/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Spacing in this book was general... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Problem 4

Spacing in this book was generally done in units of points and picas: 12 points \(=1\) pica, and 6 picas \(=1\) inch. If a figure was misplaced in the page proofs by \(0.80 \mathrm{~cm}\), what was the misplacement in (a) picas and (b) points?

Short Answer

Expert verified
The misplacement is approximately 1.89 picas or 22.68 points.

Step by step solution

01

Convert Centimeters to Inches

First, convert the misplacement from centimeters to inches. Since 1 inch is equal to 2.54 centimeters, we can convert the given misplacement of 0.80 cm into inches using the formula: \[\text{Inches} = \frac{0.80 \text{ cm}}{2.54 \text{ cm/inch}} = 0.315 \text{ inch (approx)}\]
02

Convert Inches to Picas

Once we have the misplacement in inches, we need to convert it to picas. Since 1 inch equals 6 picas, we calculate: \[\text{Picas} = 0.315 \text{ inch} \times 6 \text{ picas/inch} = 1.89 \text{ picas (approx)}\]
03

Convert Picas to Points

Now that we know the misplacement in picas, we can convert it to points. Since 1 pica equals 12 points, we find: \[\text{Points} = 1.89 \text{ picas} \times 12 \text{ points/pica} = 22.68 \text{ points (approx)}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centimeters to Inches
When dealing with measurements, especially in scientific and design fields, you often encounter the need to convert from centimeters to inches. This process is essential because different countries and industries use different measurement systems. The key conversion factor between these two units is:
  • 1 inch = 2.54 centimeters
To convert centimeters to inches, you simply divide the number of centimeters by 2.54. For example, if you have a measurement of 0.80 cm, converting it to inches would look like this:
\[\text{Inches} = \frac{0.80 \text{ cm}}{2.54 \text{ cm/inch}} = 0.315 \text{ inch (approx)}\]This conversion is the first step in translating metric measurements to the imperial system, which can be particularly useful in situations such as page layout planning where the US customary units are preferred.
Picas to Points
In the publishing and design industries, measurements in points and picas are commonplace. These units pertain specifically to typography size and spacing. The relationship between picas and points is simple and worth remembering:
  • 1 pica = 12 points
When converting from picas to points, you multiply the number of picas by 12. For instance, if you have a dimension of 1.89 picas from a layout, converting this to points would be calculated as follows:
\[\text{Points} = 1.89 \text{ picas} \times 12 \text{ points/pica} = 22.68 \text{ points (approx)}\]Points provide a more granular measurement compared to picas, making them ideal for finer adjustments in spacing and type size.
Inches to Picas
Converting inches to picas is another crucial operation when dealing with design layouts and typography. This conversion comes in handy especially in graphic design where picas are often preferred for width and text space measurements. The conversion factor is:
  • 1 inch = 6 picas
To perform the conversion, multiply the number of inches by 6. For example, if you have a 0.315-inch misalignment, converting it to picas would be:\[\text{Picas} = 0.315 \text{ inch} \times 6 \text{ picas/inch} = 1.89 \text{ picas (approx)}\]Picas provide a mid-range measurement that strikes a balance between the broader measurement of inches and the finesse of points. This makes them highly useful in effective page layout design.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The cubit is an ancient unit of length based on the distance between the elbow and the tip of the middle finger of the measurer. Assume that the distance ranged from 43 to \(53 \mathrm{~cm}\), and suppose that ancient drawings indicate that a cylindrical pillar was to have a length of 9 cubits and a diameter of 2 cubits. For the stated range, what are the lower value and the upper value, respectively, for (a) the cylinder's length in meters, (b) the cylinder's length in millimeters, and (c) the cylinder's volume in cubic meters?

Because Earth's rotation is gradually slowing, the length of each day increases: The day at the end of \(1.0\) century is \(1.0 \mathrm{~ms}\) longer than the day at the start of the century. In 20 centuries, what is the total of the daily increases in time?

An astronomical unit \((\mathrm{AU})\) is equal to the average distance from Earth to the Sun, about \(92.9 \times 10^{6} \mathrm{mi}\). A parsec \((\mathrm{pc})\) is the distance at which a length of 1 AU would subtend an angle of exactly 1 second of angle of exactly 1 second of arc (Fig. 1-8). A light-year (ly) is the distance that light, traveling through a vacuum with a speed of \(186000 \mathrm{mi} / \mathrm{s}\), would cover in \(1.0\) year. Express the Earth-Sun distance in (a) parsecs and (b) light-years.

Iron has a density of \(7.87 \mathrm{~g} / \mathrm{cm}^{3}\), and the mass of an iron atom is \(9.27 \times 10^{-26} \mathrm{~kg}\). If the atoms are spherical and tightly packed, (a) what is the volume of an iron atom and (b) what is the distance between the centers of adjacent atoms?

You are to fix dinners for 400 people at a convention of Mexican food fans. Your recipe calls for 2 jalape帽o peppers per serving (one serving per person). However, you have only habanero peppers on hand. The spiciness of peppers is measured in terms of the scoville heat unit (SHU). On average, one jalape帽o pepper has a spiciness of 4000 SHU and one habanero pepper has a spiciness of 300000 SHU. To get the desired spiciness, how many habanero peppers should you substitute for the jalape帽o peppers in the recipe for the 400 dinners?
See all solutions

Recommended explanations on Physics Textbooks

Conservation of Energy and Momentum

Read Explanation

Famous Physicists

Read Explanation

Quantum Physics

Read Explanation

Rotational Dynamics

Read Explanation

Physics of Motion

Read Explanation

Thermodynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.