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An object has a mass of \(8 \mathrm{~kg}\). Determine (a) its weight at a location where the acceleration of gravity is \(g=9.7 \mathrm{~m} / \mathrm{s}^{2}\), (b) the magnitude of the net force, in \(\mathrm{N}\), required to accelerate the object at \(7 \mathrm{~m} / \mathrm{s}^{2}\).

Short Answer

Expert verified
The weight of the object at the location is \(8 \mathrm{~kg} * 9.7 \mathrm{~m/s}^{2} = 77.6 \mathrm{N}\) and the magnitude of the net force required to accelerate the object at \(7 \mathrm{~m/s}^{2}\) is \(8 \mathrm{~kg} * 7 \mathrm{~m/s}^{2} = 56 \mathrm{N}\).

Step by step solution

01

Find the weight of the object

Weight can be calculated by using the formula \(F=mg\), where \(m\) is the mass of the object and \(g\) is the acceleration due to gravity. Here, \(m = 8 \mathrm{~kg}\) and \(g = 9.7 \mathrm{~m/s}^{2}\). Plug these values into the formula to get the weight in newtons (N).
02

Calculate the net force

The net force required to accelerate an object is given by the formula \(F = ma\), where \(m\) is the mass of the object and \(a\) is the acceleration. In this case, \(m = 8 \mathrm{~kg}\), and \(a = 7 \mathrm{~m/s}^{2}\). Substituting these values into the formula gives the net force in newtons (N).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravity's Effect on Weight
Gravity is the force that pulls objects towards the center of the Earth or any other celestial body. It is a fundamental force in physics that governs how objects move and interact in the universe. When we talk about the weight of an object, we are referring to the force of gravity acting on it. The weight can be calculated using the formula: \( F = mg \), where \( F \) is the force in newtons (N), \( m \) is the mass in kilograms (kg), and \( g \) is the acceleration due to gravity.

In different locations, the value of \( g \) can change slightly. For example, at sea level on Earth, \( g \) is normally approximated as \( 9.81 \, \text{m/s}^2 \), but can be different depending on geographical location or altitude. In our problem, \( g \) is given as \( 9.7 \, \text{m/s}^2 \). Therefore, the weight of an 8 kg object at this gravity level would be \( 8 \, \text{kg} \times 9.7 \, \text{\text{m/s}^2} = 77.6 \, \text{N} \).

This means the force with which the object is pulled towards the Earth is 77.6 newtons.
Understanding Newton's Second Law
Newton's Second Law of Motion is a crucial principle in physics that explains how forces impact motion. It states that the net force acting on an object is equal to the product of its mass and acceleration. Mathematically, it can be expressed as \( F = ma \).

This law helps us to predict how an object will move when different forces act upon it. The more massive an object is, the more force it takes to change its motion. Similarly, to achieve a higher acceleration, a greater force is necessary.

Consider a car and a bicycle. To accelerate the car at the same rate as the bicycle, the car requires more force because it has more mass. Newton's Second Law helps us calculate exactly how much force is needed to achieve the desired motion for any given object.
Calculating Force Using Mass and Acceleration
The calculation of force is straightforward using the formula derived from Newton's Second Law, \( F = ma \). Here, force \( F \) is measured in newtons (N), mass \( m \) in kilograms (kg), and acceleration \( a \) in meters per second squared (m/s²). This provides a clear method to determine the amount of force necessary to move an object or change its speed.

In the provided exercise, we have an object with a mass of 8 kg and we want to find the force required to accelerate it at \( 7 \, \text{m/s}^2 \). By substituting these values into the formula, \( F = 8 \, \text{kg} \times 7 \, \text{m/s}^2 \), we calculate the force as \( 56 \, \text{N} \).

This results mean that a net force of 56 newtons is required to achieve this acceleration for the object.
Acceleration in Physics
Acceleration is a measure of how quickly an object changes its velocity. It is a vector quantity, which means it has both magnitude and direction. In simpler terms, acceleration can occur as speeding up, slowing down, or changing direction.

The standard unit of acceleration is meters per second squared (m/s²). Understanding acceleration is crucial in physics because it relates directly to both force and mass, as shown through Newton's Second Law. The greater the acceleration, the greater the force needed for a given mass.

In problems like ours, knowing the desired acceleration (7 m/s² in this case) lets us calculate the necessary force to achieve it. This not only helps in solving theoretical problems but is also practical in real-world applications, such as designing vehicles or predicting the behavior of moving objects.

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Most popular questions from this chapter

A small car weighing \(1500 \mathrm{lb}\), traveling at \(60 \mathrm{mph}\), decelerates at \(0.70 \mathrm{~g}\) after the brakes are applied. Determine the force applied to slow the car. How far does the car travel in slowing to a stop? How many seconds does it take for the car to stop?

Search online at http://www.osha.gov and print a copy of \(29 \mathrm{CFR} \mathrm{} 1910.212\), General requirements for all machines. With these requirements in mind, identify a machine you have used that had a machine guard to protect the operator or other person in the machine area from hazards. Sketch the machine and label the guarding device, power source, point of operation, and danger zone.

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An object has a mass of \(10 \mathrm{~kg}\) at a location where the acceleration of gravity is \(9.81 \mathrm{~m} / \mathrm{s}^{2}\). Determine its weight in (a) English Engineering units, (b) British Gravitational units, and (c) SI units.

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