/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 The inner surface of a hollow cy... [FREE SOLUTION] | 91Ó°ÊÓ

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The inner surface of a hollow cylinder is subjected to tangential and axial stresses of 40,000 and \(24,000 \mathrm{psi}\), respectively. Determine the maximum shear stress at the inner surface, if the cylinder is pressurized to \(10,000 \mathrm{psi}\).

Short Answer

Expert verified
The maximum shear stress at the inner surface of the cylinder is \( \tau max \) psi.

Step by step solution

01

Defining the Variables

Define the variables present: Axial stress is denoted \( \sigma a \) = 24,000 psi, tangential stress is \( \sigma t \) = 40,000 psi, and the pressure inside the cylinder is \( p \) = 10,000 psi.
02

Applying Pressure Effect

Account for the effect of the internal pressure of the cylinder by adding it to the axial and tangential stresses: \( \sigma a' = \sigma a - p = 24000 psi - 10000 psi = 14000 psi \) and \( \sigma t' = \sigma t - p = 40000 psi - 10000 psi = 30000 psi \) where \( \sigma a' \) and \( \sigma t' \) are the new axial and tangential stresses respectively.
03

Calculate Principal Stresses

Calculate the principal stresses ( \( \sigma 1 \) and \( \sigma 2 \) ) using the following relation: \( \sigma 1 = (\sigma a' + \sigma t')/2 + √{((\sigma a' - \sigma t')/2)^2} \) and \( \sigma 2 = (\sigma a' + \sigma t')/2 - √{((\sigma a' - \sigma t')/2)^2} \)
04

Derive the Maximum Shear Stress

Derive the maximum shear stress by using the formula: \( \tau max = (\sigma 1 - \sigma 2)/2 \)

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Most popular questions from this chapter

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