/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 What are the wavelengths of elec... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What are the wavelengths of electrons with kinetic energies of (a) \(10 \mathrm{eV},(\mathrm{b})\) \(1000 \mathrm{eV}\), and (c) \(10^{7} \mathrm{eV} ?\)

Short Answer

Expert verified
Calculate the de Broglie wavelength for given energies using wavelength formula.

Step by step solution

01

Understand the Problem

We need to calculate the wavelength of electrons given their kinetic energy. The relation between energy and wavelength for particles is expressed using the de Broglie wavelength formula.
02

Use the de Broglie Wavelength Formula

The de Broglie wavelength formula is given by:\[ \lambda = \frac{h}{p} \]where \( \lambda \) is the wavelength, \( h \) is Planck's constant \((6.63 \times 10^{-34} \ \text{Js})\), and \( p \) is the momentum of the electron.
03

Relate Kinetic Energy to Momentum

For non-relativistic speeds, momentum \( p \) is related to kinetic energy \( E_k \) by the formula:\[ p = \sqrt{2mE_k} \]where \( m \) is the electron mass \((9.11 \times 10^{-31} \ \text{kg})\).
04

Calculate Wavelength for 10 eV

For kinetic energy \( E_k = 10 \ \text{eV} \), first convert eV to joules: \( 1 \ \text{eV} = 1.602 \times 10^{-19} \ \text{J} \).So, \( E_k = 10 \times 1.602 \times 10^{-19} \ \text{J}\).Then, calculate the momentum:\[ p = \sqrt{2 \times 9.11 \times 10^{-31} \ \text{kg} \times 10 \times 1.602 \times 10^{-19} \ \text{J}} \]Calculate de Broglie wavelength:\[ \lambda = \frac{6.63 \times 10^{-34} \ \text{Js}}{p} \]
05

Calculate Wavelength for 1000 eV

For kinetic energy \( E_k = 1000 \ \text{eV} \), convert to joules: \( 1000 \times 1.602 \times 10^{-19} \ \text{J} \).Calculate momentum:\[ p = \sqrt{2 \times 9.11 \times 10^{-31} \ \text{kg} \times 1000 \times 1.602 \times 10^{-19} \ \text{J}} \]Calculate de Broglie wavelength:\[ \lambda = \frac{6.63 \times 10^{-34} \ \text{Js}}{p} \]
06

Calculate Wavelength for Relativistic Energies (10^7 eV)

For the kinetic energy \( E_k = 10^{7} \ \text{eV} \), electrons are moving at relativistic speeds, so we must use the relativistic energy-momentum relation:\[ E_k = p^2c^2 / (2m) \]where \( c \) is the speed of light \((3 \times 10^8 \ \text{ms}^{-1})\).We then calculate:\[ \lambda = \frac{h}{\sqrt{2mE_k}} \] accounting for relativistic momentum.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is a crucial concept when dealing with the motion of particles like electrons. It represents the energy that an electron possesses due to its motion. For electrons, this energy can be expressed in electronvolts (eV), which is a convenient unit when dealing with subatomic particles. To relate kinetic energy to the de Broglie wavelength, it's necessary to convert eV into joules, since the standard international system uses joules for energy calculations.
Once converted, kinetic energy can empower you to determine other properties of electrons, such as momentum, which is linked to their wavelength. The formula for linking kinetic energy to momentum is especially vital in calculations at non-relativistic speeds, where its straightforward form simplifies computational steps.
Momentum
Momentum is intertwined with the concept of movement and mass. For electrons, their momentum is tied to their mass and velocity. When considering the de Broglie wavelength, momentum comes into the spotlight because it's a key player in the formula. The momentum of an electron, moving at non-relativistic speeds, can be directly derived from its kinetic energy using the formula \[ p = \sqrt{2mE_k} \]where:
  • \( p \) is momentum
  • \( m \) is the electron's mass
  • \( E_k \) is the kinetic energy
For energies like 10 eV or even 1000 eV, this simple relation allows for easy calculation of de Broglie wavelengths, helping us understand the wave nature of electrons as they zip through space.
Relativistic Speeds
At higher kinetic energies, particularly when you start reaching up around \( 10^7 \ ext{eV} \), electrons begin to approach relativistic speeds. This is because, as the kinetic energy increases, their velocities approach a significant fraction of the speed of light, necessitating a shift from classical mechanics to relativistic physics.
Relativistic speeds mean that the usual formulas for momentum and energy must be adapted to account for their increased mass and speed. Here, you use a formula that incorporates the speed of light \( c \), which is a large and constant value. For electrons at relativistic speeds, the relationship between energy, momentum, and mass becomes more complex, ensuring precise calculations are carried out.
Electron Mass
Electron mass is a fundamental constant, which is crucial when calculating properties like momentum and kinetic energy. It is a tiny value: \( 9.11 \times 10^{-31} \ ext{kg} \). Despite its minuscule size, it's essential in scientific calculations because:
  • It allows us to compute momentum from kinetic energy effectively.
  • It's a constant feature in de Broglie wavelength calculations, providing consistency in equations.
Electron mass remains unchanging regardless of the electron's state, making it a vital anchor point in understanding and calculating how these subatomic particles behave under various energy conditions. This constant value is crucial when dealing with the wave-particle duality of electrons, observed even at varying energy levels.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.