/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 An object weighs \(20 \mathrm{lb... [FREE SOLUTION] | 91Ó°ÊÓ

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An object weighs \(20 \mathrm{lb}\) at a location where the acceleration of gravity is \(g=30.5 \mathrm{ft} / \mathrm{s}^{2}\). Determine the magnitude of the net force (lb) required to accelerate the object at \(25 \mathrm{ft} / \mathrm{s}^{2}\).

Short Answer

Expert verified
The net force required to accelerate the object at \(25\, \mathrm{ft/s^2}\) is approximately \(16.39\, \mathrm{lb}\).

Step by step solution

01

Identify and Write Down Given Variables

First, identify all the given variables from the problem. The mass (\(m\)) of the object can be found through the given weight and gravitational acceleration. The weight of an object is given by the formula \(w=mg\), where \(w\) is the weight, \(m\) is the mass, and \(g\) is the gravitational acceleration. Thus, we have \(m=w/g=20\, \mathrm{lb}/30.5\, \mathrm{ft/s^2}\). Also, the acceleration (\(a\)) given in the problem is \(25\, \mathrm{ft/s^2}\).
02

Apply Newton’s Second Law of Motion

Next, according to Newton’s second law (\(F=ma\)), the force (\(F\)) is the product of the mass of the object and the acceleration. Thus, the net force required to accelerate the object is \(F=ma=20\, \mathrm{lb}/30.5\, \mathrm{ft/s^2} \times 25\, \mathrm{ft/s^2}\).
03

Calculate and Finalize the Answer

By performing the multiplication, we can calculate the net force required to accelerate the object, which is approximately \(16.39\, \mathrm{lb}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Net Force Calculation
Understanding the concept of net force is essential for analyzing the effects of different forces acting on an object. Net force is fundamentally the vector sum of all the forces acting on the object. If multiple forces are applied to an object, they must be combined, taking into account their magnitudes and directions, to calculate the net force.

For instance, if you push a book across a table, the net force on the book is a result of the force you apply, friction from the table, and any other forces present, such as air resistance. When all these forces sum up to zero, the book will either remain at rest or continue moving at the same speed and direction (Newton's First Law). However, any non-zero net force will cause the book's speed or direction to change.

In our exercise, the net force calculation involves finding the force required to accelerate an object given its mass and the desired acceleration. The calculation is straightforward since we are focusing on a single force that must counteract both gravity and achieve the desired acceleration.
Gravitational Acceleration
Gravitational acceleration, typically represented by the symbol 'g', is the acceleration due to gravity that an object experiences when it is close to a celestial body like Earth. It's important to note that this acceleration is always directed towards the center of the mass of the celestial body.

The value of 'g' varies slightly depending on where you are on Earth, but the standard average value is about 9.81 meters per second squared (m/s²) or 32.2 feet per second squared (ft/s²). In our exercise, a unique value of gravitational acceleration (\(30.5 \text{ ft/s}^2\)) is given, which is different from the average; this could be an example from a location on a different planet or a hypothetical scenario for educational purposes.

Gravitational acceleration is crucial when we calculate weight, as weight is the force exerted by gravity on an object's mass. Realizing that 'g' can differ provides essential insight into how an object's weight can change according to the gravitational acceleration of the location.
Mass and Weight Relationship
Mass and weight are often confused, but in physics, they are distinct concepts. Mass (m) is a fundamental property of matter and does not change regardless of location. It's a measure of how much matter an object contains. Weight (w), on the other hand, is the force exerted on an object due to gravity and can vary with the acceleration due to gravity.

The relationship between mass and weight is expressed by the formula: \(w = mg\), where 'w' is weight, 'm' is mass, and 'g' is the gravitational acceleration. This equation explains that weight is directly proportional to gravitational acceleration; therefore, the same mass will have a different weight on the Moon compared to Earth due to the Moon's lower 'g'.

In the provided exercise, we used this relationship to determine the mass of the object. Knowing mass is crucial because it allows us to use Newton's Second Law (\(F=ma\)) to find the net force needed for acceleration. Remember, mass remains constant while weight changes with 'g', a common source of confusion for many students when first learning about these concepts.

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Most popular questions from this chapter

A machine for testing and comparing chains and sprockets of various geometries and materials is described in Problem 1.6Db. At issue are (a) whether the chain and sprocket test machine contained proper warnings, (b) whether the test machine was properly guarded, and (c) whether the machine should be allowed to "coast down" to a stop or the sprockets should stop rotating immediately once the machine electrical power is "turned off." Search the OSHA regulations at http://www.osha.gov and specifically review the regulations 29 CFR \(1910.212\), General requirement for all machines, 29 CFR 1910.147, The control of hazardous energy (lockout/tagout), and 29 CFR 1910.145, Specifications for accident prevention signs and tags. Write several paragraphs explaining how each regulation would apply to a chain and sprocket test machine.

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The unexpected or unintentional energization or start-up of machinery, or the release of stored energy, during servicing or maintenance of the machine can result in employee injury or death. Review the regulation 29 CFR \(1910.147\) entitled The control of hazardous energy (lockout/tagout) at http://www.osha.gov and write a paragraph explaining the procedure of lockout/tagout for machines or equipment.

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