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Determine how the bending stress at the surface of a shaft subjected to a bending moment \(M\) changes with values for the shaft diameter \(d\).

Short Answer

Expert verified
The bending stress (\(σ\)) at the surface of a shaft subjected to a bending moment (\(M\)) is inversely proportional to the cube of the diameter (\(d\)). Therefore, as the shaft diameter increases, the bending stress decreases and vice versa.

Step by step solution

01

Identify the Variables

In this case, the bending moment \(M\) is constant. The variable that's changing is the shaft diameter \(d\). Therefore, we need to understand how changes in \(d\) affect the bending stress \(σ\).
02

Understand the Relationship Between σ and d

From the formula \(\sigma = \frac{32M}{πd^3}\), we can see that \(σ\) is inversely proportional to \(d^3\). This implies that as \(d\) increases, \(σ\) decreases and vice versa.
03

Explain the Relationship

Since \(σ\) and \(d\) are inversely proportional to each other, it can be said that as the diameter of the shaft increases, there is more area to distribute the bending stress; hence, the overall bending stress decreases. Conversely, if the diameter of the shaft decreases, the area to distribute the stress becomes less, resulting in an increase in the overall bending stress.

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