/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 If the refractive index for a pi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If the refractive index for a piece of optical glass is \(1.5250\), calculate the speed of light in the glass.

Short Answer

Expert verified
The speed of light in the glass is approximately \(1.97 \times 10^8\) m/s.

Step by step solution

01

Understanding Refractive Index

The refractive index, denoted as \( n \), of a medium, is defined as the ratio of the speed of light in a vacuum \( c \) to the speed of light in the medium \( v \). Mathematically, this is expressed as \( n = \frac{c}{v} \). In this problem, \( n = 1.5250 \).
02

Reviewing the Speed of Light in Vacuum

The speed of light in a vacuum is a constant, approximately \( c = 3.00 \times 10^8 \) meters per second.
03

Calculate the Speed of Light in the Glass

Rearrange the formula for refractive index to solve for \( v \): \( v = \frac{c}{n} \). Substitute \( c = 3.00 \times 10^8 m/s \) and \( n = 1.5250 \) into the equation.
04

Performing the Calculation

Compute \( v = \frac{3.00 \times 10^8}{1.5250} \) which yields \( v \). Therefore, \( v \approx 1.97 \times 10^8 \text{ m/s} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed of Light
The speed of light is a fundamental constant of nature. In a vacuum, its speed is precisely measured at approximately \(3.00 \times 10^8\) meters per second (m/s). This incredible speed means that light can travel around the Earth about seven and a half times in a single second. Hence, it serves as a universal speed limit for information and energy throughout the universe.
When we talk about the speed of light, we often consider it in relation to different mediums. This speed can change based on the medium through which light travels, which leads us to the concept of refractive index. Understanding how the speed of light varies is crucial for optics and is foundational for technologies based on light manipulation, such as lenses and fiber optics.
  • The speed of light determines how quickly information can be transmitted.
  • It's a vital constant in Einstein's theory of relativity, impacting time and space perception.
Optical Glass
Optical glass is a type of glass highly engineered for its optical properties, used in lenses, prisms, and other devices to control and manipulate light. For many applications, such as eyeglasses or camera lenses, optical glass is preferred for its clarity and precision.
The refractive index is a critical property of optical glass. This index describes how much the light will bend or refract as it enters the glass from another medium (like air). Since different types of glass have varying refractive indices, they affect how light travels through them in different ways.
  • Optical glass is essential for focusing light accurately in lenses.
  • The refractive index tells us how much the light slows down in the glass.
  • The higher the refractive index, the more the light bends.
This index helps us design lenses that can reduce distortions and enhance clarity, making them indispensable in optics and photonics.
Calculating Speed in Mediums
To calculate the speed of light in various materials, we use the refractive index. The refractive index \( n \) of a material tells us how much the light slows down compared to its speed in a vacuum. The formula used is \( n = \frac{c}{v} \), where \( c \) is the speed of light in a vacuum, and \( v \) is the speed of light in the medium.To find the speed of light in a given medium, rearrange the formula to \( v = \frac{c}{n} \). In the case of optical glass with a refractive index of 1.5250, the speed of light calculates as follows:\[ v = \frac{3.00 \times 10^8 \text{ m/s}}{1.5250} \]This yields approximately \( v = 1.97 \times 10^8 \text{ m/s} \).
  • Always start by knowing the speed of light in a vacuum.
  • Use the refractive index to understand how much slower light travels in a medium.
  • These calculations are critical in designing optical systems efficiently.
Each medium has a unique refractive index, which is determined by its density and composition, influencing how light moves within it.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A straight hollow pipe exactly \(1.250 \mathrm{~m}\) long, with glass plates \(8.50 \mathrm{~mm}\) thick to close the two ends, is thoroughly evacuated. \((a)\) If the glass plates have a refractive index of \(1.5250\), find the overall optical path between the two outer glass surfaces. (b) By how much is the optical path increased if the pipe is filled with water of refractive index 1.33300. Give answers to five significant figures.

A beam of light passes through \(285.60 \mathrm{~cm}\) of water of index \(1.3330\), then through \(15.40 \mathrm{~cm}\) of glass of index \(1.6360\), and finally through \(174.20 \mathrm{~cm}\) of oil of index \(1.3870 .\) Find to three significant figures \((a)\) each of the separate optical paths and \((b)\) the total optical path.

A ray of light in air is incident at an angle of \(54.0^{\circ}\) on the smooth surface of a piece of glass. (a) If the refractive index is 1.5152, find the angle of refraction to four significant figures. (b) Find the angle of refraction graphically.

A ray of light in air enters the center of one face of a prism at an angle making \(55.0^{\circ}\) with the normal. Traveling through the glass, the ray is again refracted into the air beyond. Assume the angle between the two prism faces to be \(60.0^{\circ}\) and the glass to have a refractive index of \(1.650 .\) Find the deviation of the ray \((a)\) at the first surface and (b) the second surface, Find the total deviation (c) by calculation and \((d)\) graphically.

In studying the refraction of light Kepler arrived at a refraction formula $$ \phi=\frac{\phi^{\prime}}{1-k \sec \phi^{\prime}} \quad \text { where } \quad k=\frac{n^{\prime}-1}{n^{\prime}} $$ \(n^{\prime}\) being the relative index of refraction. Calculate the angle of incidence \(\phi\) for a piece of glass for which \(n^{\prime}=1.7320\) and the angle of refraction \(\phi^{\prime}=32.0^{\circ}\) according to (a) Kepler's formula and \((b)\) Snell's law. Note that sec \(\phi^{\prime}=1 /\left(\cos \phi^{\prime}\right)\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.