/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 For a vehicle moving at velocity... [FREE SOLUTION] | 91Ó°ÊÓ

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For a vehicle moving at velocity, \(V\), determine the power in \(\mathrm{kW}\) to overcome aerodynamic drag. In general, the drag force, \(F_{d}\), imposed on a vehicle by the surrounding air is given by $$ F_{d}=C_{d} A \frac{1}{2} \rho V^{2} $$ where \(C_{d}\) is a constant for the vehicle called the drag coefficient, \(A\) is the projected frontal area of the vehicle, and \(\rho\) is the air density. For this vehicle, \(C_{d}=0.60, A=10 \mathrm{~m}^{2}, \rho=1.1 \mathrm{~kg} / \mathrm{m}^{2}\), and \(V=100 \mathrm{~km} / \mathrm{h}\).

Short Answer

Expert verified
The power required to overcome the aerodynamic drag for this vehicle moving at a velocity of 100 km/hr is approximately 7.07 kW.

Step by step solution

01

Calculate the drag force

The first step is to calculate the drag force using the given equation. Substitute the given values into the equation: \(F_{d}=C_{d} A \frac{1}{2} \rho V^{2}\). So, it results in \(F_{d}=0.60 \times 10 \times \frac{1}{2} \times 1.1 \times \left(\frac{100 * 1000 }{3600}\right)^{2}\), making sure to convert the velocity from km/hr to m/s by multiplying by 1000 and dividing by 3600.
02

Calculate the force

After substituting the values and doing the calculation, we find that \(F_{d} \approx 254.63\) Newton.
03

Calculate the power

The power is calculated as the product of the drag force and the velocity. So, the power can be calculated as \(P = F_{d} \times V = 254.63 \times \frac{100 * 1000}{3600}\).
04

Calculation of power

After performing the multiplication and calculating the value, we get that \(P \approx 7.07 \times 10^{3}\) W or 7.07 kW.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Drag Coefficient
The drag coefficient, denoted by \(C_d\), is a dimensionless number that describes the aerodynamic resistance of an object moving through a fluid, such as air. It's a measure that combines the shape, texture, and other attributes of an object that affect aerodynamic drag. A lower drag coefficient means the object will encounter less air resistance, and thus, it'll be more aerodynamically efficient. For example, a sleek sports car has a much lower \(C_d\) compared to a large delivery truck because of its design that allows for smoother airflow around its body.

When calculating the drag force using the drag equation \(F_{d} = C_{d} A \frac{1}{2} \rho V^{2}\), it's crucial to understand that the \(C_d\) is significant because it is directly proportional to the drag force; therefore, even small changes in \(C_d\) can lead to significantly larger or smaller drag forces. This has major implications in fuel efficiency and vehicle design.
Projected Frontal Area
The projected frontal area, represented by \(A\) in the drag equation, refers to the area of the object facing the airflow. Think of it as the 'shadow' an object casts when light is shone directly onto its front. This value is important because it directly influences the aerodynamic drag: larger frontal areas will capture more air particles, resulting in higher drag forces.

For an object like a vehicle, reducing the frontal area can be a strategy to enhance fuel efficiency, besides improving the shape (thus lowering \(C_d\)). It's also why sports cars often have a low and wide stance, which gives them a smaller frontal area to cut through air effectively. When calculating the force of drag, one should be cautious to measure the area properly, ensuring that it is projected perpendicularly to the direction of velocity.
Air Density
Air density, symbolized by \(\rho\), is a measurement that conveys how much mass of air is present within a particular volume. It tends to vary with altitude, temperature, and humidity. Denser air means more particles in a given space, so there's a higher probability of these particles colliding with an object as it moves through the air, which in turn increases the drag force.

This concept is pivotal in aerodynamic drag calculations because air density directly affects the drag force — the higher the air density, the higher the aerodynamic drag. When solving physics problems or designing vehicles for different environments, compensating for air density changes is essential. For instance, a car designed for high-altitude cities where air is less dense might perform differently at sea level.
Power Calculation
In physics, power refers to the rate of doing work or, in the case of a vehicle overcoming aerodynamic drag, the rate of converting energy to maintain a certain velocity against resistance. The power calculation for overcoming drag force involves the drag force itself and the vehicle's velocity using the formula \(P = F_{d} \times V\), where \(P\) is power, \(F_{d}\) is drag force, and \(V\) is velocity.

Since power is the product of force and velocity, understanding the implications of each variable is necessary. A higher velocity or drag force would require an increase in power to maintain the same speed. This is why faster-moving vehicles need powerful engines — not only to attain high speeds but also to sustain them against significant drag forces. Hence, understanding how to calculate power is essential for engineers and designers to ensure that vehicles are equipped with the right engines to overcome aerodynamic drag efficiently.

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