleration, \( G \) is the gravitational constant \( (6.674\times10^{-11} \ \text{m}^3\text{kg}^{-1}\text{s}^{-2}) \), \( M \) is the mass causing the gravitational field, and \( r \) is the distance from the center of the mass.
02

Calculate Gravitational Acceleration at R

At radius \( R \), the gravitational acceleration is due only to the core since the shell has no gravitational effect inside it. Use the formula with \( r = R \) and the core mass \( M = 4.1 \times 10^{24} \ \text{kg} \):\[ g = \frac{6.674 \times 10^{-11} \times 4.1 \times 10^{24}}{(6.0 \times 10^{6})^2} \]Working out the calculation gives:\[ g = \frac{2.73694 \times 10^{14}}{3.6 \times 10^{13}} = 7.6 \ \text{m/s}^2 \]
03

Calculate Total Mass within 3R

At radius \( 3R \), the gravitational acceleration is affected by the entire planet (core and shell). The total mass \( M_{total} = M (\text{core}) + 4M (\text{shell}) = 5M \). Calculate it using \( M = 4.1 \times 10^{24} \ \text{kg} \):\[ M_{total} = 5 \times 4.1 \times 10^{24} = 20.5 \times 10^{24} \ \text{kg} \]
04

Calculate Gravitational Acceleration at 3R

Use the gravitational acceleration formula at \( 3R \).\( r = 3 \times 6.0 \times 10^{6} \ \text{m} = 1.8 \times 10^{7} \ \text{m} \).\[ g = \frac{6.674 \times 10^{-11} \times 20.5 \times 10^{24}}{(1.8 \times 10^{7})^2} \]Calculate:\[ g = \frac{1.36857 \times 10^{15}}{3.24 \times 10^{14}} = 4.2 \ \text{m/s}^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Law of Gravitation
Newton's Law of Gravitation is crucial in understanding how planets and other celestial bodies interact. According to this law, any two objects with mass attract each other with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This can be expressed mathematically as:\[F = \frac{G \cdot M_1 \cdot M_2}{r^2}\]Where:
  • \( F \) is the gravitational force between the objects.
  • \( G \) is the gravitational constant, approximately \(6.674 \times 10^{-11} \, \text{m}^3\text{kg}^{-1}\text{s}^{-2}\).
  • \( M_1 \) and \( M_2 \) are the masses of the two objects.
  • \( r \) is the distance between the centers of the two masses.
This concept helps us understand gravitational acceleration, which is the gravitational force per unit mass applied to an object near a celestial body like a planet.
Planetary Mass Distribution
Understanding planetary mass distribution is paramount when calculating gravitational fields, as the mass distribution affects how gravity acts at different points around the planet. In our exercise, the planet consists of a core and an outer shell:
  • The core has a radius \(R\) and a mass \(M\).
  • The outer shell extends from radius \(R\) to \(2R\) and has a mass of \(4M\).
In this setup, the gravitational effects at different radii vary due to the presence or absence of mass. For instance, inside the first radius \(R\), only the core influences the gravitational acceleration because the shell does not exert a gravitational force inside its own radius. Beyond the surface of the core, the total mass affecting gravitational forces changes, accounting for both the core and the shell mass. Recognizing how mass is arranged within a planet allows us to better predict and calculate the gravitational forces experienced at different distances.
Gravitational Field Calculation
Calculating the gravitational field at various points outside and inside a planet requires careful consideration of both the mass and the distance involved. This is done using the formula for gravitational acceleration:\[g = \frac{G \cdot M}{r^2}\]Here:
  • \( g \) is the gravitational acceleration experienced at a distance \( r \).
  • \( M \) is the mass causing the gravitational field (can be the core mass or the total mass depending on the location).
  • \( r \) is the distance from the center of the mass.
In our case:- At distance \( R \), only the core mass \( M \) influences \( g \), as the shell contributes nothing internally.- At distance \( 3R \), the gravitational force comes from the entire planet, which includes both the core and shell, totaling a mass of \( 5M \).These calculations demonstrate how gravitational acceleration changes with both varying mass amounts and distance, providing insights into planetary gravitational fields.

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Most popular questions from this chapter

Three dimensions. Three point particles are fixed in place in an \(x y z\) coordinate system. Particle \(A\), at the origin, has mass \(m_{A}\) Particle \(B\), at \(x y z\) coordinates \((2.00 d, 1.00 d, 2.00 d)\), has mass \(2.00 m_{A}\), and particle \(C\), at coordinates \((-1.00 d, 2.00 d,-3.00 d)\), has mass \(3.00 m_{A} .\) A fourth particle \(D\), with mass \(4.00 m_{A}\), is to be placed near the other particles. In terms of distance \(d\), at what (a) \(x\), (b) \(y\), and (c) \(z\) coordinate should \(D\) be placed so that the net gravitational force on \(A\) from \(B, C\), and \(D\) is zero?

A \(150.0 \mathrm{~kg}\) rocket moving radially outward from Earth has a speed of \(3.70 \mathrm{~km} / \mathrm{s}\) when its engine shuts off \(200 \mathrm{~km}\) above Earth's surface. (a) Assuming negligible air drag acts on the rocket, find the rocket's kinetic energy when the rocket is \(1000 \mathrm{~km}\) above Earth's surface. (b) What maximum height above the surface is reached by the rocket?

The Sun, which is \(2.2 \times 10^{20} \mathrm{~m}\) from the center of the Milky Way galaxy, revolves around that center once every \(2.5 \times 10^{8}\) years. Assuming each star in the Galaxy has a mass equal to the Sun's mass of \(2.0 \times 10^{30} \mathrm{~kg}\), the stars are distributed uniformly in a sphere about the galactic center, and the Sun is at the edge of that sphere, estimate the number of stars in the Galaxy.

Planet Roton, with a mass of \(7.0 \times 10^{24} \mathrm{~kg}\) and a radius of 1600 \(\mathrm{km}\), gravitationally attracts a meteorite that is initially at rest relative to the planet, at a distance great enough to take as infinite. The meteorite falls toward the planet. Assuming the planet is airless, find the speed of the meteorite when it reaches the planet's surface.

In his 1865 science fiction novel From the Earth to the Moon, Jules Verne described how three astronauts are shot to the Moon by means of a huge gun. According to Verne, the aluminum capsule containing the astronauts is accelerated by ignition of nitrocellulose to a speed of \(11 \mathrm{~km} / \mathrm{s}\) along the gun barrel's length of \(220 \mathrm{~m} .\) (a) In \(g\) units, what is the average acceleration of the capsule and astronauts in the gun barrel? (b) Is that acceleration tolerable or deadly to the astronauts? A modern version of such gun-launched spacecraft (although without passengers) has been proposed. In this modern version, called the SHARP (Super High Altitude Research Project) gun, ignition of methane and air shoves a piston along the gun's tube, compressing hydrogen gas that then launches a rocket. During this launch, the rocket moves \(3.5 \mathrm{~km}\) and reaches a speed of \(7.0 \mathrm{~km} / \mathrm{s}\). Once launched, the rocket can be fired to gain additional speed. (c) In \(g\) units, what would be the average acceleration of the rocket within the launcher? (d) How much additional speed is needed (via the rocket engine) if the rocket is to orbit Earth at an altitude of \(700 \mathrm{~km} ?\)

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