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If a \(32.0 \mathrm{~N} \cdot \mathrm{m}\) torque on a wheel causes angular acceleration \(25.0 \mathrm{rad} / \mathrm{s}^{2}\), what is the wheel's rotational inertia?

Short Answer

Expert verified
The wheel's rotational inertia is \(1.28 \, \text{kg} \cdot \text{m}^2 \).

Step by step solution

01

Identify Known Quantities

The problem provides two key values: the torque \( \tau = 32.0 \, \text{N} \cdot \text{m} \) and the angular acceleration \( \alpha = 25.0 \, \text{rad/s}^2 \).
02

Recall the Formula for Rotational Inertia

The rotational inertia \( I \) is related to torque \( \tau \) and angular acceleration \( \alpha \) by the formula: \( \tau = I \cdot \alpha \).
03

Rearrange the Formula to Solve for \( I \)

Rearrange the formula to isolate rotational inertia \( I \): \( I = \frac{\tau}{\alpha} \).
04

Substitute Known Values into the Formula

Using the values from Step 1, substitute into the equation: \( I = \frac{32.0 \, \text{N} \cdot \text{m}}{25.0 \, \text{rad/s}^2} \).
05

Calculate Rotational Inertia

Perform the division: \( I = \frac{32.0}{25.0} = 1.28 \, \text{kg} \cdot \text{m}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Torque
In the world of physics, torque plays a crucial role when dealing with rotational motion. Essentially, torque is a measure of rotational force that causes an object to rotate about an axis.
Think of it like pushing a door open: the farther from the hinge you push (the axis), the easier the door closes. This is because the applied force has a lever arm that magnifies the effect of the force at a greater distance. In equations, torque is represented by the symbol \( \tau \).
  • Torque is calculated as the product of the force applied and the lever arm (distance from the axis of rotation).
  • It's measured in Newton-meters (Nm).
  • Torque formula: \( \tau = r \times F \times \sin(\theta) \), where \( r \) is the lever arm, \( F \) the force, and \( \theta \) the angle between the force and lever arm.
This concept is particularly important in calculating rotational inertia, as torque is directly related to angular acceleration, another key component in rotational dynamics.
What is Angular Acceleration?
Angular acceleration is the rate at which an object's rotational speed changes. Just as linear acceleration measures how quickly an object speeds up or slows down in a straight line, angular acceleration does the same but around a pivot point.
It's important to understand that angular acceleration occurs when there is a change in the rotational velocity of an object.
  • It's measured in radians per second squared \( (\text{rad} / \text{s}^2) \).
  • Angular acceleration can be produced by a torque applied to the object.
  • Formula for angular acceleration \( \alpha \): \( \alpha = \frac{\Delta \omega}{\Delta t} \), where \( \Delta \omega \) is the change in angular velocity and \( \Delta t \) is the time over which this change occurs.
In the context of calculations, angular acceleration allows us to connect torque to rotational inertia, helping us understand how an applied force impacts rotational motion.
Applying Physics Calculations to Solve Rotational Inertia
Calculating rotational inertia involves understanding the relationship between torque, angular acceleration, and inertia itself. Rotational inertia, often symbolized as \( I \), indicates how much an object resists changes in rotational motion. It's akin to mass in linear dynamics.
In solving for rotational inertia, the key formula is: \( \tau = I \cdot \alpha \), where \( \tau \) stands for torque and \( \alpha \) for angular acceleration.
  • First, identify the known quantities from the problem — torque and angular acceleration.
  • Use the formula to solve for \( I \) by rearranging it: \( I = \frac{\tau}{\alpha} \).
  • Substitute the values into the equation and solve for \( I \).
In practice, this means if we know both the torque applied to a wheel and its resulting angular acceleration, we can find out the wheel’s rotational inertia. For example, using \( 32.0 \, \text{N} \cdot \text{m} \) for torque and \( 25.0 \, \text{rad/s}^2 \) for angular acceleration, we find \( I = \frac{32.0}{25.0} = 1.28 \, \text{kg} \cdot \text{m}^2 \). This calculation helps in determining how resistant an object is to change in its rotational state.

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Most popular questions from this chapter

The masses and coordinates of four particles are as follows: \(50 \mathrm{~g}, x=2.0 \mathrm{~cm}, y=2.0 \mathrm{~cm} ; 25 \mathrm{~g}, x=0, y=4.0 \mathrm{~cm} ; 25 \mathrm{~g}\), \(x=-3.0 \mathrm{~cm}, y=-3.0 \mathrm{~cm} ; 30 \mathrm{~g}, x=-2.0 \mathrm{~cm}, y=4.0 \mathrm{~cm} .\) What are the rotational inertias of this collection about the (a) \(x\), (b) \(y\), and (c) \(z\) axes? (d) Suppose that we symbolize the answers to (a) and (b) as \(A\) and \(B\), respectively. Then what is the answer to (c) in terms of \(A\) and \(B ?\)

A disk, initially rotating at \(120 \mathrm{rad} / \mathrm{s}\), is slowed down with a constant angular acceleration of magnitude \(4.0 \mathrm{rad} / \mathrm{s}^{2} .\) (a) How much time does the disk take to stop? (b) Through what angle does the disk rotate during that time?

An automobile crankshaft transfers energy from the engine to the axle at the rate of \(100 \mathrm{hp}(=74.6 \mathrm{~kW})\) when rotating at \(\mathrm{a}\) speed of 1800 rev/min. What torque (in newton-meters) does the crankshaft deliver?

Calculate the rotational inertia of a wheel that has a kinetic energy of \(24400 \mathrm{~J}\) when rotating at 602 rev/min.

Two uniform solid cylinders, each rotating about its central (longitudinal) axis at \(235 \mathrm{rad} / \mathrm{s}\), have the same mass of \(1.25 \mathrm{~kg}\) but differ in radius. What is the rotational kinetic energy of (a) the smaller cylinder, of radius \(0.25 \mathrm{~m}\), and \((\mathrm{b})\) the larger cylinder, of radius \(0.75 \mathrm{~m} ?\)

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